Botany · Molecular Basis of Inheritance

Transcription in Prokaryotes & Eukaryotes

Transcription is the process of copying genetic information from one strand of DNA into RNA — the first arm of the central dogma. It sits between replication and translation in the chapter and is one of the most reliably tested areas in NEET botany, with the prokaryote-versus-eukaryote contrast, RNA polymerase identity and hnRNA processing appearing year after year. This subtopic builds the full mechanism step by step.

NCERT grounding

NCERT Class XII Biology, Chapter 5 (Molecular Basis of Inheritance), Section 5.5 defines the process directly: "The process of copying genetic information from one strand of the DNA into RNA is termed as transcription." The text stresses that the principle of complementarity governs transcription, "except the adenosine complements now forms base pair with uracil instead of thymine." Crucially, unlike replication — where the total DNA of an organism gets duplicated — in transcription only a segment of DNA and only one of the strands is copied into RNA.

That single sentence forces three downstream ideas the syllabus then develops: the need to demarcate the region to be transcribed (the transcription unit), the need to choose one strand (template versus coding strand), and the need for a machine to read it (DNA-dependent RNA polymerase). Sections 5.5.1 to 5.5.3 cover the transcription unit, the relationship between transcription unit and gene, and the contrasting machinery of bacteria and eukaryotes. The NIOS supplement (Chapter 23, Section 23.7.3) reinforces the same sequence of steps and the role of the sigma and rho factors.

"Why both the strands are not copied during transcription has the simple answer. First, if both strands act as a template, they would code for RNA molecule with different sequences... Second, the two RNA molecules if produced simultaneously would be complementary to each other, hence would form a double stranded RNA." — NCERT Class XII Biology, Section 5.5

How transcription works

Transcription is RNA synthesis on a DNA template. The enzyme responsible is DNA-dependent RNA polymerase: it reads a DNA strand and polymerises ribonucleotides into a complementary RNA chain. Like DNA-dependent DNA polymerase in replication, RNA polymerase catalyses polymerisation only in the 5'→3' direction, and it uses nucleoside triphosphates both as substrates and as the energy source for the reaction. It also facilitates the local opening of the DNA helix — a useful NEET fact, since NEET 2020 asked which enzyme opens the DNA helix during transcription, and the answer is RNA polymerase itself, not a separate helicase.

Because RNA polymerase moves only 5'→3', the strand it actually copies must run 3'→5'. That strand is the template strand. The other strand, which is not copied, runs 5'→3' and is displaced during transcription. By NCERT's convention this displaced, non-coding strand is — somewhat counter-intuitively — called the coding strand, because its base sequence is identical to the RNA transcript except that thymine occupies the positions where the RNA has uracil. All reference points of a transcription unit are written with respect to the coding strand.

Transcription unfolds in three steps. The enzyme cannot perform all three on its own — a recurring NEET point. RNA polymerase by itself is capable only of elongation; it associates transiently with accessory factors to initiate and to terminate.

The three steps of transcription

RNA polymerase + accessory factors
  1. Step 1

    Initiation

    RNA polymerase binds the promoter and begins synthesis. In bacteria it associates with the initiation factor sigma (σ).

    Promoter recognised
  2. Step 2

    Elongation

    The polymerase opens the helix and adds ribonucleotides 5'→3', following the rule of complementarity. Only a short stretch of RNA stays bound to the enzyme.

    RNA chain grows
  3. Step 3

    Termination

    On reaching the terminator, the nascent RNA falls off, as does the polymerase. In bacteria the termination factor rho (ρ) assists.

    Transcript released

The base-pairing logic is identical to replication, with one substitution. Where DNA replication would place a thymine opposite adenine, transcription places a uracil. So a template strand reading 3'-ATGC-5' is transcribed into RNA reading 5'-UACG-3'. The coding strand of that same region reads 5'-TACG-3' — note it matches the RNA exactly, with T standing in for U. This is why the fastest way to write an mRNA sequence in an exam is to copy the coding strand and swap every T for a U.

Figure 1 The transcription unit and RNA synthesis 5' 3' CODING STRAND (not copied) 3' 5' TEMPLATE STRAND (3'→5', copied) Promoter (upstream, 5') Structural gene Terminator (downstream, 3') RNA pol RNA transcript 5' RNA polymerase moves 5'→3' along the template; the transcript is complementary, with U in place of T.

Figure 1. A transcription unit has a promoter, a structural gene and a terminator. RNA polymerase binds the promoter, reads the 3'→5' template strand, and builds a complementary RNA in the 5'→3' direction.

