Physics · Semiconductor Electronics

p-n Junction and Its Formation

The p-n junction is the basic building block of every semiconductor device — the diode, the transistor and the integrated circuit all rest on it. Following NCERT §14.5 and NIOS §28.3, this note traces how a junction forms inside a single crystal: the diffusion of majority carriers, the immobile ion cores left behind, the depletion region and the built-in barrier potential that brings the system to equilibrium. The mechanism is small in extent but heavy in NEET weightage.

What Is a p-n Junction

A p-n junction is the interface between a p-type and an n-type region within a single semiconductor crystal. NCERT introduces it as "the basic building block of many semiconductor devices like diodes, transistor, etc." A clear understanding of junction behaviour is the prerequisite for analysing the working of all later devices in the chapter.

The junction is not made by clamping two finished blocks together. The most convenient method, described in both NCERT and NIOS, is to take a single semiconducting crystal and introduce donor (pentavalent) impurities on one side and acceptor (trivalent) impurities on the other side. NCERT describes starting from a thin p-type silicon wafer and converting part of it into n-Si by adding a small, precise quantity of pentavalent impurity. The wafer then contains a p-region, an n-region, and a metallurgical junction between them.

Before the two regions interact, recall their carrier populations. In the n-region electrons are the majority carriers and holes the minority; in the p-region holes are the majority and electrons the minority. This asymmetry across the junction is what drives everything that follows.

RegionDopantMajority carrierMinority carrierFixed ion left after diffusion
n-regionPentavalent (donor) — As, Sb, PElectronsHolesPositive donor ion (immobile)
p-regionTrivalent (acceptor) — B, Al, InHolesElectronsNegative acceptor ion (immobile)

Diffusion of Majority Carriers

Two processes occur during the formation of a p-n junction: diffusion and drift. Diffusion comes first. Because the electron concentration is high on the n-side and low on the p-side, and the hole concentration is high on the p-side and low on the n-side, a steep concentration gradient exists across the junction.

Driven by this gradient alone — not by any external voltage — holes diffuse from the p-side to the n-side ($p \rightarrow n$) and electrons diffuse from the n-side to the p-side ($n \rightarrow p$). This motion of majority carriers across the junction constitutes the diffusion current. As NIOS adds, each electron that crosses into the p-region meets a hole and the pair recombines, eliminating one free electron and one hole near the junction.

Diffusion of majority carriers across the p-n junction p-region (holes) n-region (electrons) junction + + holes diffuse electrons diffuse
Diffusion is driven by the concentration gradient: majority holes move p → n and majority electrons move n → p, giving the diffusion current. Based on NCERT Fig. 14.10.

The Depletion Region and Immobile Ions

Each diffusing carrier leaves something behind. When an electron diffuses from $n \rightarrow p$, it leaves behind an ionised donor on the n-side. This donor ion carries a positive charge and is immobile — it is bonded to the surrounding lattice atoms and cannot move. As electrons keep diffusing, a layer of positive space charge builds up on the n-side of the junction.

Symmetrically, when a hole diffuses from $p \rightarrow n$, it leaves behind an ionised acceptor on the p-side — a negative, immobile charge. A layer of negative space charge therefore builds on the p-side. Together these two layers of fixed ion cores form the depletion region, so named because the electrons and holes that crossed initially depleted the region of its free charges.

NEET Trap

What the depletion region actually contains

A common error is to picture the depletion region as full of electrons and holes piled up at the junction. The opposite is true. The depletion region has been emptied of mobile charge carriers; what remains are only the immobile ionised donor cores (positive, on the n-side) and immobile ionised acceptor cores (negative, on the p-side). NIOS confirms these are the "fixed donor and acceptor ions," not majority or minority carriers.

Depletion region = fixed ion cores + no free carriers. Thickness ≈ one-tenth of a micrometre (NCERT); about 0.5 μm (NIOS).

Depletion region with immobile ions and the built-in field p-region depletion n-region + + + built-in field E (n → p) immobile negative acceptor ions immobile positive donor ions
The depletion region holds only fixed ion cores. The space charge sets up an internal electric field pointing from the positive (n-side) charge to the negative (p-side) charge. Based on NCERT Fig. 14.10–14.11 and NIOS Fig. 28.6–28.7.

