Physics · Wave Optics

Diffraction of Light

Diffraction is the bending of light around the edges of an obstacle or aperture, a behaviour that defines the limits of ray optics. Following NCERT §10.6 and NIOS §22.3, this note builds the single-slit pattern from Huygens' secondary wavelets, derives the minima at $a\sin\theta = n\lambda$, locates the weaker secondary maxima, and fixes the angular width of the central maximum. Single-slit diffraction is a recurring NEET item, and the formula is routinely confused with the YDSE interference condition.

What Diffraction Is

When light passes through a very narrow aperture or falls on an obstacle of very small dimensions, the law of rectilinear propagation is violated. At the edges, light bends into the region of the geometrical shadow. This bending of light around the edges of an obstacle is known as diffraction. If we look closely at the shadow cast by an opaque object, close to the region of geometrical shadow there are alternate dark and bright regions, just as in interference.

Diffraction is a general characteristic exhibited by all types of waves — sound waves, light waves, water waves or matter waves. Since the wavelength of light is much smaller than the dimensions of most obstacles, we do not encounter diffraction effects of light in everyday observation; light therefore appears to travel in straight lines. To observe diffraction the size of the aperture should be of the order of the wavelength of the incident wave, and the screen should be many times farther away than the aperture is wide.

Diffraction is based on the Huygens–Fresnel principle: each unobstructed point of a wavefront acts as a source of secondary wavelets, and the disturbance at any point beyond the aperture is the superposition of all these wavelets, added with the correct phase differences. The phenomenon defines the limit of ray optics — the ability of microscopes and telescopes to distinguish very close objects is set by the wavelength of light.

FeatureGeometrical (ray) opticsDiffraction (wave) regime
Aperture size vs $\lambda$aperture $\gg \lambda$aperture $\sim \lambda$
Edge of shadowsharpfringed, light enters shadow
Treatment of lightstraight-line rayssuperposition of wavelets
Everyday visibilityshadows, imagesCD colours, streaks through eyelids

The Single-Slit Geometry

Replace the double slit of Young's experiment by a single narrow slit of width $a$, illuminated by a monochromatic source. A broad pattern with a central bright region is seen; on both sides there are alternate dark and bright regions, with the intensity becoming weaker away from the centre. Consider a parallel beam falling normally on the slit $LN$ of width $a$, with midpoint $M$. A line through $M$ perpendicular to the slit plane meets the screen at the centre $C$.

To find the intensity at a point $P$ on the screen, the lines joining $P$ to the different points $L, M, N$ of the slit are treated as parallel, making an angle $\theta$ with the normal $MC$. The slit is divided into many small parts, each treated as a secondary source. Because the incoming wavefront is parallel to the slit plane, these sources are all in phase as they leave the slit; the path difference between the wavelets from the two extreme edges, $L$ and $N$, is $a\sin\theta$.

Figure 1 · Single-slit geometry plane wavefront L M N a P C screen θ path diff = a sin θ

Rays from the two edges of the slit reach $P$ with a path difference $a\sin\theta$. Pairing wavelets across the slit decides whether $P$ is dark or bright.

Condition for the Minima

At the centre $C$ ($\theta = 0$) every wavelet travels essentially the same path and they all arrive in phase, building a bright central maximum. Move off-axis to a point where the path difference between the two extreme edges is exactly $\lambda$, i.e. $a\sin\theta = \lambda$. Divide the slit into two halves: a wavelet from the top of the first half and the matching wavelet from the top of the second half are then $\lambda/2$ apart and cancel. Every such pair cancels, so the resultant intensity is zero. This gives the first minimum.

Repeating the pairing argument — dividing the slit into 4, 6, … equal strips — shows that the intensity vanishes whenever the extreme-edge path difference is an integral multiple of $\lambda$. The general condition for the minima (zero intensity) is therefore

$$a\sin\theta = n\lambda, \qquad n = \pm 1, \pm 2, \pm 3, \ldots$$

The integer $n$ counts the order of the minimum. The value $n = 0$ is deliberately excluded — at $\theta = 0$ the whole wavefront adds constructively, giving the principal maximum rather than a dark band.

NEET Trap

Single-slit minima vs YDSE maxima

The single-slit relation $a\sin\theta = n\lambda$ locates the minima of one slit of width $a$. The Young's double-slit relation $d\sin\theta = n\lambda$ locates the maxima for two slits separated by $d$. Same algebraic form, opposite meaning — and a different length symbol. Examiners flip the words "maxima" and "minima," or swap $a$ for $d$, to catch a hurried reader.

