Physics · Kinetic Theory of Gases

Behaviour of Gases — Boyle, Charles & Avogadro

A gas held at low pressure and high temperature obeys a single tidy relation between its pressure, volume and absolute temperature. NCERT §12.3 builds that relation from four empirical laws — Boyle's, Charles's, Gay-Lussac's and Avogadro's — and combines them into the ideal gas equation $PV = \mu RT = N k_B T$. This deep-dive lays out each law in parallel, fixes the universal gas constant $R$ and the Boltzmann constant $k_B$, treats the ideal gas as the low-pressure limit of a real gas, and closes with the NEET traps and PYQs that recur on this section.

Why gases are the simple case

Properties of gases are easier to describe than those of solids and liquids. In a gas the molecules are far apart and their mutual interactions are negligible except during the brief instant of a collision. With the forces between molecules effectively switched off, the bulk behaviour collapses to one experimental relation. NCERT writes it for a fixed sample as $PV = KT$, where $T$ is the absolute (kelvin) temperature and $K$ is constant for that sample but grows with the amount of gas.

This simplicity holds only in a regime — low pressure and high temperature, well above the temperature at which the gas would liquefy or solidify. There the molecules are widely spaced, interactions vanish, and the gas approaches what we will define below as an ideal gas. The four classical gas laws are simply this one relation read with one variable held fixed at a time.

The four empirical gas laws

The gas laws share an identical logical shape: hold some quantities constant, and two of the remaining variables are tied by a simple proportionality. Reading them as a set, rather than as four unrelated facts, is the fastest route through this topic.

LawHeld constantRelationGraph shape
Boyle's law$T$, amount of gas$PV = \text{const}$, i.e. $P \propto 1/V$$P$–$V$ rectangular hyperbola (isotherm)
Charles's law$P$, amount of gas$V \propto T$ (absolute $T$)$V$–$T$ straight line through origin
Gay-Lussac / pressure law$V$, amount of gas$P \propto T$ (absolute $T$)$P$–$T$ straight line through origin
Avogadro's law$T$, $P$$V \propto N$ (number of molecules)$V$–$N$ straight line through origin

Each is a special case of $PV = KT$ with the labelled variables frozen. Charles's, Gay-Lussac's and Avogadro's laws are direct proportionalities, so all three graph as straight lines through the origin; Boyle's law is an inverse proportionality, so it graphs as a hyperbola. Three of the four demand that $T$ be measured on the absolute (kelvin) scale, which is the most exploited trap in the chapter.

Boyle's law in detail

Fix the amount of gas and the temperature in $PV = KT$ and the right-hand side is constant, so

$$PV = \text{constant} \qquad (T,\, n \text{ fixed}).$$

At constant temperature, the pressure of a given mass of gas varies inversely with its volume. Halve the volume and the pressure doubles. On a $P$–$V$ graph each fixed temperature gives one curve, a rectangular hyperbola called an isotherm; a higher temperature shifts the whole hyperbola outward. NCERT notes that experimental $P$–$V$ curves agree with Boyle's law best at high temperatures and low pressures — the same ideal regime.

V P $T_1$ (lower) $T_2 > T_1$
Fig. 1 — Boyle's law isotherms. At fixed temperature, $PV$ is constant, so each curve is a rectangular hyperbola ($P \propto 1/V$). A higher temperature ($T_2 > T_1$) places the isotherm further from the origin, since $PV = KT$ rises with $T$.

Charles's law in detail

Now fix the pressure. NCERT reads off from $PV = KT$ that $V \propto T$: at fixed pressure, the volume of a given mass of gas is proportional to its absolute temperature. The graph of $V$ against absolute $T$ is a straight line through the origin. Plotted against Celsius temperature instead, the same data is still a straight line, but it intercepts the temperature axis at $-273.15~^\circ\text{C}$ — the experimental signpost to absolute zero.

The companion pressure law (Gay-Lussac) fixes the volume instead: $P \propto T$. Heating a gas in a sealed rigid container raises its pressure in direct proportion to absolute temperature. Both are the same straight-line proportionality with a different variable held constant.

T (K) V $P_1$ (lower) $P_2 > P_1$ 0
Fig. 2 — Charles's law. At fixed pressure, $V \propto T$ on the absolute scale, giving a straight line through the origin. A lower pressure makes the line steeper (larger $V$ for the same $T$). The lines extrapolate to the origin at $T = 0~\text{K}$.

