The three rules at a glance
An atom in its ground state is the lowest-energy arrangement of its electrons. Reaching that arrangement is not guesswork — it follows a fixed procedure. The filling of electrons into the orbitals of different atoms takes place according to the Aufbau principle, which is itself built on the Pauli exclusion principle, Hund's rule of maximum multiplicity, and the relative energies of the orbitals. Each rule answers a different question, and only when all three act together does a unique configuration emerge.
It helps to keep the division of labour straight before the detail arrives. Aufbau fixes the order in which orbitals are filled; Pauli fixes the capacity of each orbital and subshell; Hund fixes how electrons distribute within a set of equal-energy orbitals.
| Rule | Governs | One-line statement |
|---|---|---|
| Aufbau principle | Order of filling | Orbitals fill in order of increasing energy; lowest available orbital first. |
| Pauli exclusion | Capacity per orbital | No two electrons share all four quantum numbers; max two per orbital, opposite spins. |
| Hund's rule | Distribution within a subshell | Each degenerate orbital gets one electron before any pairing begins; singles stay parallel. |
The Aufbau principle and the (n+l) rule
The word aufbau is German for "building up." The building up of orbitals means the filling up of orbitals with electrons. The principle states that in the ground state of the atoms, the orbitals are filled in order of their increasing energies — electrons first occupy the lowest energy orbital available to them and enter higher energy orbitals only after the lower ones are filled.
That immediately raises a question: how do we rank orbital energies? In a multi-electron atom the energy of an orbital depends on both the principal quantum number $n$ and the azimuthal quantum number $l$, because electrons in different orbitals experience different effective nuclear charge through shielding. The exact dependence is complicated, but one simple rule captures it for examination purposes — the (n+l) rule:
The lower the value of $(n+l)$ for an orbital, the lower is its energy. If two orbitals have the same value of $(n+l)$, the orbital with the lower value of $n$ has the lower energy.
Worked across the early orbitals, the $(n+l)$ values explain the famous "out of sequence" filling. The case that confuses most students is 4s versus 3d: even though 3d carries the smaller principal quantum number, 4s is filled first.
| Orbital | n | l | (n + l) | Filled before |
|---|---|---|---|---|
1s | 1 | 0 | 1 | 2s |
2s | 2 | 0 | 2 | 2p |
2p | 2 | 1 | 3 | 3s (lower n wins the tie) |
3s | 3 | 0 | 3 | 3p |
3p | 3 | 1 | 4 | 4s (lower n wins the tie) |
4s | 4 | 0 | 4 | 3d |
3d | 3 | 2 | 5 | 4p (lower n wins the tie) |
4p | 4 | 1 | 5 | 5s |
5s | 5 | 0 | 5 | 4d |
4d | 4 | 2 | 6 | 5p |
Reading the table, $4s$ has $(n+l)=4+0=4$ while $3d$ has $(n+l)=3+2=5$, so $4s$ is the lower-energy orbital and fills first. This is exactly why the valence electron of potassium, given a choice between 3d and 4s, is found in 4s. The tie cases — 2p versus 3s, 3p versus 4s, 3d versus 4p — are all settled by the second clause of the rule: when $(n+l)$ matches, lower $n$ wins.
Order of filling and the diagonal diagram
Applying the $(n+l)$ rule to every orbital produces a single useful sequence that NCERT recommends committing to memory:
$1s,\ 2s,\ 2p,\ 3s,\ 3p,\ 4s,\ 3d,\ 4p,\ 5s,\ 4d,\ 5p,\ 6s,\ 4f,\ 5d,\ 6p,\ 7s\ \dots$
Rather than re-derive every $(n+l)$ value in the exam hall, the order is read off a diagonal diagram. The subshells are written in rows by shell, and parallel arrows are drawn through them from top-right to bottom-left; following the arrows in turn gives the filling sequence.
NCERT is careful to caution that there is no single ordering of orbital energies that is universally correct for every atom. The sequence above is an extremely useful guide, but in many cases orbitals are close in energy and small changes in atomic structure can alter the order of filling. Exceptions, as the chromium and copper cases below show, do occur.
The (n+l) rule rests entirely on what n and l mean. If the four quantum numbers feel shaky, revisit Quantum Numbers before going further.