Diffraction: $a\sin\theta = n\lambda$ → dark. Interference (YDSE): $d\sin\theta = n\lambda$ → bright. Width $a$ ≠ separation $d$.

Secondary Maxima and Intensity

Between consecutive minima the cancellation is incomplete, leaving weaker bright bands called secondary maxima. Consider a direction where the extreme-edge path difference is $\tfrac{3}{2}\lambda$. Divide the slit into three equal strips: wavelets from two of the strips pair up with a $\lambda/2$ separation and cancel, but the third strip is left over and contributes constructively, producing brightness. Because only about one-third of the wavefront is left uncancelled, this maximum is far weaker than the central one.

The secondary maxima occur approximately where the path difference is a half-integral multiple of $\lambda$,

$$a\sin\theta \approx \left(n + \tfrac{1}{2}\right)\lambda, \qquad n = 1, 2, 3, \ldots$$

and they become weaker and weaker as $n$ increases, since a smaller fraction of the wavefront survives the pairing. The central maximum at $\theta = 0$ is by far the brightest feature of the pattern.

Figure 2 · Intensity distribution sin θ 0 −λ/a +λ/a −2λ/a +2λ/a central maximum width 2λ/a secondary secondary

The central maximum spans from $-\lambda/a$ to $+\lambda/a$; the secondary maxima between the outer minima are markedly fainter and confined to half that angular width.

Build the contrast

The equally spaced bright fringes you must not confuse with this pattern come from Young's Double Slit Experiment.

Width of the Central Maximum

The central maximum is the bright band lying between the first minimum on one side and the first minimum on the other. Those first minima occur at $a\sin\theta = \pm\lambda$, i.e. $\sin\theta = \pm\lambda/a$. The full angular width of the central maximum is the angle between these two minima:

$$\Delta\theta = \frac{2\lambda}{a}$$

Each secondary maximum, by contrast, spans only the gap between two adjacent higher-order minima — an angular spread of about $\lambda/a$. The central maximum is therefore twice as wide as the secondary maxima, and the NIOS text states this directly: the width of the central spot is twice the width of the other spots.

Worked Example

A single slit of width $a = 0.2\ \text{mm}$ is illuminated by light of wavelength $\lambda = 600\ \text{nm}$, with the pattern observed on a screen $D = 1.0\ \text{m}$ away. Find the linear width of the central maximum.

For small angles the half-angular width to the first minimum is $\theta_1 \approx \lambda/a$, so the linear half-width on the screen is $D\lambda/a$. The full width of the central maximum is

$$W = \frac{2D\lambda}{a} = \frac{2 \times 1.0 \times 600\times10^{-9}}{0.2\times10^{-3}} = 6.0\times10^{-3}\ \text{m} = 6.0\ \text{mm}.$$

Halving the slit width to $0.1\ \text{mm}$ would double this to $12\ \text{mm}$ — a narrower slit gives a wider pattern.

NEET Trap

Narrower slit → wider pattern

Because the angular width $2\lambda/a$ is inversely proportional to $a$, shrinking the slit spreads the pattern out, while widening the slit squeezes it toward a sharp shadow. Students often expect a smaller slit to give a smaller pattern; the relationship is the reverse. Likewise, longer wavelength (red) diffracts more than shorter wavelength (blue), so red fringes are wider.

Smaller $a$ ⇒ larger $2\lambda/a$ ⇒ broader central band. Larger $\lambda$ ⇒ broader band.

Diffraction vs Interference

As Feynman noted, there is no sharp physical line between interference and diffraction — interference usually describes the superposition of a few sources, while diffraction describes the superposition from a continuous distribution of secondary sources across a wavefront. For NEET, the operational distinctions in the table below are what get tested. In the actual double-slit experiment, the screen pattern is a superposition of single-slit diffraction from each slit and the double-slit interference between them.

PropertySingle-slit diffractionYDSE interference
Governing lengthslit width $a$slit separation $d$
Standard conditiona sinθ = nλ → minimad sinθ = nλ → maxima
Fringe spacingunequal; fall off from centreequally spaced
Central bandtwice as wide as side bandssame width as other fringes
Relative brightnesscentral maximum dominatesbright fringes nearly equal
Number of sourcescontinuous wavefronttwo discrete coherent sources

Diffraction and Resolution

Diffraction phenomena define the limits of ray optics. Because every aperture spreads light into a pattern of finite angular width, the images of two very close point objects are themselves small diffraction patches that overlap; beyond a point they can no longer be told apart. The limit of the ability of microscopes and telescopes to distinguish very close objects is therefore set by the wavelength of light — a smaller wavelength or a larger aperture improves the resolution.