Avogadro's law and the mole

Avogadro's law (originally a hypothesis) states that equal volumes of all gases at the same temperature and pressure contain equal numbers of molecules. NCERT reaches it by writing $K = N k_B$ in $PV = KT$, where $N$ is the number of molecules and $k_B$ is the same constant for every gas:

$$\frac{PV}{NT} = k_B = \text{constant for all gases}.$$

If $P$, $V$ and $T$ are the same, then $N$ is the same — irrespective of the chemical identity of the gas. Equivalently, the number density (molecules per unit volume) is identical for all gases at a fixed temperature and pressure.

QuantitySymbolNCERT value
Avogadro number$N_A$$6.02 \times 10^{23}$ per mole
Molar volume at STP (273 K, 1 atm)$V_m$$22.4~\text{litres}$
Mass of 22.4 L at STPequals the molecular weight in grams (one mole)

The number of molecules in 22.4 litres of any gas at STP is the Avogadro number $N_A = 6.02 \times 10^{23}$, and that amount of substance is one mole. Avogadro inferred the equality of numbers in equal volumes from chemical reactions; kinetic theory later justified it from first principles.

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These laws describe matter as a swarm of molecules — see molecular nature of matter for the atomic picture that makes the mole and number density meaningful.

Combining into the ideal gas equation

Putting $K = N k_B$ back into $PV = KT$ gives the molecular form $PV = N k_B T$. Grouping molecules into moles via $N = \mu N_A$ and defining $R = N_A k_B$ produces the form most used in NEET:

$$PV = \mu R T = N k_B T,$$

where $\mu$ is the number of moles, $N$ the number of molecules, $R$ the universal gas constant and $k_B$ the Boltzmann constant. The number of moles itself can be read two ways NCERT gives explicitly,

$$\mu = \frac{N}{N_A} = \frac{M}{M_0},$$

where $M$ is the mass of the sample and $M_0$ its molar mass. Writing $P = k_B n T$ with $n = N/V$ the number density, or $P = \rho R T / M_0$ with $\rho$ the mass density, are two further rearrangements of the same equation. A gas that satisfies $PV = \mu R T$ exactly at all pressures and temperatures is, by definition, an ideal gas — a theoretical model that no real gas matches perfectly.

NCERT Example 12.8 (adapted)

Show, using $PV = \mu RT$, that one mole of any ideal gas at STP (273 K, $1~\text{atm} = 1.01 \times 10^{5}~\text{Pa}$) occupies 22.4 litres. Take $R = 8.31~\text{J mol}^{-1}\text{K}^{-1}$.

Rearrange for one mole ($\mu = 1$): $V = \dfrac{\mu R T}{P} = \dfrac{(1)(8.31)(273)}{1.01 \times 10^{5}}$.

Evaluate: $V \approx \dfrac{2268}{1.01 \times 10^{5}} \approx 2.24 \times 10^{-2}~\text{m}^3 = 22.4~\text{litres}$. This molar volume is independent of the gas — a direct consequence of Avogadro's law.

The constants R and k

$R$ and $k_B$ are the same physics seen at two scales, and confusing them is a standard NEET error. $R$ is the gas constant per mole; $k_B$ is the gas constant per molecule. They are linked through Avogadro's number.

ConstantSymbol & valuePer …Appears in
Universal gas constant$R = 8.314~\text{J mol}^{-1}\text{K}^{-1}$mole$PV = \mu R T$
Boltzmann constant$k_B = 1.38 \times 10^{-23}~\text{J K}^{-1}$molecule$PV = N k_B T$
Link$k_B = R / N_A$$N_A = 6.02 \times 10^{23}$

Dalton's law of partial pressures

For a mixture of non-interacting ideal gases — $\mu_1$ moles of gas 1, $\mu_2$ of gas 2, and so on — sharing a vessel of volume $V$ at temperature $T$, the equation of state is

$$PV = (\mu_1 + \mu_2 + \dots)RT = \frac{\mu_1 RT}{V} + \frac{\mu_2 RT}{V} + \dots = P_1 + P_2 + \dots$$

The term $P_i = \mu_i RT/V$ is the partial pressure of component $i$ — the pressure that gas alone would exert in the same vessel at the same temperature. The total pressure of a mixture of ideal gases is the sum of the partial pressures. This is Dalton's law of partial pressures, and it follows immediately from applying $PV = \mu RT$ to the whole mixture.