Barrier Potential and the Built-in Field

With positive space charge on the n-side and negative space charge on the p-side, an electric field is established across the depletion region, directed from the positive charge towards the negative charge — that is, from the n-side to the p-side. This internal field is the engine of the drift process and the source of the junction's potential barrier.

The loss of electrons from the n-region and the gain of electrons by the p-region produces a difference of potential across the junction. The n-material becomes positive relative to the p-material. Because this potential difference tends to prevent further movement of electrons from the n-region into the p-region, it is called the barrier potential (also the built-in potential, $V_0$). NIOS notes that with no external field this barrier prevents diffusion of charge carriers across the junction.

Build on this

Once you can apply an external voltage to this barrier, the junction becomes a working diode. See Semiconductor Diode and Its I–V Characteristics.

Diffusion–Drift Equilibrium

The built-in field acts on any carrier near the junction. An electron that strays onto the p-side, or a hole that strays onto the n-side, is swept across by the field to its majority zone. This field-driven motion of carriers is called drift, and it gives rise to a drift current that flows in the direction opposite to the diffusion current.

The two currents do not start out equal. NCERT is precise about the sequence: initially the diffusion current is large and the drift current is small. As diffusion continues, the space-charge regions extend, the electric field strength rises, and the drift current grows. This process continues until the diffusion current exactly equals the drift current. At that instant the junction is formed and equilibrium is reached.

PropertyDiffusion currentDrift current
Carriers responsibleMajority carriersMinority carriers
Driving causeConcentration gradientBuilt-in electric field
Directionp → n (conventional)Opposite to diffusion current
At equilibriumEqual in magnitude, opposite in direction → net current is zero
NEET Trap

"Zero net current" does not mean "no current"

At equilibrium NCERT states there is "no net current" — but this is the result of two non-zero currents cancelling, not the absence of carrier motion. The diffusion current is carried by majority carriers moving down the concentration gradient; the drift current is carried by minority carriers swept by the field. They are equal and opposite, so they sum to zero. NIOS phrases the equilibrium as "zero, as equal and opposite charges are crossing the junction" — not "zero because no charges cross."

Diffusion = majority carriers; drift = minority carriers. Net current = 0 by cancellation, not by stoppage.

Diffusion and drift currents balance at equilibrium p n diffusion current (majority) drift current (minority) |I_diffusion| = |I_drift| ⇒ net current = 0
The junction settles when the drift current grows enough to exactly cancel the diffusion current. Based on NCERT §14.5.1.

Barrier Values and the Unbiased Junction

The barrier potential is a characteristic of the semiconductor material. NIOS gives its value as about 0.3 V for germanium and about 0.7 V for silicon. These are the equilibrium built-in potentials with no external bias applied. The polarity of the barrier is always such as to oppose the further diffusion of majority carriers, which is precisely what holds the equilibrium in place.

This is also the most directly examined number on this subtopic. NEET 2021 asked whether the potential barrier of a p-n junction lies between 0.1 V and 0.3 V; the statement was marked incorrect because the silicon barrier is nearly 0.7 V. Memorising the two material values, and which value goes with which element, is the single highest-yield fact here.

Worked Example

Why can a p-n junction not be made by physically joining a p-type slab to an n-type slab? (NCERT Example 14.3)

No junction forms. Any slab, however flat, has surface roughness much larger than the inter-atomic crystal spacing (about 2 to 3 Å). Continuous contact at the atomic level is therefore impossible, and the gap behaves as a discontinuity for the flowing charge carriers. A genuine junction must be created within one crystal by doping one side with donors and the other with acceptors, so that diffusion and the depletion region can develop across a continuous lattice.

Quick Recap

p-n junction formation in one screen

  • A junction is made inside a single crystal by doping one side n-type (donors) and the other p-type (acceptors), not by pressing two slabs together.
  • Diffusion of majority carriers down the concentration gradient: holes p → n, electrons n → p, giving the diffusion current.
  • Diffusing carriers leave behind immobile ionised cores — positive donors on the n-side, negative acceptors on the p-side — forming the depletion region (no free carriers; thickness ≈ 0.1–0.5 μm).
  • The space charge sets up a built-in field (n → p) and a barrier potential: about 0.3 V for Ge, 0.7 V for Si, opposing further diffusion.
  • The field drives a drift current (minority carriers) opposite to the diffusion current; the junction reaches equilibrium when the two are equal, giving zero net current.