A related idea is the distance over which a beam stays roughly collimated before diffraction widens it appreciably. A beam passing through an aperture of width $a$ spreads through an angle of order $\lambda/a$, so over a distance $z$ the spread is about $z\lambda/a$. This becomes comparable to $a$ itself at a characteristic length $z \approx a^2/\lambda$, the Fresnel distance, beyond which diffraction dominates and the ray description fails. In interference and diffraction light energy is only redistributed — darker regions lose what brighter regions gain — so energy is conserved throughout.

Quick Recap

Diffraction of Light — at a glance

  • Diffraction is the bending of light around edges; significant when aperture $\sim \lambda$.
  • Single-slit minima: $a\sin\theta = n\lambda$, with $n = \pm1, \pm2, \ldots$ (never $n=0$).
  • Secondary maxima: $a\sin\theta \approx (n+\tfrac{1}{2})\lambda$, growing weaker with $n$.
  • Central maximum angular width $= 2\lambda/a$; it is twice as wide as the side bands.
  • Narrower slit (smaller $a$) or longer $\lambda$ → wider pattern.
  • Do not confuse with YDSE: $d\sin\theta = n\lambda$ gives equally spaced bright fringes.
  • Diffraction sets the resolution limit of telescopes and microscopes.

NEET PYQ Snapshot — Diffraction of Light

Real single-slit diffraction question from the NEET archive, with worked reasoning.

NEET 2016

In a diffraction pattern due to a single slit of width $a$, the first minimum is observed at an angle $30^\circ$ when light of wavelength $5000\ \text{Å}$ is incident on the slit. The first secondary maximum is observed at an angle of:

  1. $\sin^{-1}\!\left(\dfrac{2}{3}\right)$
  2. $\sin^{-1}\!\left(\dfrac{1}{2}\right)$
  3. $\sin^{-1}\!\left(\dfrac{3}{4}\right)$
  4. $\sin^{-1}\!\left(\dfrac{1}{4}\right)$
Answer: (3) $\sin^{-1}(3/4)$

First minimum: $a\sin 30^\circ = \lambda$, so $a \cdot \tfrac{1}{2} = \lambda$, giving $\lambda/a = \tfrac{1}{2}$. First secondary maximum: $a\sin\theta = \tfrac{3}{2}\lambda$, so $\sin\theta = \tfrac{3}{2}\cdot\dfrac{\lambda}{a} = \tfrac{3}{2}\cdot\tfrac{1}{2} = \tfrac{3}{4}$. Hence $\theta = \sin^{-1}(3/4)$.

FAQs — Diffraction of Light

Common single-slit doubts, answered from NCERT and NIOS.

What is the condition for minima in single-slit diffraction?

The minima of zero intensity occur at angles satisfying a sinθ = nλ, where a is the slit width and n = ±1, ±2, ±3, …. The value n = 0 is excluded because the centre is the principal maximum, not a minimum.

Where do the secondary maxima of single-slit diffraction lie?

The secondary maxima lie approximately at a sinθ = (n + ½)λ, that is between consecutive minima, and they become weaker as n increases. The brightest is the central maximum at θ = 0.

What is the angular width of the central maximum?

The central maximum is bounded by the first minima on either side at sinθ ≈ λ/a, so its full angular width is 2λ/a. This makes the central bright band twice as wide as the secondary maxima.

What happens to the diffraction pattern when the slit is made narrower?

A narrower slit means a smaller a, so the angular width 2λ/a increases and the pattern spreads out more. A wider slit makes the bands narrower and the pattern approaches the sharp shadow of geometrical optics.

How is single-slit diffraction different from Young's double-slit interference?

In diffraction, a sinθ = nλ gives the minima of a single slit of width a, the fringes are unequally spaced and the central band is twice as wide. In YDSE, d sinθ = nλ gives the maxima for slit separation d, and the bright fringes are equally spaced and of equal width.

Why does diffraction set a limit on the resolution of optical instruments?

Because every aperture spreads light into a diffraction pattern of finite angular width, the images of two close objects overlap and cannot be separated indefinitely. The ability of microscopes and telescopes to distinguish very close objects is therefore set by the wavelength of light.