The transcription unit and the gene

A transcription unit in DNA is defined primarily by three regions: a promoter, the structural gene and a terminator. The promoter and terminator flank the structural gene. The promoter sits towards the 5' end — described as upstream, with the reference made to the polarity of the coding strand — and provides the binding site for RNA polymerase. It is the presence of the promoter that defines which strand is template and which is coding: NCERT notes that by switching the positions of promoter and terminator, the definitions of coding and template strands would be reversed. The terminator lies towards the 3' end (downstream) and usually defines the end of transcription. Additional regulatory sequences may lie further upstream or downstream of the promoter.

A gene is the functional unit of inheritance. Defining a cistron as a segment of DNA coding for a polypeptide, the structural gene of a transcription unit can be monocistronic — mostly in eukaryotes — or polycistronic — mostly in bacteria. In eukaryotes the monocistronic structural genes have interrupted coding sequences: the genes are split. The expressed sequences that appear in the mature RNA are exons; the intervening sequences that do not appear in the mature RNA are introns. This split-gene arrangement is absent in bacteria and is the structural basis of the eukaryotic processing machinery discussed below.

1 vs 3

RNA polymerases

A single DNA-dependent RNA polymerase transcribes all RNA in bacteria. Eukaryotes use three nuclear RNA polymerases with a clear division of labour — the single most frequently tested fact in this subtopic.

Prokaryotes versus eukaryotes

In bacteria there are three major types of RNA — mRNA, tRNA and rRNA — and all three are needed to synthesise a protein: mRNA provides the template, tRNA brings amino acids and reads the genetic code, and rRNAs play structural and catalytic roles in translation. A single DNA-dependent RNA polymerase catalyses transcription of all three RNA types. This enzyme binds the promoter and initiates transcription, uses nucleoside triphosphates as substrate, polymerises in a template-dependent fashion following complementarity, facilitates opening of the helix, and continues elongation until it reaches the terminator — at which point the nascent RNA falls off along with the polymerase.

The bacterial enzyme is only capable of catalysing elongation. It associates transiently with the initiation factor sigma (σ) and the termination factor rho (ρ); association with these factors alters the specificity of the polymerase to either initiate or terminate. Because the bacterial mRNA needs no processing to become active, and because transcription and translation take place in the same compartment — there is no separation of cytosol and nucleus in bacteria — translation can begin well before the mRNA is fully transcribed. Transcription and translation are therefore said to be coupled in bacteria.

Eukaryotes add two complexities. First, there are at least three RNA polymerases in the nucleus (in addition to the organellar polymerase), with a clear division of labour. Second, the primary transcripts contain both exons and introns and are non-functional; they must be processed before use. These two facts together explain why eukaryotic transcription cannot be coupled to translation.

Transcription — prokaryotes vs eukaryotes

Prokaryotes (bacteria)

1 polymerase

transcribes all RNA

  • Single DNA-dependent RNA polymerase for mRNA, tRNA and rRNA
  • mRNA is often polycistronic — one transcript, several genes
  • No nucleus; transcription and translation in the same compartment
  • mRNA needs no processing; it is functional as made
  • Transcription and translation are coupled
  • σ factor initiates, ρ factor terminates
VS

Eukaryotes

3 polymerases

division of labour

  • RNA Pol I → rRNAs (28S, 18S, 5.8S)
  • RNA Pol II → precursor of mRNA (hnRNA)
  • RNA Pol III → tRNA, 5S rRNA, snRNAs
  • mRNA is monocistronic; genes are split (exons + introns)
  • hnRNA must be processed — splicing, capping, tailing
  • Nucleus separates transcription from translation — no coupling

The division of labour among the eukaryotic polymerases is examined almost every year, so it is worth memorising precisely. RNA polymerase I transcribes the ribosomal RNAs 28S, 18S and 5.8S. RNA polymerase II transcribes the precursor of mRNA — the heterogeneous nuclear RNA (hnRNA). RNA polymerase III is responsible for tRNA, 5S rRNA and the small nuclear RNAs (snRNAs). A clean mnemonic: the numbers go up with the size of the product — Pol I makes the big rRNAs, Pol II makes the message, Pol III makes the small RNAs.

Eukaryotic RNA polymerases — one card each. NEET has asked the role of RNA Pol III in 2021 and again in 2023. Learn all three to avoid confusing the products.

RNA Pol I

rRNA

28S, 18S, 5.8S

Transcribes the large ribosomal RNAs that build the ribosome subunits.

