NCERT grounding
NCERT Class 11 Biology, Chapter 18 — Neural Control and Coordination, Section 18.3.1 — anchors this subtopic with three load-bearing statements. First: "Neurons are excitable cells because their membranes are in a polarised state." Second: the resting membrane is far more permeable to K+ than to Na+, and the sodium-potassium pump moves three Na+ out for every two K+ in. Third: when a stimulus opens Na+ channels at a site, the membrane there is depolarised, an action potential is generated, and the wave is then carried forward by local currents along the axon. NIOS Biology Chapter 17 (Section 17.6) reinforces the same mechanism and explicitly states the all-or-none and threshold rules that NEET has tested repeatedly.
"The electrical potential difference across the resting plasma membrane is called as the resting potential. The electrical potential difference across the plasma membrane at the site A is called the action potential, which is in fact termed as a nerve impulse."
NCERT Class 11 Biology · Chapter 18 · Section 18.3.1
Resting potential — the polarised axon
A neuron is not a passive wire. Even when it is not firing, the axonal membrane carries a stored electrical charge — the inside of the axon is roughly seventy millivolts negative relative to the outside, and that voltage difference is the fuel that every nerve impulse spends. NCERT calls this voltage the resting potential and locates its origin in the differential permeability of the axonal membrane to ions and in the active transport carried out by the sodium-potassium pump.
Two compartments separated by the axolemma set the stage. The axoplasm, the fluid inside the axon, contains a high concentration of potassium ions (K+) and large, negatively charged proteins that cannot cross the membrane. The extracellular fluid (ECF) outside the axon contains a high concentration of sodium ions (Na+) and a relatively low K+ concentration. So the two ions are stockpiled on opposite sides — K+ inside, Na+ outside — and each one is poised to flow down its own concentration gradient if the membrane lets it.
The membrane is selective. In the resting state it is far more permeable to K+ than to Na+ (it has a few open K+ "leak" channels), and is effectively impermeable to the trapped axoplasmic proteins. K+ therefore leaks slowly outward down its gradient, leaving an excess of unpaired negative charges (the proteins) behind. The inner face of the membrane becomes net negative; the outer face, where K+ accumulates, becomes net positive. That charge separation is the resting potential.
Resting potential
Inside of the axon is about seventy millivolts negative relative to the outside. The membrane is polarised; the neuron is excitable.
Action-potential peak
During depolarisation the membrane briefly reverses to about thirty millivolts positive inside. This reversal is the nerve impulse.
Left to itself, the slow K+ leak and the slow Na+ inward seep would eventually erase these gradients. The Na+/K+ ATPase pump — an integral membrane protein that hydrolyses one molecule of ATP per cycle — restores them. NCERT states the exact stoichiometry: the pump moves three Na+ ions out of the axon for every two K+ ions it brings in. Because three positive charges leave and only two return per cycle, the pump itself is electrogenic and contributes a small additional negativity to the inside. More importantly, it permanently maintains the steep Na+ gradient (Na+ high outside) and K+ gradient (K+ high inside) on which every impulse depends.
Ionic geography of the resting axon. Three numbers are non-negotiable for NEET: high K+ inside, high Na+ outside, and the 3 Na+ out : 2 K+ in pump ratio. Mis-state any of these and the question is gone.
Inside (axoplasm)
High K+, low Na+.
Trapped negatively charged proteins.
Net charge: negative.
Outside (ECF)
Low K+, high Na+.
No trapped anions.
Net charge: positive.
Na+/K+ pump
3 Na+ out per cycle.
2 K+ in per cycle.
Powered by ATP; electrogenic.
Resting permeability
Membrane is more permeable to K+.
Nearly impermeable to Na+.
Result: inside ~ −70 mV.
This stored voltage is what makes a neuron excitable. The membrane is sitting on a gradient that, if the right channels open, can collapse violently and rapidly in either direction. The job of the resting potential is to hold the gun cocked; the action potential is the trigger pull.
The action potential, step by step
When a stimulus — mechanical, chemical, thermal or electrical — reaches the axonal membrane at a site, the local voltage-gated Na+ channels at that site sense the small initial depolarisation and snap open. The membrane there becomes briefly, freely permeable to Na+. Sodium ions, which were held outside at high concentration, rush inward down both their concentration gradient and the prevailing electrical gradient.
The result is dramatic. Within roughly a millisecond, enough positive charge has poured into the axon at that site to reverse the polarity of the membrane: the inside swings from about minus seventy millivolts up to roughly plus thirty millivolts, and the outside becomes briefly negative relative to the inside. NCERT names this reversed potential difference the action potential and explicitly identifies it as the nerve impulse. The membrane at that site is said to be depolarised.
Figure 1. The action potential plotted against time. A stimulus at the start of the trace depolarises the resting membrane to threshold; voltage-gated Na+ channels open, Na+ rushes in, and the membrane swings rapidly from about minus seventy millivolts to roughly plus thirty millivolts. Na+ channels then close and voltage-gated K+ channels open; K+ exits the axon and the membrane repolarises, briefly overshooting into hyperpolarisation before settling back to the resting potential.
