Tetravalence of carbon & shapes of organic molecules
Carbon's electronic configuration is 1s² 2s² 2p² — four valence electrons sitting in the second shell. To form bonds it hybridises: one 2s and three 2p orbitals collapse into four equivalent sp³ orbitals (methane, 109.5°, tetrahedral); one 2s and two 2p orbitals into three sp² orbitals plus an unhybridised p (ethene, 120°, trigonal planar); one 2s and one 2p into two sp orbitals plus two unhybridised p (ethyne, 180°, linear). The number of σ bonds + lone pairs around carbon determines the hybridisation state. Four → sp³. Three → sp². Two → sp.
The hybridisation also fixes the bond length, bond strength, and acidity. An sp orbital has 50% s-character, an sp² orbital 33%, and an sp³ orbital 25%. More s-character means the orbital sits closer to the nucleus — shorter bonds, stronger bonds, more electronegative carbon, more acidic C–H. That is why ethyne (sp) is more acidic than ethene (sp²) is more acidic than ethane (sp³) — a NEET 2017 question that hinged on this exact rule.
Carbon's four bonds are not a chemical accident — they are the structural premise on which every organic molecule, from methane to DNA, is built.
Why tetravalence matters
A π bond is built from sideways overlap of two parallel p-orbitals. Its electron cloud lies above and below the bonding plane, making the electrons accessible to attacking reagents. This is why multiple bonds are the most reactive centres in a molecule and why double-bond rotation is restricted — twisting one CH₂ relative to the other destroys p-orbital overlap. That restriction is the origin of geometrical (cis-trans) isomerism.
Structural representations
The same molecule can be drawn in several conventions, each with a purpose. The complete structural formula shows every atom and every bond (dash = single, two dashes = double, three dashes = triple). The condensed structural formula compresses bonds and counts identical substituents with subscripts — CH₃CH₂CH₂CH₃ for butane. The bond-line (skeletal) formula draws only the carbon skeleton as a zig-zag line; line junctions and terminals are carbon atoms (hydrogens implied to satisfy tetravalence), and only heteroatoms (O, N, Cl, etc.) are labelled. A bond-line cyclohexane is just a hexagon.
For three-dimensional structures, the wedge–dash convention is used. A solid wedge denotes a bond projecting out of the page toward the observer; a dashed wedge denotes a bond projecting behind the page; normal lines lie in the plane. Three physical models also exist — framework (bonds only), ball-and-stick (atoms + bonds), and space-filling (van der Waals radii). NEET problems set in the bond-line and wedge-dash conventions appear in stereochemistry questions; learning to convert fluently between condensed, skeletal, and 3D forms is non-negotiable.
Classification of organic compounds
Every organic compound belongs to one of two broad families. Acyclic (open-chain or aliphatic) compounds have a straight or branched chain of carbon atoms — alkanes, alkenes, alkynes, and their derivatives. Cyclic compounds contain at least one closed ring. Cyclic compounds split further into homocyclic (carbocyclic), where the ring is made of carbon only, and heterocyclic, where one or more atoms (usually N, O, or S) replace ring carbons. Carbocyclic compounds split again into alicyclic (saturated or non-aromatic — cyclohexane, cyclopentene) and aromatic (benzene and its derivatives, with delocalised π electrons obeying Hückel's 4n+2 rule).
Within these structural families, compounds are further classified by the functional group they carry — an atom or group responsible for the characteristic chemistry of the molecule: –OH (alcohols, suffix -ol), –CHO (aldehydes, -al), >C=O (ketones, -one), –COOH (carboxylic acids, -oic acid), –NH₂ (amines, -amine), –X (haloalkanes, prefix halo-), –NO₂ (nitro, prefix nitro-), and so on. Compounds sharing the same functional group form a homologous series with a common general formula (alkanes CnH2n+2, alkenes CnH2n, alkynes CnH2n−2), where each successive member differs from the previous by a CH₂ unit.