NEET PYQ Snapshot — p-n Junction and Its Formation

Real NEET questions touching depletion width, barrier potential and the formation mechanism, plus NCERT exercise concepts.

NEET 2020

The increase in the width of the depletion region in a p-n junction diode is due to

  1. reverse bias only
  2. both forward bias and reverse bias
  3. increase in forward current
  4. forward bias only
Answer: (1) reverse bias only

Under reverse bias the external battery attracts majority carriers away from the junction, so the depletion region widens and the barrier rises to (V₀ + V). Forward bias narrows it.

NEET 2021

Consider statements (A) and (B): (A) A zener diode is connected in reverse bias when used as a voltage regulator. (B) The potential barrier of a p-n junction lies between 0.1 V to 0.3 V.

  1. (A) is incorrect but (B) is correct.
  2. (A) and (B) both are correct.
  3. (A) and (B) both are incorrect.
  4. (A) is correct and (B) is incorrect.
Answer: (4) (A) correct, (B) incorrect

The potential barrier of a silicon diode is nearly 0.7 V (≈0.3 V for germanium), so statement (B) is wrong. The zener-as-regulator statement (A) is correct.

Concept · NCERT Ex 14.4

In an unbiased p-n junction, holes diffuse from the p-region to the n-region because

  1. free electrons in the n-region attract them.
  2. they move across the junction by the potential difference.
  3. hole concentration in the p-region is more as compared to the n-region.
  4. all the above.
Answer: (c) higher hole concentration in p-region

Diffusion in an unbiased junction is driven purely by the concentration gradient, not by any potential difference. Holes flow from the high-concentration p-side to the low-concentration n-side.

FAQs — p-n Junction and Its Formation

Quick answers to the questions most asked on junction formation.

Can a p-n junction be made by physically pressing a p-type slab against an n-type slab?
No. Any slab, however flat, has surface roughness much larger than the inter-atomic crystal spacing (about 2 to 3 Å), so continuous contact at the atomic level is not possible and the junction would behave as a discontinuity for the flowing charge carriers. A real junction is made within a single crystal by adding donor impurities to one side and acceptor impurities to the other, as described in NCERT and NIOS.
What is the depletion region made of?
The depletion region is the narrow zone on either side of the junction that has been emptied of free charge carriers. It contains only the immobile ionised donor cores (positive) on the n-side and immobile ionised acceptor cores (negative) on the p-side. It is called the depletion region because the electrons and holes that crossed initially depleted it of its free charges. Its thickness is of the order of one-tenth of a micrometre.
Why do holes diffuse from the p-side to the n-side during junction formation?
Holes diffuse from the p-region to the n-region because the hole concentration in the p-region is much greater than in the n-region. Diffusion is driven purely by this concentration gradient, not by any external potential difference. Electrons diffuse the opposite way, from n to p, for the same reason.
What is the value of the barrier potential for silicon and germanium?
The barrier potential is a characteristic of the semiconductor material. It is about 0.3 V for germanium and about 0.7 V for silicon. NEET 2021 tested this directly: the claim that the potential barrier of a p-n junction lies between 0.1 V and 0.3 V was marked incorrect because the silicon barrier is nearly 0.7 V.
Why is there no net current in an unbiased p-n junction at equilibrium?
As the depletion region grows, the electric field grows and the drift current increases until it exactly balances the diffusion current. The diffusion current (majority carriers crossing down the concentration gradient) and the drift current (minority carriers swept across by the field) are equal in magnitude and opposite in direction, so the net current is zero even though both component currents are non-zero.
Does the width of the depletion region increase under forward or reverse bias?
The depletion width increases under reverse bias only. In reverse bias the external field pulls majority carriers away from the junction, widening the space-charge region and raising the barrier height to (V0 + V). Forward bias does the opposite: it narrows the depletion region and lowers the barrier to (V0 − V). NEET 2020 tested exactly this.