Chemistry · Salt Analysis

Anion Tests — Dilute Acid Group

Five anions — carbonate, sulphide, sulphite, nitrite and acetate — announce themselves the instant dilute sulphuric acid touches the salt, each releasing a gas you can see or smell. This is Step I of anion analysis in the NCERT Laboratory Manual (Unit 7, Experiment 7.1), and it is the fastest, highest-yield screen in the entire scheme. Master the gas, the smell and the one confirmatory reaction for each, and a large slice of salt-analysis questions becomes routine.

Why a Dilute Acid Group

Qualitative analysis works through reactions that the senses can register directly — a precipitate forming, a colour changing, or a gas escaping. The dilute acid anion group is built entirely on that third signal. When a salt of carbonate, sulphide, sulphite, nitrite or acetate is treated with dilute sulphuric acid (dilute HCl serves the same purpose), the weak conjugate acid that forms is unstable and breaks down, liberating a characteristic gas at room temperature or on gentle warming.

Because all five respond to one reagent, the dilute acid test is the very first wet test performed on the salt, before any confirmatory chemistry. The NCERT manual is explicit that preliminary tests with dilute H₂SO₄ — alongside the later concentrated acid test — give a good early indication of the acid radical present and should always precede confirmatory work. Anions that resist dilute acid (sulphate, phosphate, the halides, borate) are deliberately left for the concentrated acid group and the sulphate–phosphate–borate tests.

AnionGas evolvedSmellQuick field signal
Carbonate, $\ce{CO3^2-}$$\ce{CO2}$OdourlessBrisk effervescence; lime water milky
Sulphide, $\ce{S^2-}$$\ce{H2S}$Rotten eggsLead acetate paper turns black
Sulphite, $\ce{SO3^2-}$$\ce{SO2}$Pungent, burning sulphurAcidified $\ce{K2Cr2O7}$ paper turns green
Nitrite, $\ce{NO2^-}$$\ce{NO2}$PungentBrown fumes; KI–starch paper blue
Acetate, $\ce{CH3COO^-}$$\ce{CH3COOH}$ vapoursVinegarNeutral $\ce{FeCl3}$ gives blood-red colour

The Gas-Evolution Test Setup

The procedure is fixed: take about 0.1 g of the salt in a test tube, add 1–2 mL of dilute sulphuric acid, and observe at room temperature. If nothing escapes, warm the tube gently. Any gas that comes off is then led through a delivery tube to the appropriate detector — lime water, lead acetate paper, dichromate paper or KI–starch paper — exactly as in Fig. 7.1 of the manual. The apparatus below is the standard arrangement.

Figure 1 · Apparatus salt + dil. H₂SO₄ gas → detector DETECTORS lime water → CO₂/SO₂ Pb-acetate → H₂S K₂Cr₂O₇ → SO₂ KI–starch → NO₂

A cork-and-delivery-tube assembly carries the evolved gas from the reaction tube into a separate detector tube or onto a moistened test paper, so the gas can be identified without contamination from the acid mixture.

Carbonate — CO₃²⁻

Carbonate is the most conspicuous member of the group. Adding dilute H₂SO₄ to a carbonate produces brisk effervescence of a colourless, odourless gas. Passing that gas through lime water turns it milky because insoluble calcium carbonate precipitates.

$$\ce{Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2 ^}$$

$$\ce{Ca(OH)2 + CO2 -> CaCO3 v + H2O}$$

A subtle confirmatory cue: if CO₂ is bubbled in excess, the milkiness disappears as the insoluble carbonate redissolves to soluble calcium hydrogen carbonate. This reversal is itself diagnostic of CO₂.

$$\ce{CaCO3 + CO2 + H2O -> Ca(HCO3)2}$$

Confirmation of carbonate uses the solid salt or its aqueous solution directly — never a sodium carbonate extract, which would itself carry carbonate ions and give a false positive.

Sulphide — S²⁻

With warm dilute H₂SO₄ a sulphide gives hydrogen sulphide, a colourless gas with the unmistakable smell of rotten eggs. Held over the mouth of the tube, a strip of filter paper moistened with lead acetate turns black as black lead sulphide forms.

$$\ce{Na2S + H2SO4 -> Na2SO4 + H2S ^}$$

$$\ce{(CH3COO)2Pb + H2S -> PbS v + 2CH3COOH}$$

The confirmatory wet test is the sodium nitroprusside test. Make the salt solution alkaline with ammonium hydroxide (or use the sodium carbonate extract for water-insoluble salts) and add a drop of sodium nitroprusside: a purple to violet colour appears from the complex formed.

$$\ce{Na2S + Na2[Fe(CN)5NO] -> Na4[Fe(CN)5NOS]}$$

NEET Trap

H₂S smell is not enough — confirm it

Candidates often stop at "rotten-egg smell = sulphide." NEET stems frequently pair the gas with a detector. The lead acetate paper turning black (PbS) and the sodium nitroprusside giving purple/violet are the diagnostic endpoints — memorise the colours, not just the smell.

Rule: H₂S → black on lead acetate paper; purple with sodium nitroprusside.

Sulphite — SO₃²⁻

On warming with dilute H₂SO₄ a sulphite evolves sulphur dioxide — suffocating, pungent, with the smell of burning sulphur. SO₂ is a reducing gas, and its reducing action drives both confirmatory tests.

$$\ce{Na2SO3 + H2SO4 -> Na2SO4 + H2O + SO2 ^}$$

SO₂ turns paper moistened with acidified potassium dichromate green by reducing chromium(VI) to chromium(III):

$$\ce{K2Cr2O7 + H2SO4 + 3SO2 -> K2SO4 + Cr2(SO4)3 + H2O}$$

With barium chloride, a sulphite solution gives a white precipitate of barium sulphite that dissolves in dilute HCl, re-evolving SO₂; the same precipitate decolourises acidified potassium permanganate, again through reduction.

$$\ce{Na2SO3 + BaCl2 -> 2NaCl + BaSO3 v}$$

$$\ce{BaSO3 + 2HCl -> BaCl2 + H2O + SO2 ^}$$

$$\ce{2KMnO4 + 5SO2 + 2H2O -> K2SO4 + 2MnSO4 + 2H2SO4}$$

Build the foundation

New to the gas-test logic? