Botany · Principles of Inheritance and Variation

Incomplete Dominance

Incomplete dominance is the first deviation from Mendel's Law of Dominance that NCERT introduces. When the F1 hybrid resembles neither parent but sits midway between them — as the pink snapdragon does between red and white — the familiar 3:1 F2 ratio collapses into 1:2:1. NEET tests this subtopic almost every cycle, usually as a one-line statement question, so a precise grasp of why the ratio shifts is worth easy marks.

NCERT grounding

The NCERT Class 12 chapter Principles of Inheritance and Variation places incomplete dominance immediately after the Law of Segregation, as Section 4.2.2.1. The text states plainly that when experiments on peas were repeated using other traits in other plants, it was found that sometimes the F1 had a phenotype that did not resemble either of the two parents and was in between the two. The chosen illustration is the inheritance of flower colour in the dog flower — snapdragon, or Antirrhinum sp.

In a cross between a true-breeding red-flowered plant (RR) and a true-breeding white-flowered plant (rr), the F1 (Rr) is pink. When this F1 is self-pollinated, the F2 appears in the ratio 1 (RR) red : 2 (Rr) pink : 1 (rr) white. NCERT notes that the genotype ratios were exactly as expected in any Mendelian monohybrid cross, but the phenotype ratios had changed from the 3:1 dominant : recessive ratio. The NIOS supplement reinforces the same pattern with a second plant, the four o'clock plant Mirabilis jalapa, and records that its F2 phenotypic ratio is 1 red : 2 pink : 1 white.

"What happened was that R was not completely dominant over r and this made it possible to distinguish Rr as pink from RR (red) and rr (white)." — NCERT, Class 12 Biology, Section 4.2.2.1

Why the F1 is intermediate and the F2 is 1:2:1

Incomplete dominance is best defined as a pattern of inheritance in which neither member of an allele pair is fully dominant, so the heterozygote expresses a phenotype that lies between those of the two homozygotes. It is sometimes called partial dominance. The word "incomplete" is doing precise work here: the dominant allele is not absent, it simply fails to mask the recessive allele completely, leaving the heterozygote with a visibly distinct, intermediate appearance.

To set up the standard NEET cross, assign R to the red-flower allele and r to the white-flower allele in snapdragon. A true-breeding red plant is homozygous RR; a true-breeding white plant is homozygous rr. These two are the parental (P) generation. Each parent is homozygous, so each produces only one type of gamete — RR yields R gametes, rr yields r gametes. Every F1 zygote therefore receives one R and one r and is heterozygous Rr. Because R is only partially dominant, the F1 is not red; it is pink.

The intermediate phenotype is the diagnostic feature

The single most important observation in incomplete dominance is that the heterozygote has its own phenotype. In a normal monohybrid cross — for example tall (TT) crossed with dwarf (tt) — the F1 Tt is tall, indistinguishable from the TT parent, because the dominant allele fully masks the recessive one. In snapdragon, the F1 Rr looks like neither RR nor rr. It is a third, identifiable phenotype. This is precisely why incomplete dominance is classed as an exception to the Law of Dominance: NCERT's First Law says that in a dissimilar pair of factors one dominates the other, and here neither does so completely.

Figure 1 Incomplete dominance cross in snapdragon Incomplete dominance — snapdragon flower colour P RR Red × rr White F1 Rr Pink — intermediate phenotype self-pollinate (Rr × Rr) F2 RR Rr Rr rr 1 Red : 2 Pink : 1 White

Figure 1. The standard snapdragon cross. Red RR and white rr parents give a pink Rr F1; self-pollination of the F1 yields an F2 of 1 red : 2 pink : 1 white, with each genotype showing its own phenotype.

Tracking the F2: why segregation still gives 1 : 2 : 1 genotypes

When the pink F1 (Rr) is self-pollinated, each plant produces two kinds of gametes — R and r — in equal proportion of one-half each. This is the Law of Segregation operating exactly as it does in any monohybrid cross; incomplete dominance does not touch it. Random fertilisation of these gametes produces three genotypes. Using the binomial expansion that NCERT applies to the monohybrid cross, (½R + ½r)2 expands to ¼ RR + ½ Rr + ¼ rr. The genotypic ratio is therefore 1 RR : 2 Rr : 1 rr.