The reversal is short-lived. NCERT writes that the rise in Na+ permeability is "extremely short-lived" and is "quickly followed by a rise in permeability to K+." Two events happen almost simultaneously: the voltage-gated Na+ channels inactivate (they close and become temporarily unresponsive), and a slower set of voltage-gated K+ channels open. K+, now held inside the axon at high concentration and facing an inside that has briefly become positive, rushes outward.
That K+ efflux drains positive charge out of the axon. The membrane potential falls back from plus thirty millivolts toward minus seventy — the process is repolarisation. Because K+ channels close a bit sluggishly, K+ keeps leaving briefly beyond the resting value and the membrane dips slightly below minus seventy millivolts. This undershoot is hyperpolarisation. Finally the K+ channels close, the Na+/K+ pump quietly tidies up the ion accounting, and the membrane is restored to the resting state, ready to fire again.
Four phases at one site of the axon
-
Step 1
Resting
Inside ~ −70 mV. Membrane K+-permeable; Na+ shut out. Pump maintains gradients.
-
Step 2
Depolarisation
Stimulus → voltage-gated Na+ channels open → Na+ rushes in. Inside swings to ~ +30 mV. Polarity reverses; this is the action potential / nerve impulse.
-
Step 3
Repolarisation
Na+ channels inactivate. Voltage-gated K+ channels open → K+ leaves. Inside returns toward −70 mV.
-
Step 4
Hyperpolarisation & reset
K+ channels close slowly → brief undershoot below −70 mV. Pump restores gradients; site re-armed.
The whole event at a single patch of membrane takes roughly one to two milliseconds. Note carefully what the Na+/K+ pump does not do during the action potential: it does not move charge fast enough to depolarise the membrane, and it does not actively pump anything during repolarisation. Depolarisation is driven entirely by passive Na+ inflow through voltage-gated channels, and repolarisation by passive K+ outflow through a different set of voltage-gated channels. The pump is the slow background bookkeeper, not the trigger.
Propagation along the axon
A nerve impulse must travel. The patch of axon at site A has just reversed polarity — outside negative, inside positive — but the patch immediately ahead at site B is still at resting state with outside positive and inside negative. Adjacent regions with opposite polarity cannot coexist. A local current begins to flow: on the inner surface of the membrane, positive charge flows from A toward B; on the outer surface, current flows from B back to A to complete the circuit. NCERT describes this loop explicitly in Section 18.3.1.
Figure 2. Local-circuit propagation of the action potential along an unmyelinated axon. At site A, Na+ has just rushed in and the polarity is reversed (outside negative, inside positive). Site B immediately ahead is still resting. The voltage difference drives a current loop — inner current from A to B, outer current from B back to A — that depolarises B to threshold and fires its own Na+ channels. The wave then advances one patch at a time. Behind A, the membrane is in a refractory state and cannot fire again, so the impulse can only travel forward.
That local current is enough to depolarise site B past its own threshold. Site B's voltage-gated Na+ channels open, Na+ floods in, and a fresh action potential is generated there. Meanwhile site A has already entered repolarisation and is becoming refractory. The wave moves one patch forward; the patch behind it cools off and resets. This is the self-propagating nature of the nerve impulse — every patch regenerates the signal in full as it passes, so the impulse does not decay with distance the way a passive electrical signal would in a copper wire.
Saltatory conduction in myelinated fibres
Conduction in an unmyelinated axon — one patch at a time, every patch — is reliable but slow. The vertebrate nervous system speeds it up dramatically by wrapping most peripheral and central long-distance axons in a fatty insulating sheath called myelin. In the PNS, myelin is laid down by Schwann cells; in the CNS, by oligodendrocytes (NEET 2017 Q.114). Myelin is interrupted at regular intervals by exposed gaps called nodes of Ranvier, where the axolemma is in direct contact with the extracellular fluid.
Myelin is an electrical insulator. Beneath the myelin sheath the axonal membrane cannot exchange ions with the ECF, so the action potential cannot regenerate on the internodes. Voltage-gated Na+ and K+ channels, instead of being spread evenly along the axon, are clustered at the nodes of Ranvier. The action potential, once fired at one node, cannot fire on the internode that follows; the local current spreads passively beneath the myelin to the next node and triggers a fresh action potential there. The impulse therefore appears to jump from node to node — saltatory conduction (from Latin saltare, to leap).
Unmyelinated axon
~ 0.5–2 m/s
continuous, patch-by-patch
- Every patch of membrane regenerates the impulse.
- Na+/K+ channels are spread along the entire axon.
- Common in autonomic and parts of the somatic system.
- Lower energy efficiency — more pump work per metre.
Myelinated axon
~ 10–120 m/s
saltatory, node-to-node
- Action potential jumps between nodes of Ranvier.
- Voltage-gated channels concentrated at nodes only.