The Pauli exclusion principle
Aufbau tells us which orbital to fill next, but not how many electrons that orbital can hold. That limit comes from the exclusion principle, given by the Austrian scientist Wolfgang Pauli in 1926. According to this principle, no two electrons in an atom can have the same set of four quantum numbers. An equivalent and more usable statement is: only two electrons may exist in the same orbital, and these electrons must have opposite spin.
The reasoning is direct. An orbital is fixed by a single set of $n$, $l$ and $m_l$. Two electrons sharing that orbital therefore already agree on three of the four quantum numbers, so to remain distinct they must differ in the fourth — the spin quantum number $m_s$, taking $+\tfrac{1}{2}$ and $-\tfrac{1}{2}$. A third electron would be forced to repeat a complete set, which the principle forbids.
This restriction is what hands every subshell its capacity. Since the 1s subshell comprises one orbital, it holds at most two electrons; the p and d subshells, with three and five orbitals, hold a maximum of 6 and 10 respectively. In general the maximum number of electrons in the shell with principal quantum number $n$ is $2n^2$.
| Subshell | l | Orbitals | Max electrons |
|---|---|---|---|
s | 0 | 1 | 2 |
p | 1 | 3 | 6 |
d | 2 | 5 | 10 |
f | 3 | 7 | 14 |
"Same orbital" still means a difference
A 2016 NEET item asked how two electrons occupying the same orbital are distinguished. The answer is the spin quantum number — not the magnetic, azimuthal or principal quantum number, all of which the two electrons share. Two electrons in one orbital are identical in $n$, $l$ and $m_l$; only $m_s$ tells them apart.
Same orbital ⇒ same n, l, ml; the distinguishing label is ms (spin).
Hund's rule of maximum multiplicity
Pauli caps an orbital at two electrons, but when a subshell has several orbitals of equal energy — degenerate orbitals such as the three p, five d or seven f orbitals — a further question arises: do incoming electrons pair up in one orbital, or spread out singly? Hund's rule of maximum multiplicity settles this. It states that pairing of electrons in the orbitals belonging to the same subshell does not take place until each orbital belonging to that subshell has got one electron each, i.e. is singly occupied. The single electrons keep parallel spins as far as possible.
A useful consequence follows directly. Since there are three p, five d and seven f orbitals, pairing begins with the entry of the 4th, 6th and 8th electron into the p, d and f subshells respectively. Before those electrons arrive, every orbital of the subshell holds a single, parallel-spin electron.
Nitrogen's configuration is not 2px12py12pz1 with mixed spins
A 2018 NEET item flagged "the electronic configuration of N atom is $1s^2\,2s^2\,2p_x^1\,2p_y^1\,2p_z^1$" as the wrong statement — not because the orbital occupancy is wrong, but because in degenerate orbitals all unpaired electrons must show the same (parallel) spin. The occupancy is right; the implied spin pairing is the error Hund's rule rules out.
In a degenerate set, single electrons occupy separate orbitals with parallel spins — never paired prematurely.
Orbital diagrams in practice
Electronic configuration can be written two ways: the $s^a p^b d^c$ notation, or the orbital (box-and-arrow) diagram in which each orbital is a box and each electron an arrow — up arrow for one spin, down arrow for the opposite. The orbital diagram is more informative because the arrows display all four quantum numbers, spin included. Nitrogen and oxygen show Hund's rule cleanly: nitrogen ($1s^2\,2s^2\,2p^3$) keeps its three 2p electrons in separate boxes with parallel spin, while oxygen's fourth 2p electron is forced to pair.
| N (Z = 7) 1s² 2s² 2p³ |
1s
↑↓
2s
↑↓
2p
↑↑↑
|
| O (Z = 8) 1s² 2s² 2p⁴ |
1s
↑↓
2s
↑↓
2p
↑↓↑↑
|
How many unpaired electrons are present in ground-state oxygen, and which rule fixes the answer?
Oxygen ($Z=8$) has the configuration $1s^2\,2s^2\,2p^4$. By Hund's rule, the first three 2p electrons singly occupy the three 2p orbitals; the fourth must pair with one of them. That leaves two singly occupied 2p orbitals, so oxygen has two unpaired electrons. Hund's rule fixes the distribution; Pauli ensures the paired electrons in the doubly-filled 2p orbital carry opposite spin.