IUPAC nomenclature
The International Union of Pure and Applied Chemistry's 1958 system replaced the chaos of trivial names (formic acid from formica, marsh gas for methane) with a rule-based protocol. Every IUPAC name has three parts — a word root (carbon-count: meth-, eth-, prop-, but-, pent-, hex-, hept-, oct-, non-, dec-), a suffix (saturation: -ane, -ene, -yne; functional group: -ol, -al, -oic acid…), and one or more prefixes (substituents in alphabetical order, with their position locants). The protocol is mechanical — apply the rules in order and the name writes itself.
For molecules with more than one functional group, IUPAC assigns priority — only the highest-priority group becomes the suffix; the rest become prefixes. The simplified priority order (descending): –COOH > –COOR > –SO₃H > –COX > –CONH₂ > –CHO > –CO– (ketone) > –CN > –OH > –NH₂ > –X (halogen) > –NO₂ > –C=C– > –C≡C–. Thus CH₃CH(OH)CH₂CH(Br)COOH is named 2-bromo-4-hydroxypentanoic acid, with COOH as suffix and the rest as prefixes. NEET 2022 set exactly such a multi-substituent IUPAC problem (1-bromo-5-chloro-4-methylhexan-3-ol) and 2017 tested a polyfunctional name (3-keto-2-methylhex-4-enal).
Isomerism
Two compounds with the same molecular formula but different structures are isomers. NCERT and NIOS together recognise two broad families: structural (constitutional) isomerism, where the connectivity differs, and stereoisomerism, where the connectivity is the same but the spatial arrangement differs. Structural isomerism further breaks into four sub-types; stereoisomerism into two main configurational sub-types.
Five tested types of isomerism. Structural: chain, position, functional, metamerism. Stereo: geometrical (cis-trans / E-Z), optical (R/S enantiomers). NEET also tests tautomerism — a special dynamic functional isomerism (keto-enol).
Chain isomerism
Skeleton differs
straight vs branched
n-Butane (CH₃CH₂CH₂CH₃) and isobutane (2-methylpropane) share C₄H₁₀ but differ in carbon-chain skeleton.
Pentane has 3 chain isomers; hexane has 5.Position isomerism
Group location
same chain, different locant
Propan-1-ol (CH₃CH₂CH₂OH) vs propan-2-ol (CH₃CH(OH)CH₃) — the OH sits at a different carbon.
Functional isomerism
Different group
different family of compound
C₂H₆O = ethanol (CH₃CH₂OH) or methoxymethane (CH₃–O–CH₃). C₃H₆O₂ = propanoic acid or methyl ethanoate.
Metamerism
Alkyl split
around a heteroatom
C₄H₁₀O ethers: 1-methoxypropane (CH₃–O–C₃H₇) vs ethoxyethane (C₂H₅–O–C₂H₅) — different alkyl groups on either side of O.
NEET 2021: C₄H₁₀O shows metamerismGeometrical (cis-trans / E-Z)
Same side / opposite
around C=C (restricted rotation)
cis-but-2-ene: both CH₃ on the same side. trans-but-2-ene: on opposite sides. Cis-trans requires each C of C=C to bear a hydrogen.
Optical (R/S enantiomers)
Mirror images
chiral C with 4 different groups
Lactic acid has one chiral C → two non-superimposable mirror images (enantiomers). Rotate plane-polarised light in opposite directions: d/(+) and l/(–).
The R/S system assigns absolute configuration at a chiral carbon. Rank the four substituents by Cahn-Ingold-Prelog priority (1 = highest, 4 = lowest). Orient the molecule so the lowest-priority group points away from you. Trace 1→2→3: clockwise is R (rectus), anticlockwise is S (sinister). The older D/L system (Fischer projections, used for sugars and amino acids) and R/S can both be applied to the same molecule, but they describe different conventions — and the d/l labels for rotation direction are entirely separate from D/L configuration.