- Found in most spinal and cranial nerves.
- Faster and more energy-efficient than continuous conduction.
For NEET, two related facts are worth memorising. Saltatory conduction is faster and more energy-efficient — faster because only the nodes need to spend time on the full action-potential cycle, and more efficient because the Na+/K+ pump has fewer Na+ ions to pump back out per metre of axon. Diseases that strip away myelin (such as multiple sclerosis in humans) slow or block conduction even though the axon itself remains anatomically intact — proof that the myelin sheath is functionally essential, not just a passive covering.
All-or-none law, threshold and refractory period
A nerve impulse does not come in shades. NCERT and NIOS both state the law in the same form: a stimulus must reach a threshold strength to open enough voltage-gated Na+ channels to ignite the regenerative cycle. Below threshold, the small leak of Na+ is mopped up by ongoing K+ outflow and pump activity, and no impulse is generated. At or above threshold, the action potential fires at its full, characteristic amplitude — and increasing the stimulus further does not make the impulse bigger, faster or stronger. This is the all-or-none law.
How then does the nervous system encode a stronger stimulus? Two ways. First, by frequency coding: a stronger stimulus makes the same axon fire more action potentials per second. Second, by population coding: a stronger stimulus recruits additional sensory axons with higher thresholds, so more fibres in the same nerve fire together. Neither mechanism changes the amplitude of any single impulse.
| Property | What it means | NEET-relevant cue |
|---|---|---|
| Threshold | The minimum stimulus strength needed to trigger an action potential (≈ −55 mV across the membrane). | Below threshold = no impulse; at or above threshold = full impulse. |
| All-or-none | An impulse is either generated in full or not at all; its amplitude does not depend on stimulus strength. | Stronger stimulus → higher frequency, not higher amplitude. |
| Absolute refractory period | The interval just after an action potential during which Na+ channels are inactivated and a second impulse cannot be generated at any stimulus strength. | Sets the upper limit on firing frequency; enforces forward propagation. |
| Relative refractory period | The slightly longer interval during which the membrane is hyperpolarised; a stronger-than-normal stimulus can still fire an impulse. | Explains why very intense stimuli can produce abnormally rapid trains of impulses. |
| Conduction velocity | The speed at which the impulse travels along the axon. | Depends on axon diameter and on myelination — not on stimulus strength. |
The refractory period is the time after an action potential during which the axon either cannot, or cannot easily, fire again. In the absolute refractory period, voltage-gated Na+ channels are still inactivated; they will not open no matter how strong the stimulus. In the slightly longer relative refractory period, the K+ channels are still open and the membrane is hyperpolarised, so a larger-than-usual stimulus is needed to push the membrane back up to threshold. The refractory period has two important consequences. It places a ceiling on the maximum firing rate of an axon (typically a few hundred impulses per second). And it ensures one-way propagation: the patch behind a moving impulse is refractory, so the impulse cannot travel backward along the axon.
Worked examples
During the conduction of a nerve impulse along an axon, the role of the sodium-potassium pump is best described as which of the following?
(1) It drives the depolarisation phase by pumping Na+ into the axon.
(2) It drives the repolarisation phase by pumping K+ out of the axon.
(3) It restores the resting ionic gradients in the background, moving 3 Na+ out for every 2 K+ in.
(4) It opens the voltage-gated Na+ channels when threshold is reached.
Answer: (3). The pump is an active transporter that uses ATP to expel 3 Na+ for every 2 K+ it brings in. It does not generate the action potential — depolarisation is driven by passive Na+ inflow through voltage-gated Na+ channels and repolarisation by passive K+ outflow through voltage-gated K+ channels. The pump's job is to maintain the resting gradients on which both fluxes depend.
A nerve fibre is stimulated with a series of pulses, each stronger than the previous one but all above threshold. Which of the following is observed?
(1) The amplitude of each action potential increases with stimulus strength.
(2) The conduction velocity along the axon increases with stimulus strength.
(3) The amplitude of the action potential remains the same; the firing frequency may increase.
(4) The resting potential becomes more negative after each pulse.
Answer: (3). The all-or-none law states that once threshold is crossed, every action potential is generated at its full, fixed amplitude. The nervous system encodes stronger stimuli through the frequency of impulses and the number of fibres recruited, not through bigger spikes. Conduction velocity depends on axon diameter and myelination, not on stimulus strength.
Which of the following correctly pairs the ion movement with the phase of an action potential?
(1) Depolarisation — K+ moves into the axon.
(2) Depolarisation — Na+ moves into the axon.
(3) Repolarisation — Na+ moves out of the axon.
(4) Repolarisation — K+ moves into the axon.
Answer: (2). During depolarisation, voltage-gated Na+ channels open and Na+ — held at high concentration outside — rushes into the axon, swinging the inside from about minus seventy millivolts to roughly plus thirty millivolts. During repolarisation, voltage-gated K+ channels open and K+ — held at high concentration inside — moves out, restoring the inside-negative resting potential.