RNA Pol II

hnRNA

precursor of mRNA

Transcribes the heterogeneous nuclear RNA — the unprocessed mRNA precursor.

RNA Pol III

tRNA

tRNA, 5S rRNA, snRNAs

Transcribes the small RNAs — transfer RNA, 5S ribosomal RNA and snRNAs.

Processing of hnRNA into mature mRNA

Because eukaryotic genes are split, the primary transcript made by RNA Pol II — hnRNA — contains both exons and introns and is non-functional as made. Three processing events convert it into a translatable mRNA. Splicing removes the introns and joins the exons in a defined order. Capping adds an unusual nucleotide — methyl guanosine triphosphate — to the 5' end of the hnRNA. Tailing adds 200–300 adenylate residues (the poly-A tail) to the 3' end, in a template-independent manner. It is the fully processed hnRNA, now called mRNA, that is transported out of the nucleus for translation.

hnRNA → mature mRNA

Three processing events, all in the nucleus
  1. Splicing

    Remove introns

    Introns are excised and exons are joined in a defined order, producing a continuous coding sequence.

    Exons joined
  2. Capping

    5' cap added

    An unusual nucleotide, methyl guanosine triphosphate, is added to the 5' end of the hnRNA.

    5' end protected
  3. Tailing

    Poly-A tail added

    200–300 adenylate residues are added at the 3' end in a template-independent manner.

    mRNA exported
Figure 2 Processing of hnRNA into mature mRNA hnRNA (primary transcript) Exon 1 Intron Exon 2 Intron Exon 3 splicing removes introns Mature mRNA cap poly-A tail (200–300 A) 5' methyl-G cap exons joined

Figure 2. Splicing removes introns and joins exons; a methyl guanosine triphosphate cap is added at the 5' end and a 200–300 residue poly-A tail at the 3' end. The fully processed transcript is the mature mRNA exported for translation.

NCERT closes the section by noting the evolutionary significance: split genes probably represent an ancient feature of the genome, and the process of splicing "represents the dominance of RNA-world." For NEET, the exam-relevant takeaway is structural — spliceosomes (the splicing machinery) are absent in bacteria, which is why NEET 2017 could ask in which cells spliceosomes are not found, with bacteria as the answer.

In transcription only a segment of DNA, and only one of its two strands, is copied into RNA.

NCERT — Molecular Basis of Inheritance, §5.5

Worked examples

Worked example 1

The coding strand of a transcription unit reads 5'-ATGCATGCATGC-3'. Write the sequence of the mRNA transcribed from this unit.

The mRNA has the same sequence as the coding strand, with uracil replacing thymine. Replace every T with U: 5'-AUGCAUGCAUGC-3'. (You need not work through the template strand — copying the coding strand and swapping T for U is the fastest route, and is exactly how NEET 2018 Q.172 is solved.)

Worked example 2

A eukaryotic primary transcript made by RNA polymerase II is found to contain sequences absent from the corresponding mature mRNA. Name the transcript, name those absent sequences, and name the process that removes them.

The primary transcript of RNA Pol II is hnRNA (heterogeneous nuclear RNA). The sequences present in hnRNA but absent from mature mRNA are the introns (the expressed sequences that are retained are exons). The process that removes introns and joins the exons in a defined order is splicing. hnRNA also undergoes 5' capping and 3' tailing before export.

Worked example 3

Which single enzyme catalyses initiation, elongation and termination of transcription in prokaryotes, and how does it manage all three steps?

The enzyme is DNA-dependent RNA polymerase. On its own it can catalyse only elongation. It associates transiently with the initiation factor sigma (σ) to begin transcription and with the termination factor rho (ρ) to end it. These factors alter the specificity of the polymerase, allowing the one enzyme to perform all three steps.

Common confusion & NEET traps

Transcription questions punish three specific confusions: the template/coding strand naming, the mismatch between which strand is copied and which polarity it has, and the identity of the three eukaryotic polymerases. The callouts below isolate each.

Sigma factor vs Rho factor

Sigma (σ) factor

Initiation

helps transcription begin

  • Associates with RNA polymerase to start transcription
  • Alters specificity so the enzyme recognises the promoter
  • An initiation factor
VS

Rho (ρ) factor

Termination

helps transcription end

  • Associates with RNA polymerase to terminate transcription
  • Alters specificity so the enzyme releases the transcript
  • A termination factor (asked directly in NEET 2025)

NEET PYQ Snapshot — Transcription in Prokaryotes & Eukaryotes

Real NEET previous-year questions on transcription, RNA polymerases and the transcription unit.