Tautomerism is a special dynamic functional isomerism — keto and enol forms of a carbonyl compound interconvert via migration of a proton, e.g. acetone (keto, CH₃COCH₃) ⇌ propen-2-ol (enol, CH₃C(OH)=CH₂). The keto form is usually overwhelmingly more stable. Tautomers are a sub-class of structural isomers, not stereoisomers.
Bond fission — homolytic vs heterolytic
Every organic reaction begins with a bond breaking. There are exactly two ways. In homolytic fission, the two bonding electrons separate equally — each atom keeps one. The result is two neutral species with unpaired electrons: free radicals. In heterolytic fission, one atom takes both electrons; the result is a cation (electron-deficient, often a carbocation) and an anion (electron-rich, often a carbanion). The two pathways generate different intermediates, demand different conditions, and follow different rules.
The charged species produced by heterolysis are classified by what they want. An electrophile ("electron-loving") is electron-deficient — positively charged (H⁺, NO₂⁺, R⁺, Cl⁺) or neutral with an empty orbital (BF₃, AlCl₃). It attacks regions of high electron density. A nucleophile ("nucleus-loving") is electron-rich — negatively charged (OH⁻, CN⁻, Cl⁻, RO⁻) or neutral with a lone pair (H₂O, NH₃, ROH). It attacks regions of low electron density. NEET 2017 asked precisely this definition: an electrophile can be neutral or positively charged and forms a bond by accepting a pair of electrons from a nucleophile — option (1) was the only correct statement.
Electronic effects — inductive, electromeric, resonance, hyperconjugation
Reactions require polarised bonds. The polarisation comes from four well-defined electron-displacement effects. Two are permanent (always present in the ground state): inductive and resonance. Two are temporary (induced only when a reagent attacks): electromeric, and to a partial extent hyperconjugation. Mastering these four effects explains almost every reactivity trend in organic chemistry — acid strength, basicity, electrophilic aromatic substitution patterns, carbocation stability, alkene stability.
Inductive (I) effect
σ-bond polarisation
permanent · transmitted
Polarisation of σ bonds by an electronegative atom, transmitted along the carbon chain. Decreases sharply with distance (negligible past C3).
–I (electron-withdrawing): –NR₃⁺ > –NO₂ > –CN > –F > –Cl > –Br > –I > –OH > –OCH₃ > –C₆H₅ > –H.
+I (electron-releasing): (CH₃)₃C– > (CH₃)₂CH– > CH₃CH₂– > CH₃– > –H.
NEET 2018: –I order –NH₂ < –OR < –FElectromeric (E) effect
π-bond shift
temporary · in presence of reagent
Complete transfer of π-bonded electrons to one atom of a double or triple bond when a reagent attacks. Disappears once the reagent leaves.
+E: electron pair moves away from the attacking atom. –E: moves toward it. Example: C=O + H⁺ → C⁺–O–H.
Resonance (R / M) effect
π-delocalisation
permanent · canonical forms
Several Lewis structures (resonance/canonical structures) differ only in the position of π and lone-pair electrons. The real molecule is the hybrid.
Benzene C–C bonds (139 pm) are intermediate between single (154 pm) and double (130 pm) — direct evidence of resonance. Stabilises carboxylate, enolate, aniline, phenol.
Hyperconjugation
σ–π conjugation
aka "no-bond resonance"
σ (C–H) electrons of an alkyl group delocalise into an adjacent empty p-orbital, π-bond, or radical site. Each α-H contributes.
9 α-H in (CH₃)₃C⁺ → tertiary butyl cation is the most-stabilised by hyperconjugation. Explains tert > sec > primary carbocation order.