Up to this point, snapdragon behaves identically to Mendel's tall–dwarf pea cross. The divergence appears only when genotype is translated into phenotype. In the pea cross, the ¼ TT and the ½ Tt plants are all tall and cannot be told apart externally, so they merge into a single phenotypic class of ¾ tall, against ¼ dwarf — the 3:1 ratio. In snapdragon, the ¼ RR are red, the ½ Rr are pink, and the ¼ rr are white. No two genotypes share a phenotype, so the three classes stay separate: 1 red : 2 pink : 1 white.

Figure 2 Punnett square of the F1 self-cross in incomplete dominance F1 self-cross: Rr × Rr R r R r eggs pollen RR Red Rr Pink Rr Pink rr White Genotypes 1 RR : 2 Rr : 1 rr = Phenotypes 1 Red : 2 Pink : 1 White

Figure 2. The Punnett square for the pink F1 self-cross. Segregation gives genotypes 1 RR : 2 Rr : 1 rr; because each genotype shows its own colour, the phenotypic ratio is identical — 1 red : 2 pink : 1 white.

1:2:1

The defining ratio

In incomplete dominance the F2 phenotypic ratio equals the genotypic ratio, both 1:2:1. This identity happens because every genotype expresses a distinct, visible phenotype — there is no phenotypic merging of heterozygote with homozygous dominant.

This is the conceptual heart of the subtopic, and the line NEET examiners return to repeatedly. The 3:1 ratio of a Mendelian monohybrid cross is fundamentally a phenotypic compression of an underlying 1:2:1 genotypic ratio. Complete dominance hides the heterozygote inside the dominant class. Remove that masking — give the heterozygote its own appearance — and the hidden 1:2:1 simply becomes visible. Incomplete dominance does not create a new ratio; it reveals the genotypic ratio that was always there.

Why R fails to mask r — the dosage explanation

NCERT pairs incomplete dominance with an explanation of what dominance actually means at the level of the gene. Every gene carries information to make a product, often an enzyme. A diploid plant carries two copies of each gene. The functional R allele codes for a working enzyme that catalyses the production of red pigment in the petals. The r allele is a modified form that produces either a non-functional enzyme or no enzyme at all, and so makes no pigment.

A homozygous RR plant carries two functional copies and synthesises a full dose of pigment, giving deep red flowers. A homozygous rr plant carries no functional copy, makes no pigment, and the flowers stay white. The heterozygote Rr carries exactly one functional copy. In many traits a single functional allele still makes enough product to give the full dominant phenotype — that is ordinary complete dominance. But in snapdragon flower colour, one functional copy produces only about half the pigment of two copies, and that half-dose is visibly less intense. The petal therefore looks pink rather than red.

From allele dosage to flower colour

Snapdragon — Antirrhinum
  1. RR

    Two functional copies

    Both alleles make working enzyme; full dose of red pigment produced.

    Red
  2. Rr

    One functional copy

    Only the R allele makes enzyme; roughly half the pigment is produced.

    Pink
  3. rr

    No functional copy

    Neither allele makes working enzyme; no pigment is produced.

    White

This dosage view delivers a useful insight: dominance is not an absolute property of an allele. It depends on whether one functional copy is enough to build the full phenotype. NCERT makes exactly this point with starch synthesis in pea seeds. The gene has alleles B and b; BB seeds make large starch grains and round seeds, bb make small grains and wrinkled seeds. For seed shape, B behaves as a fully dominant allele, since Bb seeds are round. But the starch grains in Bb seeds are of intermediate size, so for the phenotype "starch grain size", the very same B and b alleles show incomplete dominance. The same allele pair can be completely dominant for one trait and incompletely dominant for another, depending on which phenotype you choose to measure.

Incomplete dominance is not blending inheritance

A pink F1 between red and white parents looks superficially like the old, discredited "blending" theory of heredity, in which parental traits supposedly mix permanently like paints. Incomplete dominance decisively refutes blending. If colour truly blended and fused, a self-cross of two pink plants could never recover pure red or pure white — yet the snapdragon F2 produces both parental colours again, cleanly. The alleles R and r remain discrete, particulate units; they segregate intact into gametes and reassemble. Only the visible expression of the heterozygote is intermediate. The hereditary factors themselves never blend.

