Physics · Electric Charges and Fields

Electric Field & Field Lines

A charge does not reach across empty space to grip another charge directly; it first fills the surrounding space with an electric field, and that field exerts the force. NCERT Sections 1.7 and 1.8 build this idea from the operational definition $E = F/q_0$ up to the elegant pictures Faraday called lines of force. For NEET, this subtopic is the bridge between Coulomb's law and every flux, dipole and Gauss problem that follows.

What the Electric Field Is

Consider a point charge $Q$ fixed at the origin. Place a second charge $q$ at a point $P$ a distance $r$ away, and $Q$ exerts a force on $q$ as given by Coulomb's law. NCERT poses a sharper question: if $q$ is removed, what is left at $P$? The answer the early scientists gave is that $Q$ produces an electric field everywhere in the surrounding space. When another charge is brought to $P$, the field already present there acts on it and produces the force.

Operationally, the field is the force per unit positive test charge. If a small positive test charge $q_0$ at a point experiences a force $\mathbf{F}$, then the electric field there is

$$\mathbf{E} = \frac{\mathbf{F}}{q_0}, \qquad \mathbf{F} = q\,\mathbf{E}$$

Equation $\mathbf{F} = q\mathbf{E}$ also fixes the SI unit: with force in newtons and charge in coulombs, $E$ is measured in newtons per coulomb (N/C). NCERT notes the alternate unit volt per metre (V/m), introduced in the next chapter — the two are numerically identical. Because force is a vector, the electric field is a vector field: it has a magnitude and a direction at every point in three-dimensional space.

NEET Trap

The field does not depend on the test charge

Although $E$ is defined as $F/q$, the field is independent of $q$. Since $F$ is proportional to $q$, the ratio $F/q$ cancels the dependence. The field is a property of the source and the point in space — not of whatever charge you happen to drop there.

To avoid the test charge disturbing the source, NCERT writes the exact definition as a limit: $\;\mathbf{E} = \displaystyle\lim_{q \to 0}\frac{\mathbf{F}}{q}.$

Field of a Point Charge

Setting $q_0$ to unity in $F = q_0 E$ shows that the electric field due to a charge $Q$ is numerically equal to the force a unit positive charge would feel. Substituting Coulomb's law gives the field of a point charge at distance $r$:

$$\mathbf{E} = \frac{1}{4\pi\varepsilon_0}\,\frac{Q}{r^{2}}\,\hat{\mathbf{r}} = k\,\frac{Q}{r^{2}}\,\hat{\mathbf{r}}, \qquad k = \frac{1}{4\pi\varepsilon_0} \approx 9 \times 10^{9}\ \text{N m}^2\,\text{C}^{-2}$$

Here $\hat{\mathbf{r}}$ is the unit vector pointing from the source charge to the field point. NCERT lists the consequences plainly: for a positive source charge the field points radially outward; for a negative source charge it points radially inward. Because the magnitude depends only on $r$, the field has the same value everywhere on a sphere centred on the charge — it possesses spherical symmetry.

Figure 1 +Q −Q
Field of a single point charge. For $+Q$ the field arrows point radially outward; for $-Q$ they point radially inward. Arrow length shrinks with distance because $E \propto 1/r^2$.
NEET Trap

$E = kQ/r^2$ is the field; $F = qE$ is the force

$E = kQ/r^2$ involves only the source charge $Q$ — it is the field the source sets up, with or without anything placed in it. The force on a charge $q$ that you then introduce is $F = qE$. Writing $F = kQ/r^2$ (omitting the second charge) or treating $E$ as if it depended on $q$ are both classic errors.

Field = cause set up by the source. Force = effect felt by a charge placed in it.

Superposition of Fields

For a system of charges $q_1, q_2, \ldots, q_n$, the field at a point $P$ is again defined as the force on a unit positive test charge placed there without disturbing the sources. Combining Coulomb's law with the superposition principle, the total field is the vector sum of the fields each charge would produce alone:

$$\mathbf{E}(\mathbf{r}) = \mathbf{E}_1 + \mathbf{E}_2 + \cdots + \mathbf{E}_n = \frac{1}{4\pi\varepsilon_0}\sum_{i=1}^{n}\frac{q_i}{r_{iP}^{2}}\,\hat{\mathbf{r}}_{iP}$$

Each $\hat{\mathbf{r}}_{iP}$ points from charge $q_i$ to $P$, and $r_{iP}$ is the distance between them. Because $\mathbf{E}$ is a vector, the contributions must be added head-to-tail (or by components), not as bare numbers — a point the worked example below makes concrete.

NCERT Example 1.8

Two point charges $q_1 = +10^{-8}\,\text{C}$ and $q_2 = -10^{-8}\,\text{C}$ are placed $0.1\,\text{m}$ apart. The field is required at three points around them.