The ideal gas as a limit; deviations of real gases

No real gas is truly ideal. The ideal model assumes point molecules with no intermolecular forces — true only when molecules are far apart, which means low pressure or high temperature. As NCERT puts it, at low pressures or high temperatures the molecules are far apart and molecular interactions are negligible, so the gas behaves like an ideal one. The clean diagnostic is the dimensionless ratio $PV/\mu RT$, which equals exactly 1 for an ideal gas at every state point.

P PV/μRT ideal (= 1) 1 real gas
Fig. 3 — Real gas versus ideal gas. For an ideal gas $PV/\mu RT = 1$ at all pressures (dashed line). A real gas departs from 1 — typically dipping below at moderate pressure (attractions dominate) and rising above at high pressure (finite molecular volume dominates) — but every real-gas curve returns toward 1 as $P \to 0$. The ideal gas is the low-pressure limit of any real gas.

NCERT's Fig. 12.1 shows the same gas at three temperatures: all curves approach ideal behaviour as pressure falls and as temperature rises, and the higher-temperature curve hugs the ideal line over a wider pressure range. This is the qualitative content NEET expects — the direction of approach to ideality, not a quantitative equation of state for real gases.

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These laws are empirical here. They are derived from molecular collisions in kinetic theory of an ideal gas, where $PV = \tfrac{1}{3}Nm\overline{v^2}$ recovers Boyle, Charles and Avogadro.

Quick recap

Gas laws in one breath

  • Boyle: $PV = $ const at fixed $T,n$ → $P$–$V$ hyperbola. Charles: $V \propto T$ at fixed $P$ → straight line. Pressure law: $P \propto T$ at fixed $V$. Avogadro: equal $V$ at same $T,P$ → equal $N$.
  • All combine to $PV = \mu R T = N k_B T$; an ideal gas obeys this exactly at all states.
  • $R = 8.314~\text{J mol}^{-1}\text{K}^{-1}$ (per mole); $k_B = 1.38 \times 10^{-23}~\text{J K}^{-1}$ (per molecule); $k_B = R/N_A$.
  • One mole of any ideal gas occupies 22.4 L at STP and holds $N_A = 6.02 \times 10^{23}$ molecules.
  • $T$ is always absolute (kelvin). $V$ vs $T(\text{K})$ passes through the origin; $V$ vs $t(^\circ\text{C})$ does not.
  • Real gases approach ideal behaviour at low pressure and high temperature; $PV/\mu RT \to 1$ as $P \to 0$.
  • Dalton: total pressure of an ideal-gas mixture is the sum of partial pressures, $P = P_1 + P_2 + \dots$

NEET PYQ Snapshot — Behaviour of Gases

Three PYQs that test the gas laws and the ideal gas equation directly. Same toolkit each time: fix what's constant, write $PV = nRT$, keep $T$ in kelvin.

NEET 2024

The graph shows the $T$–$V$ curves of an ideal gas (with $T$ temperature and $V$ volume) at three pressures $P_1$, $P_2$ and $P_3$, compared with Charles's law (dotted lines). The correct relation is:

  1. $P_3 > P_2 > P_1$
  2. $P_1 > P_3 > P_2$
  3. $P_2 > P_1 > P_3$
  4. $P_1 > P_2 > P_3$
Answer: (4) P₁ > P₂ > P₃

Charles's law. At fixed pressure $V = (\mu R/P)\,T$, so on a $T$–$V$ plot the slope $dT/dV = P/\mu R$ is proportional to $P$. The steepest line corresponds to the highest pressure; ranking the slopes gives $P_1 > P_2 > P_3$. (Equivalently, at a given $T$ the smallest volume belongs to the highest pressure.)

NEET 2022

The volume occupied by the molecules contained in 4.5 kg of water at STP, if the intermolecular forces vanish away, is:

  1. $5.6 \times 10^{3}~\text{m}^3$
  2. $5.6 \times 10^{-3}~\text{m}^3$
  3. $5.6~\text{m}^3$
  4. $5.6 \times 10^{6}~\text{m}^3$
Answer: (3) 5.6 m³

Ideal gas equation. Moles $n = \dfrac{4.5 \times 10^{3}~\text{g}}{18~\text{g/mol}} = 250$. With forces gone the molecules form an ideal gas, so $V = \dfrac{nRT}{P} = \dfrac{250 \times 8.3 \times 273}{10^{5}} \approx 5.66~\text{m}^3$. (Or directly: $250~\text{mol} \times 22.4~\text{L} = 5600~\text{L} = 5.6~\text{m}^3$ via the molar volume.)