NEET 2020: tert vs sec carbocationSteric hindrance is a non-electronic factor that limits reactivity. When bulky groups crowd the reaction site, the attacking reagent simply cannot approach. Esterification rates fall in the order CH₃COOH > RCH₂COOH > R₂CHCOOH > R₃CCOOH — Meyer (1874) observed exactly this, and it explains why pivalic acid (R = CH₃) is far less reactive than acetic acid.
Reactive intermediates — carbocation, carbanion, radical
Heterolytic and homolytic fission generate three short-lived species that drive most organic mechanisms. Carbocations (positively charged carbon, sp² hybridised, planar, six electrons) are stabilised by anything that donates electron density — alkyl groups (+I and hyperconjugation), adjacent lone pairs, and π-systems (resonance). Carbanions (negatively charged carbon, sp³ pyramidal, eight electrons) are stabilised by electron-withdrawing groups (–I and –M). Free radicals (neutral, one unpaired electron, sp² planar) follow the same stability order as carbocations because hyperconjugation stabilises both.
NEET 2022 framed exactly this contrast: in SN2 the product shows inversion of configuration; in SN1 the planar carbocation intermediate produces a 1:1 racemic mixture of enantiomers. A racemic mixture is optically inactive because the equal d and l rotations cancel. The deeper truth is that the stability of the reactive intermediate — carbocation, carbanion, or radical — controls which mechanism the molecule prefers.
Methods of purification
Once a compound has been synthesised, it must be separated from impurities and obtained pure. Five techniques cover almost every laboratory case, each exploiting a different physical property.
Sublimation
Solid → vapour
no liquid phase
Used when a solid converts directly to vapour on heating (camphor, naphthalene, NH₄Cl). The vapour is recondensed on a cool surface — non-sublimable impurities are left behind.
Crystallisation
Solubility difference
hot vs cold solvent
Dissolve in minimum hot solvent, filter hot, cool slowly. The pure compound crystallises (its solubility falls sharply with temperature); soluble impurities stay in the mother liquor.
Distillation
Boiling-point difference
simple · fractional · steam · reduced-pressure
Simple: BP difference > ~30°C. Fractional: closer BPs (petroleum fractions). Steam: volatile, water-immiscible compounds with stable HP (e.g. ortho-nitrophenol — NEET 2017). Reduced-pressure: heat-sensitive compounds (glycerol, sugars).
NEET 2017: o-/p-nitrophenol → steamDifferential extraction
Solubility partition
two immiscible solvents
Organic compound dissolved in water is shaken with an immiscible organic solvent (ether). The compound partitions into the solvent in which it is more soluble; evaporation gives the pure product.
Chromatography
Adsorption / partition
stationary + mobile phase
Adsorption (column, TLC) — components separate by how strongly they bind the silica/alumina. Partition (paper) — separation by relative solubility in the two solvent phases. Essential for closely related mixtures and small samples.
Qualitative analysis — detecting the elements
Before any structure can be assigned, the elements present must be identified. Carbon and hydrogen are detected by heating the compound with CuO in a dry test tube: C → CO₂ (turns limewater milky), H → H₂O (turns anhydrous CuSO₄ blue). For everything else, the compound is first fused with sodium metal to convert covalent N, S, X (Cl, Br, I), and P into ionic form — NaCN, Na₂S, NaX, Na₃PO₄. The fused mass is boiled with distilled water to give Lassaigne's extract (L.E.), on which the element tests are performed.
Test for nitrogen: L.E. + FeSO₄, boil, acidify with H₂SO₄ — Prussian blue colour confirms N (ferriferrocyanide formation, Fe₄[Fe(CN)₆]₃). Test for sulphur: L.E. + sodium nitroprusside → violet colour; or L.E. + lead acetate (after acidification) → black PbS precipitate. Test for halogens: L.E. + HNO₃ + AgNO₃ — white precipitate (soluble in NH₄OH) = Cl; pale-yellow (partly soluble) = Br; yellow (insoluble) = I. If N or S is also present, L.E. is first boiled with concentrated HNO₃ to expel CN⁻ and S²⁻ ions that would otherwise interfere. Test for phosphorus: fuse with Na₂O₂, boil with HNO₃, add ammonium molybdate — canary-yellow precipitate of ammonium phosphomolybdate confirms P.
