Physics · Units and Measurement

Dimensions of Physical Quantities

A dimension is the grammar of a physical quantity. Strip away the numbers and units, and what remains is a small block of exponents — how many factors of mass, length and time the quantity carries. That block is the dimensional formula. Master it, and you can spot a wrong textbook formula in seconds and untangle the NEET examiner's favourite trap: quantities that share dimensions but mean different things. This deep-dive defines what dimensions are, builds the dimensional formula and equation, lays out a 35-row master table grouped by mechanics, thermal, electromagnetic and modern physics, and lists every dimensionless quantity NEET expects you to recognise on sight. Two PYQs (NEET 2022, 2021) anchor the article.

What "dimension" means in physics

NCERT's definition in §1.4 is the cleanest one to memorise: the dimensions of a physical quantity are the powers (or exponents) to which the base quantities are raised to represent that quantity. Square brackets around a quantity — like $[F]$ — signal that we are talking about its dimensions, not its numerical magnitude.

The seven base dimensions correspond one-for-one with the seven SI base quantities established in the SI system of units:

Base quantity Dimension symbol SI base unit
Length[L]metre (m)
Mass[M]kilogram (kg)
Time[T]second (s)
Electric current[A]ampere (A)
Thermodynamic temperature[K]kelvin (K)
Amount of substance[mol]mole (mol)
Luminous intensity[cd]candela (cd)

In mechanics, only $[M]$, $[L]$ and $[T]$ are needed. Volume, the product of three lengths, has dimensions $[L^3]$ — but NCERT explicitly writes its full dimensional signature as $[M^0 L^3 T^0]$, the zero exponents stating that mass and time do not enter. Force is mass times acceleration:

$$[F] = [M] \cdot \frac{[L]}{[T]^2} = [M L T^{-2}]$$

NCERT closes §1.4 with a critical remark: magnitudes are not considered when writing dimensions; it is the quality of the type of physical quantity that enters. Initial velocity, final velocity, average velocity and speed all share the dimensions $[L T^{-1}]$. A dimension does not distinguish a velocity from a speed, or an instantaneous value from an average.

"The nature of a physical quantity is described by its dimensions."

NCERT Class 11 Physics, §1.4

Dimensional formula vs dimensional equation

NCERT §1.5 separates two terms that students often blur together.

A dimensional formula is the expression that shows which base quantities, and to what powers, build a given derived quantity. Examples lifted directly from NCERT §1.5:

  • Volume: $[M^0 L^3 T^0]$
  • Speed or velocity: $[M^0 L T^{-1}]$
  • Acceleration: $[M^0 L T^{-2}]$
  • Mass density: $[M L^{-3} T^0]$

A dimensional equation is what you get when you set the symbol of the physical quantity (in square brackets) equal to its dimensional formula. NCERT writes them as:

$$[V] = [M^0 L^3 T^0], \quad [v] = [M^0 L T^{-1}], \quad [F] = [M L T^{-2}], \quad [\rho] = [M L^{-3} T^0]$$

The compact way to state the distinction: a formula is the right-hand side; an equation is the formula bracketed with the symbol on the left. NEET questions usually ask "what is the dimensional formula of X?" — they want the right-hand side, but the answer is conventionally written as a dimensional equation.

Four more worked formulas

Work along with each derivation. The skill is learning to read the defining equation as a chain of multiplications and divisions of base quantities.

Worked formula · momentum

Find the dimensional formula of linear momentum $p = mv$.

$[p] = [m] \cdot [v] = [M] \cdot [L T^{-1}] = [M L T^{-1}]$. SI unit: kg m s$^{-1}$.

Worked formula · work / energy

Find the dimensional formula of work $W = F \cdot d$.

$[W] = [F] \cdot [d] = [M L T^{-2}] \cdot [L] = [M L^2 T^{-2}]$. SI unit: kg m$^2$ s$^{-2}$, named joule (J). Kinetic energy $\tfrac{1}{2}mv^2$ gives $[M] \cdot [L T^{-1}]^2 = [M L^2 T^{-2}]$ — the same formula, as it must, because work-energy theorem demands it. NCERT Example 1.4 ruled out three "kinetic energy formulas" using exactly this dimensional check.

Worked formula · pressure

Find the dimensional formula of pressure $P = F/A$.