Complete dominance vs Incomplete dominance — F2 of a monohybrid cross

Complete dominance

3 : 1

F2 phenotypic ratio

  • F1 heterozygote resembles the dominant parent
  • Heterozygote and homozygous dominant share one phenotype
  • Phenotypic ratio (3:1) ≠ genotypic ratio (1:2:1)
  • Example: tall × dwarf pea — F1 all tall
VS

Incomplete dominance

1 : 2 : 1

F2 phenotypic ratio

  • F1 heterozygote is intermediate between both parents
  • Every genotype has its own distinct phenotype
  • Phenotypic ratio (1:2:1) = genotypic ratio (1:2:1)
  • Example: red × white snapdragon — F1 all pink

Two further points sharpen the comparison for the exam. First, incomplete dominance is an exception to the Law of Dominance only. The Law of Segregation holds without exception — NCERT and NIOS both treat it as universal — which is why the F2 genotypes remain 1:2:1. Second, the test cross becomes redundant in incomplete dominance. Mendel needed a test cross because he could not tell a TT plant from a Tt plant by sight. In snapdragon, RR is red and Rr is pink: genotype is read straight off the phenotype. A pink plant is unambiguously heterozygous.

Briefly contrasting with codominance

Codominance is the other classic deviation from the Law of Dominance, and NEET frequently asks the two together, so the distinction must be airtight. In incomplete dominance the heterozygote shows a single blended, intermediate phenotype — pink, which is one new colour, not red-and-white side by side. In codominance the heterozygote expresses both parental phenotypes fully and separately, with no blending and no intermediate. The NCERT example of codominance is the AB blood group: a person with genotype IAIB has red blood cells carrying both A-type and B-type sugars at full strength, because both alleles express completely and simultaneously. There is no "intermediate sugar". The short rule: incomplete dominance blends into one new phenotype, codominance shows both phenotypes at once.

Worked examples

Worked example 1

In Mirabilis jalapa, the four o'clock plant, a red-flowered plant is crossed with a white-flowered plant and all F1 plants are pink. If 240 F2 plants are produced when the F1 is selfed, how many are expected to be pink?

Flower colour here shows incomplete dominance, so the F2 phenotypic ratio is 1 red : 2 pink : 1 white, a total of 4 parts. Pink occupies 2 of those 4 parts, i.e. one-half of the F2. Therefore expected pink plants = 240 × 2/4 = 120. As a check, red = 240 × 1/4 = 60 and white = 240 × 1/4 = 60, and 60 + 120 + 60 = 240.

Worked example 2

A pink snapdragon is crossed with a white snapdragon. State the genotypes of the parents and predict the phenotypic ratio of the offspring.

A pink snapdragon is the heterozygote, genotype Rr; a white snapdragon is homozygous recessive, rr. This is effectively a test cross. The Rr parent gives R and r gametes in equal proportion; the rr parent gives only r gametes. The offspring are therefore ½ Rr and ½ rr. Since Rr is pink and rr is white, the offspring appear as 1 pink : 1 white. No red offspring can arise because no R gamete is available from the white parent.

Worked example 3

A student claims that the pink F1 of a snapdragon cross proves that hereditary factors blend together permanently. Evaluate this claim.

The claim is incorrect. If the alleles truly blended and fused, the original red and white colours could never reappear. But self-pollinating two pink (Rr) plants regenerates pure red (RR) and pure white (rr) plants in the F2. This recovery shows the R and r alleles stay discrete, particulate units that segregate intact during gamete formation. Only the expression of the heterozygote is intermediate; the factors themselves do not blend. Incomplete dominance therefore supports particulate inheritance and refutes blending inheritance.

Worked example 4

In a monohybrid cross, the F2 generation shows a phenotypic ratio of 1:2:1. What does this immediately tell you about dominance, and how does it relate to the genotypic ratio?

A 1:2:1 phenotypic ratio in the F2 of a monohybrid cross indicates incomplete dominance — the heterozygote has a distinct intermediate phenotype rather than resembling the homozygous dominant. Because each of the three genotypes (1 homozygous dominant : 2 heterozygous : 1 homozygous recessive) expresses a different visible phenotype, the phenotypic ratio is identical to the genotypic ratio. This equality of the two ratios is the signature of incomplete dominance and distinguishes it from the 3:1 phenotypic ratio of complete dominance.

Common confusion & NEET traps

Most marks lost on this subtopic come from three predictable confusions: mixing up incomplete dominance with codominance, wrongly claiming the Law of Segregation is violated, and forgetting that the 1:2:1 here is a phenotypic ratio, not merely a genotypic one.

NEET PYQ Snapshot — Incomplete Dominance

Real NEET questions on incomplete dominance, the intermediate phenotype and the 1:2:1 ratio.

