Statement of the law
Ampere's circuital law provides an alternative and appealing way of expressing the field–current relationship contained in the Biot–Savart law. Consider an open surface bounded by a closed curve C, with current passing through it. Break the boundary into small line elements $d\mathbf{l}$, take the tangential component of the magnetic field $B_t$ at each element, and multiply by the element length: $B_t\,dl = \mathbf{B}\cdot d\mathbf{l}$. Summing over the boundary in the limit of vanishingly small elements gives an integral.
Ampere's law states that this integral equals $\mu_0$ times the total current passing through the surface:
$$\oint \mathbf{B}\cdot d\mathbf{l} = \mu_0 I$$
where $I$ is the total current through the surface and the integral is taken over the closed loop coinciding with the boundary C. As NIOS Section 18.4 stresses, the result is independent of the size or shape of the closed loop. The relation carries a sign convention given by the right-hand rule: curl the fingers of the right hand in the sense the boundary is traversed in the loop integral, and the thumb points in the direction in which current $I$ is counted positive.
The magnetic analogue of Gauss's law
Ampere's circuital law is not new in content from the Biot–Savart law. Both relate the magnetic field and the current, and both express the same physical consequences of a steady electrical current. In NCERT's words, Ampere's law is to the Biot–Savart law what Gauss's law is to Coulomb's law. Both Ampere's and Gauss's laws relate a physical quantity on the periphery or boundary — the magnetic or electric field — to another physical quantity, the source in the interior, which is the enclosed current or the enclosed charge respectively.
One restriction must be remembered: Ampere's circuital law holds for steady currents that do not fluctuate with time. With that caveat, symmetry turns the law into a calculation tool, in exactly the way Gauss's law is wielded in electrostatics.
| Aspect | Gauss's law (electric) | Ampere's law (magnetic) |
|---|---|---|
| Integral form | ∮E·dA = q_enc/ε₀ | ∮B·dl = μ₀I_enc |
| Integral over | Closed surface | Closed loop (line) |
| Source in interior | Enclosed charge | Enclosed current |
| Underlying inverse-square law | Coulomb's law | Biot–Savart law |
| Made tractable by | Symmetry of charge | Symmetry of current |
Choosing an Amperian loop
For many applications a much simplified version of the law suffices. We assume it is possible to choose a loop — called an Amperian loop — such that at each point of the loop one of three conditions holds: (i) $\mathbf{B}$ is tangential to the loop and is a non-zero constant $B$; or (ii) $\mathbf{B}$ is normal to the loop; or (iii) $\mathbf{B}$ vanishes. Let $L$ be the length of the loop for which $\mathbf{B}$ is tangential, and let $I_e$ be the current enclosed. The law then reduces to
$$B L = \mu_0 I_e$$
This reduction is only valid when the configuration has a symmetry — such as the cylindrical symmetry of an infinite straight wire — that guarantees one of the three conditions everywhere on the loop. Without symmetry the integral cannot be pulled apart, and one falls back on the Biot–Savart law.
Application 1 — long straight wire
For an infinite straight current-carrying wire, the natural Amperian loop is a circle of radius $r$ with the wire along its axis. By symmetry the field is tangential to the circle and has the same magnitude at every point on it, so the left-hand side of $BL = \mu_0 I_e$ becomes $B \cdot 2\pi r$. The full current $I$ threads the loop, giving
$$B \times 2\pi r = \mu_0 I \quad\Rightarrow\quad B = \frac{\mu_0 I}{2\pi r}$$
This is the same field obtained, with far more labour, by integrating the Biot–Savart law over the whole wire. NCERT highlights four features of this result that are favourite NEET hooks: the field has cylindrical symmetry (it depends only on $r$); its lines form closed concentric circles rather than originating and terminating on charges; even for an infinite wire the field at a finite distance is finite and blows up only as $r \to 0$; and its direction follows the right-hand grip rule — grasp the wire with the thumb along the current and the fingers curl in the direction of $\mathbf{B}$.
Stacking many such loops into a tightly wound coil gives the uniform interior field of a solenoid. See Solenoid Magnetic Field for the rectangular-loop derivation that gives $B = \mu_0 n I$.
Application 2 — inside a thick wire
NCERT Example 4.7 takes a long straight wire of circular cross-section (radius $a$) carrying steady current $I$ distributed uniformly across the cross-section, and asks for the field in the regions $r < a$ and $r > a$. This is the single most-tested consequence of Ampere's law for NEET.
Outside ($r > a$). The Amperian loop is a circle concentric with the cross-section, $L = 2\pi r$, and the current enclosed is the full $I$. The law gives the familiar straight-wire result:
$$B (2\pi r) = \mu_0 I \quad\Rightarrow\quad B = \frac{\mu_0 I}{2\pi r}, \qquad B \propto \frac{1}{r}\;(r>a)$$
Inside ($r < a$). Now the current enclosed $I_e$ is not $I$ but is less than this value. Since the distribution is uniform, $I_e = I\left(\dfrac{\pi r^2}{\pi a^2}\right) = I\dfrac{r^2}{a^2}$. Applying Ampere's law,