$[P] = [F] / [A] = [M L T^{-2}] / [L^2] = [M L^{-1} T^{-2}]$. SI unit: kg m$^{-1}$ s$^{-2}$, named pascal (Pa).

Worked formula · power

Find the dimensional formula of power $P = W/t$.

$[P] = [W] / [t] = [M L^2 T^{-2}] / [T] = [M L^2 T^{-3}]$. SI unit: kg m$^2$ s$^{-3}$, named watt (W).

Master table — 35 NEET-essential quantities

The list below collects every dimensional formula NEET has tested, or is likely to test, across mechanics, thermal physics, electromagnetism and modern physics. Use it as a reference and as a self-test: cover the right-hand columns, read the defining relation, and reconstruct the formula before peeking.

Quantity Defining relation Dimensional formula SI unit
Mechanics — kinematics & dynamics
Velocity / speed$v = \dfrac{\text{length}}{\text{time}}$$[M^0 L T^{-1}]$m s$^{-1}$
Acceleration$a = \dfrac{v}{t}$$[M^0 L T^{-2}]$m s$^{-2}$
Force$F = ma$$[M L T^{-2}]$N (kg m s$^{-2}$)
Linear momentum$p = mv$$[M L T^{-1}]$kg m s$^{-1}$
Impulse$J = F \cdot t$$[M L T^{-1}]$N s
Work / energy / heat$W = F \cdot d$$[M L^2 T^{-2}]$J
Power$P = W/t$$[M L^2 T^{-3}]$W
Pressure / stress$P = F/A$$[M L^{-1} T^{-2}]$Pa (N m$^{-2}$)
Young's modulus / bulk modulusstress / strain$[M L^{-1} T^{-2}]$Pa
Density$\rho = m/V$$[M L^{-3} T^0]$kg m$^{-3}$
Frequency$\nu = 1/T$$[M^0 L^0 T^{-1}]$Hz (s$^{-1}$)
Angular velocity / angular frequency$\omega = \theta/t$$[M^0 L^0 T^{-1}]$rad s$^{-1}$
Angular momentum$L = I\omega = mvr$$[M L^2 T^{-1}]$kg m$^2$ s$^{-1}$
Torque / moment of force$\tau = r \times F$$[M L^2 T^{-2}]$N m
Moment of inertia$I = mr^2$$[M L^2 T^0]$kg m$^2$
Surface tension$\gamma = F/L$$[M L^0 T^{-2}]$N m$^{-1}$
Coefficient of viscosity$F = \eta A \,dv/dx$$[M L^{-1} T^{-1}]$Pa s
Universal gravitational constant $G$$F = G m_1 m_2 / r^2$$[M^{-1} L^3 T^{-2}]$N m$^2$ kg$^{-2}$
Gravitational potential$V_g = U/m$$[M^0 L^2 T^{-2}]$J kg$^{-1}$
Spring constant$F = kx$$[M L^0 T^{-2}]$N m$^{-1}$
Thermal physics
Temperature$[K]$K
Specific heat capacity$c = Q/(m \Delta T)$$[M^0 L^2 T^{-2} K^{-1}]$J kg$^{-1}$ K$^{-1}$
Latent heat$L = Q/m$$[M^0 L^2 T^{-2}]$J kg$^{-1}$
Boltzmann constant $k_B$$E = k_B T$$[M L^2 T^{-2} K^{-1}]$J K$^{-1}$
Universal gas constant $R$$PV = nRT$$[M L^2 T^{-2} K^{-1} \text{mol}^{-1}]$J mol$^{-1}$ K$^{-1}$
Coefficient of thermal conductivity$Q/t = -kA \,dT/dx$$[M L T^{-3} K^{-1}]$W m$^{-1}$ K$^{-1}$
Stefan–Boltzmann constant $\sigma$$E = \sigma T^4$$[M L^0 T^{-3} K^{-4}]$W m$^{-2}$ K$^{-4}$
Electricity & magnetism
Electric current$[A]$A
Electric charge$q = It$$[M^0 L^0 T A]$C (A s)
Electric potential / EMF$V = W/q$$[M L^2 T^{-3} A^{-1}]$V (J C$^{-1}$)
Electric field$E = F/q$$[M L T^{-3} A^{-1}]$V m$^{-1}$
Electrical resistance$R = V/I$$[M L^2 T^{-3} A^{-2}]$$\Omega$ (V A$^{-1}$)
Capacitance$C = q/V$$[M^{-1} L^{-2} T^4 A^2]$F (C V$^{-1}$)
Permittivity of free space $\varepsilon_0$$F = q_1 q_2 / (4\pi\varepsilon_0 r^2)$$[M^{-1} L^{-3} T^4 A^2]$C$^2$ N$^{-1}$ m$^{-2}$
Permeability of free space $\mu_0$$F/L = \mu_0 I_1 I_2 / (2\pi r)$$[M L T^{-2} A^{-2}]$T m A$^{-1}$ (or H m$^{-1}$)
Magnetic field $B$$F = qvB$$[M L^0 T^{-2} A^{-1}]$T (tesla)
Magnetic flux $\Phi_B$$\Phi_B = B \cdot A$$[M L^2 T^{-2} A^{-1}]$Wb (V s)
Self / mutual inductance$\varepsilon = -L \,dI/dt$$[M L^2 T^{-2} A^{-2}]$H (henry)
Modern physics & optics
Planck constant $h$$E = h\nu$$[M L^2 T^{-1}]$J s
Refractive index $n$$n = c/v$$[M^0 L^0 T^0]$dimensionless
Wavelength$[M^0 L T^0]$m
Wave number $\bar{\nu}$$\bar{\nu} = 1/\lambda$$[M^0 L^{-1} T^0]$m$^{-1}$