Half-filled and fully-filled stability
Hund's rule already hints at something deeper: a set of degenerate orbitals that is exactly half-filled or completely filled carries extra stability. The ground-state configuration of an atom always corresponds to the state of lowest total electronic energy, and NCERT identifies two physical reasons why $p^3$, $p^6$, $d^5$, $d^{10}$, $f^7$ and $f^{14}$ sets sit at unusually low energy.
| Cause | Why it lowers the energy |
|---|---|
| Symmetrical distribution | Half-filled and completely filled subshells have a symmetrical distribution of electrons. Electrons in the same subshell have equal energy but different spatial distribution, so they shield one another relatively little and are held more strongly by the nucleus. |
| Exchange energy | Whenever two or more electrons with the same spin occupy degenerate orbitals, they can exchange positions, releasing exchange energy. The number of possible exchanges is maximum when the subshell is exactly half-filled or completely filled — so the exchange energy, and the stability, is greatest there. |
The exchange energy is, in fact, the underlying basis of Hund's rule itself — electrons that enter orbitals of equal energy adopt parallel spins as far as possible precisely because doing so maximises the number of exchanges. The extra stability of half-filled and completely filled subshells is therefore due to relatively small shielding, smaller coulombic repulsion energy, and larger exchange energy.
The chromium and copper anomaly
The clearest payoff of half-filled and fully-filled stability appears in the first transition series. Working through scandium to zinc, the five 3d orbitals fill progressively — but chromium and copper break the simple pattern. Their position would suggest $3d^4\,4s^2$ and $3d^9\,4s^2$, yet they are actually $3d^5\,4s^1$ and $3d^{10}\,4s^1$.
The explanation is exactly the stability argument above. In these atoms the 4s and 3d subshells differ only slightly in energy, so an electron shifts from the lower-energy 4s to the higher-energy 3d when that shift leaves the 3d subshell either exactly half-filled or completely filled. Chromium gains a half-filled $3d^5$ alongside a half-filled $4s^1$; copper gains a completely filled $3d^{10}$ alongside a half-filled $4s^1$.
| Cr (Z = 24) [Ar] 3d⁵ 4s¹ |
3d
↑↑↑↑↑
4s
↑
|
| Cu (Z = 29) [Ar] 3d¹⁰ 4s¹ |
3d
↑↓↑↓↑↓↑↓↑↓
4s
↑
|
Memorise Cr and Cu, then count unpaired electrons carefully
The two exceptions every NEET candidate must know cold: chromium is $\ce{[Ar]}\,3d^5\,4s^1$ (not $3d^4\,4s^2$) and copper is $\ce{[Ar]}\,3d^{10}\,4s^1$ (not $3d^9\,4s^2$). Errors usually appear when counting unpaired electrons: Cr has 6 unpaired electrons (five in 3d plus one in 4s), whereas Cu has only 1 (the lone 4s electron, since 3d is fully paired).
Cr: 3d⁵4s¹ → 6 unpaired. Cu: 3d¹⁰4s¹ → 1 unpaired. NCERT itself adds the caution that further exceptions do exist.
One important caveat keeps these anomalies in proportion. NCERT writes its own warning beside the chromium and copper cases — "caution: exceptions do exist" — because the half-filled and fully-filled stability argument is a guideline, not an inviolable law. It accounts neatly for Cr and Cu in the 3d series, and similar effects appear among the heavier transition and inner-transition metals, but the diagonal Aufbau order remains the default starting point for every atom.
Aufbau, Pauli, Hund's Rules
- Aufbau principle: in the ground state, orbitals fill in order of increasing energy — lowest available orbital first.
- (n+l) rule: lower $(n+l)$ means lower energy; for equal $(n+l)$, lower $n$ fills first. This puts 4s ($n+l=4$) before 3d ($n+l=5$).
- Filling order: $1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s$, read off the diagonal diagram.
- Pauli exclusion: no two electrons share all four quantum numbers; max two per orbital with opposite spins; shell capacity $=2n^2$.
- Hund's rule: each degenerate orbital takes one parallel-spin electron before any pairing; p, d and f pairing starts at the 4th, 6th and 8th electron.
- Stability: half-filled and fully-filled sets ($p^3,p^6,d^5,d^{10},f^7,f^{14}$) are extra-stable from symmetry and exchange energy — giving Cr $= 3d^5 4s^1$ and Cu $= 3d^{10}4s^1$.