NEET 2025

A container has two chambers of volumes $V_1 = 2$ L and $V_2 = 3$ L separated by a thermal-insulator partition. They hold $n_1 = 5$ and $n_2 = 4$ moles of ideal gas at pressures $p_1 = 1$ atm and $p_2 = 2$ atm. When the partition is removed, the equilibrium pressure is:

  1. $1.8$ atm
  2. $1.3$ atm
  3. $1.6$ atm
  4. $1.4$ atm
Answer: (3) 1.6 atm

Dalton / ideal-gas mixing at fixed T. Since $nRT = pV$ for each chamber and temperature is common, $p_1 V_1 + p_2 V_2 = P(V_1 + V_2)$. Thus $1(2) + 2(3) = P(5)$, giving $P = 8/5 = 1.6~\text{atm}$.

FAQs — Behaviour of Gases

Short answers to the gas-law questions NEET aspirants get wrong most often.

Why must temperature be in kelvin for the gas laws?
Charles's law ($V \propto T$) and the pressure law ($P \propto T$) are direct proportionalities, and a direct proportionality is only meaningful from an absolute zero. The Celsius scale has its zero at the freezing point of water, not at the true zero of molecular motion, so $V \propto t(^\circ\text{C})$ is false — a gas at $0~^\circ\text{C}$ does not have zero volume. The ideal gas equation $PV = nRT$ is likewise written with $T$ as absolute temperature. Always convert: $T(\text{K}) = t(^\circ\text{C}) + 273.15$, usually rounded to 273 in NEET.
What is the difference between the universal gas constant R and the Boltzmann constant k?
$R = 8.314~\text{J mol}^{-1}\text{K}^{-1}$ is the gas constant per mole; it appears in $PV = nRT$ where $n$ is the number of moles. $k_B = 1.38 \times 10^{-23}~\text{J K}^{-1}$ is the gas constant per molecule; it appears in $PV = Nk_BT$ where $N$ is the number of molecules. They are linked by $k_B = R/N_A$, where $N_A = 6.02 \times 10^{23}$ is Avogadro's number. $R$ is macroscopic bookkeeping, $k_B$ is molecular bookkeeping; multiplying $k_B$ by $N_A$ reassembles $R$.
Is Avogadro's law about volume or about number of molecules?
Both, read in the right direction. Avogadro's law states that equal volumes of all gases at the same temperature and pressure contain equal numbers of molecules. Equivalently, at fixed $T$ and $P$ the number density (molecules per unit volume) is the same for every gas. The fact NEET tests: one mole of any ideal gas occupies 22.4 litres at STP (273 K, 1 atm) and contains $N_A = 6.02 \times 10^{23}$ molecules.
When does a real gas behave most like an ideal gas?
At low pressure and high temperature — specifically temperatures well above the gas's liquefaction point. Under these conditions molecules are far apart, so intermolecular forces and the finite molecular volume become negligible, which are exactly the two assumptions the ideal gas model makes. As pressure rises or temperature falls toward liquefaction, the real-gas $PV/\mu RT$ curve departs from the ideal value of 1.
What does the quantity PV/nRT tell us about a gas?
For a perfect (ideal) gas, $PV/\mu RT$ equals exactly 1 at every pressure and temperature. For a real gas it deviates from 1, and the size of the deviation measures how non-ideal the gas is under those conditions. A plot of $PV/\mu RT$ versus $P$ for a real gas approaches the horizontal line at 1 as pressure tends to zero, which is why the ideal gas is described as the low-pressure limit of any real gas.
What is Dalton's law of partial pressures and how does it follow from the ideal gas equation?
For a mixture of non-interacting ideal gases sharing one vessel of volume $V$ at temperature $T$, the total pressure is the sum of the partial pressures: $P = P_1 + P_2 + \dots$, where each partial pressure $P_i = \mu_i RT/V$ is the pressure that component $i$ alone would exert in the same vessel. It follows directly from applying $PV = \mu RT$ to the mixture: $PV = (\mu_1 + \mu_2 + \dots)RT$, then splitting the right side term by term.