Three observations to encode now. Every "rate" carries one extra $T^{-1}$ over its parent — angular velocity is angle per time, power is energy per time, current is charge per time. Every "per area" or "per volume" inherits negative powers of $L$ — pressure $L^{-1}$, density $L^{-3}$. Electromagnetic quantities are the ones involving $[A]$ — permeability, capacitance, flux, inductance.

Dimensionless quantities — units without dimensions

A quantity is dimensionless if every base exponent in its dimensional formula is zero — written $[M^0 L^0 T^0]$. NCERT §1.6.1 explains why these appear: they are always ratios of two quantities of the same kind, so the units cancel. Memorise the canonical list.

Dimensionless quantity Definition / ratio Unit (if any)
Plane angle $\theta$arc length / radiusradian (rad)
Solid angle $\Omega$area / radius$^2$steradian (sr)
Strainchange in length / original length
Refractive index $n$speed of light in vacuum / in medium
Relative density (specific gravity)density of substance / density of water
Dielectric constant $\kappa$ (relative permittivity $\varepsilon_r$)$\varepsilon / \varepsilon_0$
Relative permeability $\mu_r$$\mu / \mu_0$
Coefficient of friction $\mu$friction force / normal force
Mechanical advantage / efficiencyratio of forces or energies
Poisson's ratio $\sigma$lateral strain / longitudinal strain
Fine-structure constant $\alpha$$e^2/(4\pi\varepsilon_0 \hbar c) \approx 1/137$
Arguments of $\sin$, $\cos$, $\log$, $e^x$must be pure numbers

Same dimensions, different physical meaning

Dimensional formulae are coarse — they record the type of base quantities involved, not the structure built from them. So several physically distinct quantities can share an identical formula. NEET examiners love testing this; NCERT explicitly warns in §1.6.2 that "It does not distinguish between the physical quantities having same dimensions." The four most-tested clashes are:

Common dimensional formula Quantities that share it Why they differ physically
$[M L^2 T^{-2}]$ Work, kinetic energy, potential energy, heat, torque Energy is a scalar describing transfer; torque is a vector cross-product $\mathbf{r} \times \mathbf{F}$. Joule is the unit of energy; torque uses N m (never J).
$[M L^{-1} T^{-2}]$ Pressure, stress, Young's / bulk / shear modulus, energy density Stress is force per area; modulus is stress over (dimensionless) strain — same dimensions. Energy density is energy per volume, which also collapses to this formula.
$[M L^2 T^{-1}]$ Angular momentum, Planck constant $L = I\omega$ and $h$ via $E = h\nu$. The shared dimensions are why Bohr's quantisation rule $L = n\hbar$ works — but angular momentum is a vector, $h$ a scalar constant.
$[M^0 L^0 T^{-1}]$ Frequency, angular frequency, decay constant, velocity gradient $\nu = 1/T$ (Hz); $\omega = 2\pi\nu$ (rad s$^{-1}$); decay constant $\lambda$ in $e^{-\lambda t}$ (s$^{-1}$). Same $[T^{-1}]$, different physical context.