At a point A located $0.05\,\text{m}$ from each charge along the line joining them, both fields point the same way: $E_{1A} = E_{2A} = 3.6\times10^{4}\ \text{N C}^{-1}$, so they add to $E_A = 7.2\times10^{4}\ \text{N C}^{-1}$ directed toward the right. At a point B beyond the positive charge the two fields oppose, giving $E_B = 3.2\times10^{4}\ \text{N C}^{-1}$ to the left. The arithmetic differs only because the directions differ — the same superposition rule governs all three points.

Build the foundation

The vector-sum rule used here is developed in full in Forces Between Multiple Charges — work through it before tackling field problems.

Physical Significance of the Field

For electrostatics, NCERT is candid: the electric field is convenient but not strictly necessary, since the measurable quantity — the force on a charge — can be found directly from Coulomb's law and superposition. The field is, for static charges, simply an elegant way of characterising the electrical environment, telling us at each point what force a unit positive charge would feel.

Its deeper meaning emerges only beyond electrostatics, with charges in accelerated motion. No signal can travel faster than the speed of light $c$, so the effect of a sudden movement of one charge cannot reach a distant charge instantaneously — there is a time delay between cause and effect. The field accounts for this elegantly: an accelerating charge launches electromagnetic waves that propagate at speed $c$ and only later exert a force on the distant charge.

Because of this, fields are regarded as physical entities with their own dynamics, able to carry energy, and not merely as mathematical bookkeeping. The concept, introduced by Faraday, is now central to physics.

AspectWhat NCERT establishes
DefinitionForce per unit positive test charge, $E = F/q_0$, taken in the limit $q_0 \to 0$.
Independence$E$ is independent of the test charge; it depends only on the source and the point in space.
Source vs. test chargeThe charge producing the field is the source charge; the charge probing it is the test charge.
Spatial natureA vector defined at every point of 3-D space; varies from point to point.
Finite propagationEffects of a changing source travel outward at speed $c$, not instantaneously.

Electric Field Lines

Since $\mathbf{E}$ is a vector at every point, we can draw arrows whose length is proportional to the field strength at each location. For a point charge these arrows point radially outward and shorten with distance because $E \propto 1/r^2$. Connecting arrows that follow one another produces a continuous curve — a field line. Faraday named these lines of force; NCERT prefers the term field lines as more accurate.

Replacing arrows with lines seems to discard the information once carried by arrow length. It does not. The field magnitude is now encoded in the density of lines: where the field is strong, near a charge, the lines crowd together; where it is weak, far away, the lines spread apart. The number of lines crossing a unit area held perpendicular to them is proportional to the field magnitude there.

A neat self-consistency follows. As distance from a point charge increases, the field falls as $1/r^2$ while the area enclosing the charge grows as $r^2$, so the number of lines crossing any enclosing surface stays constant regardless of distance. The absolute number of lines one chooses to draw is arbitrary — only their relative density carries physical meaning.

Properties of Field Lines

A field line is, in general, a space curve drawn so that the tangent to it at any point gives the direction of the net field there; an arrowhead fixes which of the two tangent directions is meant. NCERT lists four governing properties, set out below.

PropertyStatementReason
EndpointsLines start on positive charges and end on negative charges; for a single charge they start or end at infinity.Field points away from $+$ and toward $-$.
ContinuityIn a charge-free region the lines are continuous curves with no breaks.The field is defined and finite at every such point.
No crossingTwo field lines can never cross each other.A crossing would give two field directions at one point — absurd.
No closed loopsElectrostatic field lines do not form closed loops.Follows from the conservative nature of the electrostatic field.
DirectionThe tangent at a point gives the direction of $\mathbf{E}$ there.Lines are built by joining field arrows.
DensityCloseness of lines is proportional to field strength.Lines per unit perpendicular area $\propto E$.
NEET Trap

Field lines never cross — and never loop

Two examiner favourites. First, no two field lines intersect: at a crossing the tangent would define two directions for $\mathbf{E}$, which is impossible. Second, electrostatic lines do not form closed loops — that is reserved for magnetic field lines. A diagram showing crossing lines or a closed electrostatic loop is automatically wrong.

Closer lines ⇒ stronger field. Lines begin on $+$, terminate on $-$ (or at infinity).

Field-Line Patterns

NCERT illustrates three standard configurations. A single charge gives the radial pattern of Figure 1 above. The remaining two — the dipole and a pair of like charges — reveal attraction and repulsion at a glance.

