Physics · Current Electricity

Temperature Dependence of Resistivity

The resistivity of a material is not a fixed number — it shifts as the material heats or cools. NCERT Section 3.8 captures this with a single linear law and traces it back to the microscopic picture $\rho = m/(ne^2\tau)$. The crucial NEET payoff is the contrast: metals grow more resistive with temperature while semiconductors grow less resistive, and the same equation explains both through the opposite behaviour of $\tau$ and $n$.

The Linear Resistivity Law

The resistivity of a material depends on temperature, and different materials respond differently. Over a temperature range that is not too large, the resistivity of a metallic conductor is given to good approximation by NCERT Eq. (3.26):

$$\rho_T = \rho_0\left[1 + \alpha\,(T - T_0)\right]$$

Here $\rho_T$ is the resistivity at temperature $T$, $\rho_0$ is the resistivity at a chosen reference temperature $T_0$, and $\alpha$ is the temperature coefficient of resistivity. Because resistance is proportional to resistivity for a fixed conductor, the same dependence carries straight over to resistance:

$$R_T = R_0\left[1 + \alpha\,\Delta T\right], \qquad \Delta T = T - T_0$$

Equation (3.26) implies that a plot of $\rho_T$ against $T$ is a straight line whose slope is set by $\alpha$. The relation is an approximation valid only over a limited range around $T_0$ where the curve is effectively straight, a point the next figure makes explicit.

Two cautions are worth fixing at the outset. First, the law is empirical and local: it describes the behaviour near a chosen reference temperature, and the coefficient $\alpha$ is itself an average over the range used, not a universal constant. Second, the resistance form $R_T = R_0[1 + \alpha\,\Delta T]$ holds only because the conductor's geometry — its length and cross-section — is assumed unchanged; what genuinely varies with temperature is the material property $\rho$, and $R$ simply inherits that variation. This is exactly the principle behind the platinum resistance thermometer, where a measured resistance is read back as a temperature.

Figure 1 · ρ–T for a metal (copper) Temperature T → ρ_T → positive slope (α > 0) non-linear at low T

Resistivity of copper rises with temperature; near $T_0$ the curve is straight, but at temperatures much below 0 °C it deviates noticeably from the line.

Temperature Coefficient of Resistivity

Rearranging the linear law gives the meaning of $\alpha$ directly. In the range where resistivity increases linearly with temperature, $\alpha$ is the fractional increase in resistivity per unit increase in temperature:

$$\alpha = \frac{\rho_T - \rho_0}{\rho_0\,(T - T_0)} = \frac{1}{\rho_0}\,\frac{\Delta\rho}{\Delta T}$$

From the defining equation the dimension of $\alpha$ is $(\text{temperature})^{-1}$, so its SI unit is $\mathrm{K^{-1}}$. Since a temperature difference has the same numerical value in kelvin and in degrees Celsius, $\alpha$ may equally be quoted per °C. For metals $\alpha$ is positive; for semiconductors and insulators it is negative.

Class of materialSign of αHow ρ changes with TMicroscopic mechanism
Metals (Cu, Ag, Pt)Positiveρ increases with Tn nearly constant; τ falls as lattice vibrations grow
Semiconductors (Si, Ge)Negativeρ decreases with Tn rises with T, outweighing the fall in τ
InsulatorsNegativeρ decreases with Tn rises with T (more carriers freed)
Alloys (manganin, constantan, nichrome)Nearly zeroρ almost unchangedvery weak dependence; ρ already high

All four rows trace back to a single equation. The derivation of conductivity in NCERT gives $\sigma = ne^2\tau/m$, and inverting it yields the resistivity expression at the heart of this topic, Eq. (3.27):

$$\rho = \frac{1}{\sigma} = \frac{m}{n\,e^2\,\tau}$$

So $\rho$ depends inversely on two quantities: the number $n$ of free carriers per unit volume, and the average time $\tau$ (the relaxation time) between collisions. Temperature pulls on both, and which one wins decides the sign of $\alpha$.

Metals: Positive α

As temperature rises, the average speed of the conduction electrons increases, so they collide with the fixed lattice ions more frequently. The average time between collisions $\tau$ therefore decreases with temperature. In a metal, the carrier density $n$ does not depend on temperature to any appreciable extent. With $n$ fixed and $\tau$ falling, $\rho = m/(ne^2\tau)$ must increase — exactly the rising graph observed for copper. This is why metals carry a positive temperature coefficient of resistivity.

ρ
Build the foundation first

The $\rho = m/(ne^2\tau)$ result and how materials are classified by resistivity are set up in Resistivity of Materials.