How to find the dimensional formula of an unfamiliar quantity

You will not always be given a memorised formula. The reliable procedure: start from a defining equation, isolate the unknown, and read off dimensions from the rest. Four worked examples below cover the four kinds of derivation NEET tests.

Worked derivation · surface tension

From $F = \gamma L$, find $[\gamma]$.

Surface tension $\gamma$ is force per unit length along the boundary of a liquid surface. Rearranging, $\gamma = F/L$. Substituting dimensions:

$$[\gamma] = \frac{[F]}{[L]} = \frac{[M L T^{-2}]}{[L]} = [M L^0 T^{-2}] = [M T^{-2}]$$

SI unit: N m$^{-1}$. The $L^0$ is conventional — you can write either $[M T^{-2}]$ or $[M L^0 T^{-2}]$, the latter signals deliberately that length cancelled.

Worked derivation · gravitational constant $G$

From Newton's law $F = G m_1 m_2 / r^2$, find $[G]$ (NIOS Terminal Q.4).

$G = F r^2 / (m_1 m_2)$, so:

$$[G] = \frac{[M L T^{-2}] \cdot [L^2]}{[M]^2} = [M^{-1} L^3 T^{-2}]$$

SI unit: N m$^2$ kg$^{-2}$.

Worked derivation · Planck constant $h$

From $E = h\nu$, find $[h]$.

$h = E/\nu$, so $[h] = [M L^2 T^{-2}] / [T^{-1}] = [M L^2 T^{-1}]$. SI unit: J s — same dimensional formula as angular momentum.

Worked derivation · coefficient of viscosity $\eta$

From $F = \eta A \,(dv/dx)$, find $[\eta]$.

Velocity gradient $dv/dx$ has dimensions $[L T^{-1}] / [L] = [T^{-1}]$. So:

$$[\eta] = \frac{[M L T^{-2}]}{[L^2] \cdot [T^{-1}]} = [M L^{-1} T^{-1}]$$

SI unit: Pa s. The CGS unit is the poise = g cm$^{-1}$ s$^{-1}$.

The same procedure handles every NEET-bank quantity: write the defining equation, isolate the unknown, substitute dimensions for every symbol on the right-hand side. The full set of dimensional-analysis applications — checking equations for homogeneity, deriving the form of an unknown relation, and converting between unit systems — is treated in the sibling article.

Quick recap

What this subtopic locked in

  • Seven base dimensions. $[M], [L], [T], [A], [K], [\text{mol}], [\text{cd}]$. Mechanics needs only the first three.
  • Formula vs equation. Dimensional formula is the right-hand side; dimensional equation sets it equal to $[X]$.
  • 35-row master table. Mechanics, thermal, electromagnetism and modern physics — every dimensional formula NEET expects, grouped for revision.
  • Dimensionless quantities. Plane angle, solid angle, strain, refractive index, relative density, dielectric constant, $\mu_r$, friction coefficient, Poisson's ratio — and arguments of $\sin$, $\log$, $\exp$.
  • Same dimensions, different physics. Work/torque, pressure/stress/Young's modulus, angular momentum/Planck constant, frequency/angular frequency/decay constant.
  • Derivation procedure. Start from the defining equation, isolate the unknown, substitute dimensions for every symbol on the right.

NEET PYQ Snapshot — Dimensions

Three PYQs that ask directly for a dimensional formula or test recognition of a specific combination. Solutions reference the master table above.

NEET 2022

The dimensions $[M L T^{-2} A^{-2}]$ belong to the

  1. Self inductance
  2. Magnetic permeability
  3. Electric permittivity
  4. Magnetic flux
Answer: (2) Magnetic permeability

Why: From Ampere's force law $F/L = \mu_0 I_1 I_2 / (2\pi r)$, rearranging gives $\mu_0 = (F/L) \cdot r / (I_1 I_2)$. Substituting dimensions: $[\mu_0] = ([MLT^{-2}]/[L]) \cdot [L] / [A]^2 = [MLT^{-2} A^{-2}]$. Distractor (1) self-inductance: $[L] = [ML^2 T^{-2} A^{-2}]$ (extra $L$). (3) permittivity: $[\varepsilon_0] = [M^{-1} L^{-3} T^4 A^2]$ (reciprocal sign of every exponent). (4) magnetic flux: $[\Phi_B] = [ML^2 T^{-2} A^{-1}]$ (extra $L$, only one $A^{-1}$).