Figure 2 +q −q
A dipole $(+q, -q)$. Lines leave the positive charge and curve into the negative charge, picturing the mutual attraction of two equal and opposite charges.
Figure 3 null +q +q
Two equal positive charges $(q, q)$. The lines bend away from one another, vividly picturing mutual repulsion. Midway between them the opposing fields cancel, giving a null point where $E = 0$.
Quick Recap

Electric Field & Field Lines in one screen

  • Definition: $E = F/q_0$ — force per unit positive test charge, taken as $q_0 \to 0$. Unit: N/C ($=$ V/m). It is a vector field, independent of the test charge.
  • Point charge: $E = kQ/r^2$, radially out for $+Q$, in for $-Q$; spherically symmetric. Don't confuse the field $kQ/r^2$ with the force $qE$.
  • Superposition: total field is the vector sum $\mathbf{E} = \sum k q_i/r_{iP}^2\,\hat{\mathbf{r}}_{iP}$.
  • Significance: a real physical entity that mediates the force and propagates changes at speed $c$.
  • Field lines: tangent gives field direction; density ∝ strength; start on $+$, end on $-$; never cross; never form closed loops in electrostatics.
  • Patterns: radial (single charge), curving $+$ to $-$ (dipole), bending apart with a null point (two like charges).

NEET PYQ Snapshot — Electric Field & Field Lines

Genuine NEET previous-year questions that turn on the field of a charge and the force it exerts.

NEET 2020

A spherical conductor of radius 10 cm has a charge of $3.2 \times 10^{-7}\,\text{C}$ distributed uniformly. What is the magnitude of the electric field at a point 15 cm from the centre of the sphere? $\left(\frac{1}{4\pi\varepsilon_0} = 9\times10^9\ \text{N m}^2/\text{C}^2\right)$

  • (1) $1.28 \times 10^{5}\ \text{N/C}$
  • (2) $1.28 \times 10^{6}\ \text{N/C}$
  • (3) $1.28 \times 10^{7}\ \text{N/C}$
  • (4) $1.28 \times 10^{4}\ \text{N/C}$
Answer: (1)

Outside a uniformly charged sphere the field is that of a point charge at the centre: $E = kQ/r^2 = (9\times10^9)(3.2\times10^{-7})/(0.15)^2 = 1.28\times10^{5}\ \text{N/C}$. The radius 10 cm matters only to confirm the point lies outside.

NEET 2018

An electron falls from rest through a vertical distance $h$ in a uniform, vertically upward electric field $E$. The field is then reversed (same magnitude) and a proton falls from rest through the same distance $h$. The time of fall of the electron, compared with that of the proton, is:

  • (1) smaller
  • (2) 5 times greater
  • (3) 10 times greater
  • (4) equal
Answer: (1)

Each particle feels $F = eE$ of equal magnitude, so acceleration $a = eE/m \propto 1/m$. Since $m_e \ll m_p$, the electron's acceleration is far larger and $t_e < t_p$ — direct application of $F = qE$. Unlike free fall under gravity, the time here depends on mass.

NEET 2023

If $\oint_S \mathbf{E}\cdot d\mathbf{S} = 0$ over a closed surface, then:

  • (1) the electric field inside the surface is necessarily uniform.
  • (2) the number of flux lines entering the surface must equal the number leaving it.
  • (3) the magnitude of the electric field on the surface is constant.
  • (4) all the charges must necessarily be inside the surface.
Answer: (2)

Zero net outflow means the lines that enter must also leave — a direct reading of field lines as a flow picture. It says nothing about uniformity or where the charges sit; that net-flux idea is developed in Electric Flux.

FAQs — Electric Field & Field Lines

Six questions that clear the recurring confusions in this subtopic.

Does the electric field depend on the test charge used to measure it?
No. Although E is defined operationally as F/q, the field is independent of q. Since F is proportional to q, the ratio F/q does not depend on q. The electric field is a characteristic of the source charge and the point in space, not of the test charge placed there. To avoid disturbing the source, NCERT defines it as the limit of F/q as q tends to zero.
Why must the test charge be vanishingly small?
The source charge Q produces the field, but if a finite test charge q is brought near it, q exerts an equal and opposite force on Q and tends to move it, changing the very field we wish to measure. Making q negligibly small keeps the force on Q negligible while the ratio F/q stays finite, so E is defined as the limit of F/q as q tends to zero.
What is the difference between E = kQ/r² and F = qE?
E = kQ/r² gives the field that a single source charge Q sets up at a distance r — it does not involve the charge you place in the field. F = qE then gives the force on a charge q placed where the field is E. The field exists whether or not q is present; the force exists only when q is there. Mixing the two — for example writing F = kQ/r² — is a common NEET error.
Can two electric field lines ever cross?
No. If two lines crossed, the tangent at the point of intersection would give two different directions for the field there, but the field at a point can have only one direction. A crossing would therefore imply two directions for E at one point, which is absurd. Hence field lines never intersect.
What does the density of field lines represent?
The relative closeness of field lines represents the relative strength of the field. Lines crowd together where the field is strong (close to a charge) and spread apart where it is weak. Quantitatively, the number of lines crossing a unit area held perpendicular to them is proportional to the field magnitude, which reproduces the 1/r² fall-off of a point charge.
Why do electrostatic field lines not form closed loops?
Electrostatic field lines start on positive charges and end on negative charges (or run to and from infinity for a single charge). They never form closed loops because the electrostatic field is conservative — a consequence developed in the chapter on electrostatic potential. This distinguishes them from magnetic field lines, which do form closed loops.