NEET 2025 Q.119

Which factor is important for termination of transcription?

  1. γ (gamma)
  2. α (alpha)
  3. σ (sigma)
  4. ρ (rho)
Answer: (4) ρ (rho)

Why: In prokaryotes RNA polymerase catalyses only elongation. It associates with the initiation factor sigma (σ) to start and the termination factor rho (ρ) to terminate transcription.

NEET 2024 Q.132

A transcription unit in DNA is defined primarily by the three regions in DNA, and these are, with respect to upstream and downstream ends:

  1. Repressor, Operator gene, Structural gene
  2. Structural gene, Transposons, Operator gene
  3. Inducer, Repressor, Structural gene
  4. Promoter, Structural gene, Terminator
Answer: (4) Promoter, Structural gene, Terminator

Why: A transcription unit consists of a promoter (upstream, 5' end), the structural gene, and a terminator (downstream, 3' end of the coding strand).

NEET 2023 Q.117

What is the role of RNA polymerase III in the process of transcription in eukaryotes?

  1. Transcription of only snRNAs
  2. Transcription of rRNA (28S, 18S and 5.8S)
  3. Transcription of tRNA, 5S rRNA and snRNA
  4. Transcription of precursor of mRNA
Answer: (3) tRNA, 5S rRNA and snRNA

Why: RNA Pol I transcribes rRNAs (28S, 18S, 5.8S), RNA Pol II transcribes hnRNA (mRNA precursor), and RNA Pol III transcribes tRNA, 5S rRNA and snRNAs.

NEET 2018 Q.172

AGGTATCGCAT is a sequence from the coding strand of a gene. What will be the corresponding sequence of the transcribed mRNA?

  1. AGGUAUCGCAU
  2. UGGTUTCGCAT
  3. ACCUAUGCGAU
  4. UCCAUAGCGUA
Answer: (1) AGGUAUCGCAU

Why: The mRNA has the same sequence as the coding strand, with uracil in place of thymine. Replacing every T with U in AGGTATCGCAT gives AGGUAUCGCAU.

FAQs — Transcription in Prokaryotes & Eukaryotes

Quick answers to the questions students ask most about transcription.

What is the difference between the template strand and the coding strand?

The template strand has 3'→5' polarity and is the strand actually copied by RNA polymerase. The coding strand has 5'→3' polarity, is not copied, and carries the same base sequence as the RNA transcript except that thymine takes the place of uracil. All reference points of a transcription unit are written with respect to the coding strand.

How many RNA polymerases do prokaryotes and eukaryotes have?

Prokaryotes have a single DNA-dependent RNA polymerase that transcribes all three RNA types — mRNA, tRNA and rRNA. Eukaryotes have three nuclear RNA polymerases: RNA polymerase I transcribes rRNAs (28S, 18S, 5.8S), RNA polymerase II transcribes the precursor of mRNA (hnRNA), and RNA polymerase III transcribes tRNA, 5S rRNA and snRNAs.

Why can transcription and translation be coupled in prokaryotes but not in eukaryotes?

Prokaryotes have no nucleus, so transcription and translation occur in the same compartment, and the mRNA needs no processing. Ribosomes can therefore begin translating an mRNA before its transcription is complete. In eukaryotes the nuclear membrane separates transcription from translation, and hnRNA must be fully processed before export, so the two processes cannot be coupled.

What are the three steps of transcription and which factors assist RNA polymerase?

Transcription proceeds through initiation, elongation and termination. RNA polymerase by itself can only catalyse elongation. In bacteria it associates transiently with the initiation factor sigma (σ) to begin transcription and with the termination factor rho (ρ) to end it; these factors alter the enzyme's specificity.

What processing does hnRNA undergo to become functional mRNA?

The primary transcript hnRNA contains both exons and introns and is non-functional. It undergoes splicing, in which introns are removed and exons are joined in a defined order; 5' capping, in which an unusual nucleotide, methyl guanosine triphosphate, is added to the 5' end; and 3' tailing, in which 200–300 adenylate residues are added to the 3' end in a template-independent manner.

What is a transcription unit made of?

A transcription unit is defined primarily by three regions of DNA: a promoter, the structural gene and a terminator. The promoter lies towards the 5' (upstream) end of the structural gene and provides the binding site for RNA polymerase; the terminator lies towards the 3' (downstream) end and usually defines the end of transcription.