NEET 2021

If $E$ and $G$ respectively denote energy and gravitational constant, then $E/G$ has the dimensions of

  1. $[M^2] [L^{-2}] [T^{-1}]$
  2. $[M^2] [L^{-1}] [T^0]$
  3. $[M] [L^{-1}] [T^{-1}]$
  4. $[M] [L^0] [T^0]$
Answer: (2)

Why: $[E] = [M L^2 T^{-2}]$ and $[G] = [M^{-1} L^3 T^{-2}]$ from the master table. Dividing: $$\left[\frac{E}{G}\right] = \frac{[M L^2 T^{-2}]}{[M^{-1} L^3 T^{-2}]} = [M^{1-(-1)} L^{2-3} T^{-2-(-2)}] = [M^2 L^{-1} T^0]$$ Distractor (1) miscomputes the $T$ exponent. (3) drops a power of $M$. (4) ignores the negative-exponent rule when dividing $L$ terms.

NEET 2021

If force $[F]$, acceleration $[A]$ and time $[T]$ are chosen as the fundamental physical quantities, find the dimensions of energy in this new system.

  1. $[F][A^{-1}][T]$
  2. $[F][A][T]$
  3. $[F][A][T^2]$
  4. $[F][A][T^{-1}]$
Answer: (3) $[F][A][T^2]$

Why: Energy in conventional dimensions is $[E] = [M L^2 T^{-2}]$. Assume $[E] = [F]^a [A]^b [T]^c$ and substitute $[F] = [M L T^{-2}]$, $[A] = [L T^{-2}]$, $[T] = [T]$: $$[M L^2 T^{-2}] = [M^a L^{a+b} T^{-2a -2b + c}]$$ Comparing: $a = 1$, $a + b = 2 \Rightarrow b = 1$, and $-2a - 2b + c = -2 \Rightarrow c = 2$. So $[E] = [F][A][T^2]$. Distractor (1) and (4) get wrong exponents for $T$; (2) drops the squared time.

FAQs — Dimensions of Physical Quantities

Short answers to the questions NEET aspirants ask most about dimensions and dimensional formulae.

What is the dimension of a physical quantity?
The dimension of a physical quantity is the power to which each base quantity must be raised to represent that quantity. NCERT identifies seven base dimensions — length [L], mass [M], time [T], electric current [A], thermodynamic temperature [K], amount of substance [mol] and luminous intensity [cd]. For example, force is mass times acceleration, so its dimensions are [M L T−2].
What is the difference between a dimensional formula and a dimensional equation?
A dimensional formula is the expression that shows which base quantities, and to what powers, build a derived quantity — for example [M L T−2] is the dimensional formula of force. A dimensional equation equates the symbol of the physical quantity in square brackets to its dimensional formula — for example, [F] = [M L T−2] is the dimensional equation of force.
Are dimensionless quantities the same as unitless quantities?
No. A quantity can be dimensionless and still carry a unit. Plane angle is the ratio of arc to radius — dimensionless — yet has the unit radian. Strain is the ratio of two lengths — dimensionless and unitless. Refractive index, dielectric constant, relative density and the fine-structure constant are all dimensionless. NEET 2022 tested this exact distinction with plane and solid angle.
Why do work, energy and torque share the same dimensions?
All three are products of force and length and therefore carry dimensions [M L² T−2]. But they describe different physics — work and energy are scalars representing energy transfer, while torque is a vector representing rotational tendency. Dimensional identity does not imply physical identity. The same trap appears with pressure, stress and Young's modulus, all [M L−1 T−2].
What are the dimensions of the universal gravitational constant G?
From Newton's law F = G m₁m₂/r², rearranging gives G = F r² / (m₁ m₂). Substituting dimensions, [G] = [M L T−2] × [L²] ÷ [M²], which simplifies to [M−1 L³ T−2]. The SI unit is N m² kg−2. This was a NIOS Terminal Exercise.
Can the argument of a sine or logarithm have dimensions?
No. The arguments of trigonometric, exponential and logarithmic functions must be dimensionless — NCERT states this explicitly in §1.6.1. If you see an expression like sin(ωt), then ωt must reduce to [M⁰ L⁰ T⁰] — which it does, because angular frequency has dimension [T−1] and time has dimension [T], so the product is pure. The same rule rules out terms like log(x) where x has dimensions.