NEET 2019

In Antirrhinum (Snapdragon), a red flower was crossed with a white flower and in F1 generation pink flowers were obtained. When pink flowers were selfed, the F2 generation showed white, red and pink flowers. Choose the incorrect statement from the following:

  1. This experiment does not follow the Principle of Dominance.
  2. Pink colour in F1 is due to incomplete dominance.
  3. Ratio of F2 is 1 (Red) : 2 (Pink) : 1 (White).
  4. Law of Segregation does not apply in this experiment.
Answer: (4)

Why: Flower colour in Antirrhinum shows incomplete dominance, an exception to the Law of Dominance — so statements 1, 2 and 3 are correct. The Law of Segregation, however, is universally applicable; the F2 genotypes 1:2:1 prove it operates. Statement 4 is therefore the incorrect statement.

Concept

In a monohybrid cross showing incomplete dominance, the F2 generation displays a phenotypic ratio of:

  1. 3 : 1
  2. 9 : 3 : 3 : 1
  3. 1 : 2 : 1
  4. 2 : 1
Answer: (3)

Why: In incomplete dominance the heterozygote has a distinct intermediate phenotype, so the three genotypes RR, Rr and rr appear as three separate phenotypes. The phenotypic ratio therefore equals the genotypic ratio, 1:2:1, rather than the 3:1 of complete dominance.

Concept

A pink-flowered Mirabilis jalapa plant is crossed with a red-flowered plant. The expected phenotypic ratio of the offspring is:

  1. All pink
  2. 1 red : 1 pink
  3. 1 red : 2 pink : 1 white
  4. 3 red : 1 pink
Answer: (2)

Why: Pink is the heterozygote Rr and red is homozygous RR. The cross Rr × RR gives gametes that combine into ½ RR and ½ Rr — that is, 1 red : 1 pink. No white (rr) offspring is possible because the red parent contributes no r allele.

FAQs — Incomplete Dominance

Quick answers to the questions NEET aspirants ask most about incomplete dominance.

What is incomplete dominance?

Incomplete dominance is a pattern of inheritance in which neither allele of a heterozygote is fully dominant, so the F1 hybrid shows a phenotype intermediate between the two parents. In snapdragon (Antirrhinum), a true-breeding red-flowered plant (RR) crossed with a true-breeding white-flowered plant (rr) gives pink F1 plants (Rr) — a colour that resembles neither parent.

Why is the F2 ratio 1:2:1 instead of 3:1 in incomplete dominance?

Segregation of alleles still produces genotypes in a 1 RR : 2 Rr : 1 rr ratio, exactly as in a normal monohybrid cross. In complete dominance the heterozygote (Rr) looks identical to the homozygous dominant (RR), so RR and Rr merge into one phenotypic class, giving 3:1. In incomplete dominance the heterozygote has its own visible intermediate phenotype, so every genotype is a distinct phenotype and the phenotypic ratio equals the genotypic ratio, 1:2:1.

Which two plants are the standard NCERT examples of incomplete dominance?

The dog flower or snapdragon (Antirrhinum sp.) is the example used in the NCERT Class 12 chapter. The NIOS supplement adds the four o'clock plant, Mirabilis jalapa. In both, a red-flowered parent crossed with a white-flowered parent gives pink-flowered F1 plants and a 1 red : 2 pink : 1 white F2.

Does incomplete dominance violate the Law of Segregation?

No. Incomplete dominance is an exception only to the Law of Dominance, because neither allele dominates the other. The Law of Segregation still applies fully — the Rr heterozygote produces R and r gametes in equal proportion, which is why the F2 genotypes are 1 RR : 2 Rr : 1 rr. The Law of Segregation is universally valid.

How does incomplete dominance differ from codominance?

In incomplete dominance the heterozygote shows a single blended intermediate phenotype, such as pink between red and white. In codominance the heterozygote expresses both parental phenotypes fully and separately, with no blending — as in the AB blood group, where red blood cells carry both A-type and B-type sugars. Incomplete dominance blends; codominance shows both.

How is the intermediate pink phenotype explained at the molecular level?

The R allele codes for a functional enzyme that makes red pigment, while r produces little or no functional enzyme. A homozygous RR plant has two working copies and makes full red pigment; rr has none and stays white. The heterozygote Rr has only one working copy, producing roughly half the pigment, so the flower appears pink. The intermediate phenotype reflects a reduced dosage of functional gene product.