Quantitative analysis — measuring the elements
Once the elements are identified, their percentage composition is determined by classical combustion/precipitation methods, each named after the chemist who developed it. The percentages are then converted to mole ratios to give the empirical formula, from which (with molar mass) the molecular formula follows.
The Kjeldahl percentage of nitrogen is computed as:
% N = (1.4 × Normality of acid × Volume of acid used to neutralise NH₃) / mass of compound
Kjeldahl's formula — back-titration of liberated ammonia
Oxygen is usually obtained by difference: %O = 100 − (%C + %H + %N + %S + ...). A direct method (Aluise) decomposes the compound in N₂ atmosphere, passes evolved O over hot coke (→ CO) and then I₂O₅ (→ I₂ + CO₂), weighing the products. Modern laboratories use the CHN elemental analyser — a fully automated combustion instrument that estimates C, H, and N simultaneously from 1–3 mg of sample in minutes. It is the descendant of Liebig's combustion train and Dumas's nitrogen collection apparatus.
NEET PYQ Snapshot
Real NEET previous-year questions on this chapter — solve before moving on.
In Lassaigne's extract of an organic compound, both nitrogen and sulphur are present, which gives blood red colour with Fe³⁺ due to the formation of —
Answer: (1) [Fe(SCN)]²⁺Why: When N and S are both present, sodium fusion forms NaSCN. SCN⁻ reacts with Fe³⁺ to give the blood-red ferric thiocyanate complex [Fe(SCN)]²⁺. Prussian blue (option 2) forms only when N alone is present.
The Kjeldahl's method for the estimation of nitrogen cannot be used for which type of compound?
Answer: (2) Pyridine and nitro compoundsWhy: Kjeldahl's method requires the nitrogen to be converted to (NH₄)₂SO₄ during digestion. Nitrogen in ring systems (pyridine), nitro groups, and azo groups does not undergo this conversion — Dumas method is used instead.
The compound which shows metamerism is —
Answer: (1) C₄H₁₀OWhy: Metamerism requires unequal alkyl groups around a heteroatom (O, N, S). C₄H₁₀O ethers give CH₃–O–C₃H₇ and C₂H₅–O–C₂H₅, which are metamers. C₃H₈O cannot — only one ether (methoxymethane analogue) is possible. C₅H₁₂ has no heteroatom at all.
A tertiary butyl carbocation is more stable than a secondary butyl carbocation because of which of the following?
Answer: (3) HyperconjugationWhy: The tert-butyl cation (CH₃)₃C⁺ has 9 α-hydrogens available for hyperconjugation; the sec-butyl cation has only 5. Hyperconjugation (no-bond resonance) delocalises σ-electrons of α-C–H bonds into the empty p-orbital of the cation, stabilising it.
The most suitable method of separation of a 1:1 mixture of ortho- and para-nitrophenols is —
Answer: (1) Steam distillationWhy: o-Nitrophenol has intramolecular H-bonding (chelated) — lower boiling point, volatile in steam. p-Nitrophenol has intermolecular H-bonding — higher boiling point, non-volatile in steam. So steam carries the ortho isomer alone, separating the two.
Expert FAQs
Questions NEET has asked from this chapter, answered straight.
Why is carbon tetravalent?
What is the difference between homolytic and heterolytic fission?
Why is a tertiary carbocation more stable than a secondary one?
What is the difference between an electrophile and a nucleophile?
What is hyperconjugation?
Which method is used to estimate nitrogen in pyridine or nitro compounds?
How are halogens estimated in an organic compound?
What is the difference between cis-trans and E/Z nomenclature?
Go Deeper
Drill into the subtopics that NEET asks most often.