Figure 2 · the τ-versus-n tug of war METAL n constant τ ↓ with T ρ ↑ (α > 0) SEMICONDUCTOR n ↑↑ strongly with T τ ↓ with T ρ ↓ (α < 0)

In $\rho = m/(ne^2\tau)$ both $n$ and $\tau$ live in the denominator. In a metal $n$ is frozen so the falling $\tau$ raises $\rho$; in a semiconductor the surging $n$ overwhelms the falling $\tau$ and $\rho$ drops.

Semiconductors and Insulators: Negative α

For insulators and semiconductors the story changes because the carrier density $n$ is itself strongly temperature-dependent. As temperature rises, $n$ increases — more electrons gain enough thermal energy to become free to conduct. This increase more than compensates any decrease in $\tau$, so in $\rho = m/(ne^2\tau)$ the resistivity decreases with temperature. The temperature coefficient is therefore negative, and the resistivity of semiconductors such as silicon and germanium falls as they warm up — the opposite of metallic behaviour.

Figure 3 · ρ–T for a typical semiconductor Temperature T → ρ_T → ρ falls (α < 0)

For a semiconductor, rising temperature frees many more carriers, so resistivity drops sharply — the curve falls from left to right.

NEET Trap

Don't blur "resistivity rises" across all materials

The reflex "heating increases resistance" is true only for conductors. As temperature rises, resistance increases for metals but decreases for semiconductors and insulators. The driver is which quantity changes: in metals $\tau$ falls (with $n$ fixed); in semiconductors $n$ rises and dominates.

Metal → positive α (ρ ↑). Semiconductor / insulator → negative α (ρ ↓).

Alloys: Near-Zero α

Some materials behave almost indifferently to temperature. Nichrome — an alloy of nickel, iron and chromium — shows a very weak dependence of resistivity on temperature, and manganin and constantan share this property. Their temperature coefficient is vanishingly small (of the order of $10^{-6}\ \mathrm{{}^{\circ}C^{-1}}$) while their resistivity is comparatively high.

That combination is precisely what a wire-bound standard resistor needs: a stable, well-defined resistance that barely drifts as the wire warms during use. This is why these alloys, and not pure metals, are chosen for standard resistance coils.

It helps to read the alloy case through the same $\rho = m/(ne^2\tau)$ lens. An alloy is still metallic, so its carrier density $n$ stays essentially fixed with temperature; the disorder of the mixed lattice already scatters electrons so strongly that the additional scattering introduced by heating is a small fractional change. The relaxation time $\tau$ therefore varies only weakly, $\rho$ barely moves, and $\alpha$ comes out tiny. The high baseline resistivity and the near-flat response are two faces of the same heavily-disordered structure.

Figure 4 · ρ–T comparison for the three classes Temperature T → ρ_T → metal (α > 0) alloy (α ≈ 0) semiconductor (α < 0)

The three signatures side by side: a rising metal line, a near-flat alloy line, and a falling semiconductor curve.

Superconductivity

Studying resistivity at very low temperatures led to a striking discovery: certain metals and alloys lose their resistivity completely below a characteristic transition (critical) temperature $T_c$ that is specific to each material. Below $T_c$ the resistivity becomes effectively zero ($\rho \to 0$), and a current once set up in such a material persists indefinitely without any external source to maintain it. These materials are called superconductors. Developing materials that superconduct nearer to room temperature is an active and consequential field of research, with applications such as energy-efficient electromagnets for magnetic levitation.

Worked Example · platinum resistance

The resistance of a platinum wire is $2\ \Omega$ at $0\ \mathrm{{}^{\circ}C}$ and $6.8\ \Omega$ at $80\ \mathrm{{}^{\circ}C}$. Find its temperature coefficient of resistance.

Use $R_T = R_0(1 + \alpha T)$ with $T_0 = 0\ \mathrm{{}^{\circ}C}$, so $6.8 = 2[1 + \alpha(80)]$. Then $\dfrac{6.8}{2} - 1 = 80\alpha$, giving $\dfrac{3.4 - 1}{80} = \dfrac{2.4}{80} = 0.03$. Hence $\alpha = 3\times10^{-2}\ \mathrm{{}^{\circ}C^{-1}}$. (NEET 2023.)

Quick Recap

Temperature dependence of resistivity in one screen

  • Linear law: $\rho_T = \rho_0[1 + \alpha(T - T_0)]$, equivalently $R_T = R_0[1 + \alpha\,\Delta T]$.
  • $\alpha$ = fractional change in resistivity per unit temperature rise; unit $\mathrm{K^{-1}}$ (or per °C).
  • Origin equation: $\rho = m/(ne^2\tau)$ — $\rho$ depends inversely on $n$ and $\tau$.
  • Metals: $n$ fixed, $\tau$ falls with T ⇒ $\rho$ rises ⇒ positive $\alpha$.
  • Semiconductors / insulators: $n$ rises with T and dominates ⇒ $\rho$ falls ⇒ negative $\alpha$.
  • Alloys (manganin, constantan, nichrome): tiny $\alpha$ ⇒ used for standard resistors.
  • Below the transition temperature $T_c$, superconductors have $\rho \to 0$.
  • The linear law is only an approximation over a limited range; it bends at very low T.

NEET PYQ Snapshot — Temperature Dependence of Resistivity

Recent NEET questions testing the sign of α and the linear resistance law.

NEET 2022

As the temperature increases, the electrical resistance

  1. Decreases for both conductors and semiconductors
  2. Increases for conductors but decreases for semiconductors
  3. Decreases for conductors but increases for semiconductors
  4. Increases for both conductors and semiconductors
Answer: (2)

For a conductor the resistivity (and hence resistance) increases with temperature, while for a semiconductor it decreases — the carrier density $n$ rises and dominates.

NEET 2023

The resistance of a platinum wire at 0 °C is 2 Ω and 6.8 Ω at 80 °C. The temperature coefficient of resistance of the wire is

  1. $3 \times 10^{-1}\ \mathrm{{}^{\circ}C^{-1}}$
  2. $3 \times 10^{-4}\ \mathrm{{}^{\circ}C^{-1}}$
  3. $3 \times 10^{-3}\ \mathrm{{}^{\circ}C^{-1}}$
  4. $3 \times 10^{-2}\ \mathrm{{}^{\circ}C^{-1}}$
Answer: (4)

$R = R_0(1 + \alpha T)$: $6.8 = 2[1 + \alpha(80)]$, so $\alpha = \dfrac{2.4}{80} = 0.03 = 3\times10^{-2}\ \mathrm{{}^{\circ}C^{-1}}$.

NEET 2020

The solids which have the negative temperature coefficient of resistance are

  1. insulators only
  2. semiconductors only
  3. insulators and semiconductors
  4. metals
Answer: (3)

In both insulators and semiconductors the carrier density $n$ increases with temperature, lowering $\rho$ — a negative α. Metals have positive α.

FAQs — Temperature Dependence of Resistivity

The points NEET aspirants most often need to nail down.

Why does the resistivity of a metal increase with temperature?
From $\rho = m/(ne^2\tau)$, a metal's free-electron number $n$ is essentially independent of temperature. As temperature rises, lattice ions vibrate more vigorously, the average speed of the electrons increases, collisions become more frequent, and the relaxation time $\tau$ falls. With $n$ fixed and $\tau$ decreasing, $\rho$ increases. This gives metals a positive temperature coefficient of resistivity.
Why do semiconductors and insulators have a negative temperature coefficient of resistivity?
In semiconductors and insulators the number density $n$ of charge carriers increases sharply with temperature as more electrons gain enough energy to become free. This rise in $n$ more than compensates the decrease in relaxation time $\tau$, so $\rho = m/(ne^2\tau)$ decreases as temperature rises. The temperature coefficient α is therefore negative.
What is the temperature coefficient of resistivity and what is its unit?
The temperature coefficient of resistivity α is defined through $\rho_T = \rho_0[1 + \alpha(T - T_0)]$ as the fractional increase in resistivity per unit increase in temperature. From this relation the dimension of α is $(\text{temperature})^{-1}$, so its SI unit is $\mathrm{K^{-1}}$ (equivalently per °C, since a temperature difference is the same on both scales).
Why are manganin and constantan used for standard resistors?
Alloys such as manganin, constantan and nichrome have a very small (nearly negligible) temperature coefficient of resistivity together with a relatively high resistivity. Their resistance therefore changes very little with temperature, which is exactly the property needed for wire-bound standard resistors whose value must stay stable as they warm up.
Is the linear law ρ_T = ρ₀[1 + α(T − T₀)] valid at all temperatures?
No. For a metallic conductor the linear relation holds only over a limited range of temperature around the reference temperature $T_0$. At temperatures much lower than 0 °C the graph of $\rho_T$ against $T$ deviates considerably from a straight line, so the linear approximation should be applied only in a range where the ρ–T graph is effectively straight.
What is superconductivity?
Certain metals and alloys lose their resistivity completely below a characteristic transition (critical) temperature $T_c$; below $T_c$ the resistivity becomes effectively zero and a current once set up persists without any external source. Such materials are called superconductors, and developing materials that superconduct nearer room temperature is an active area of research.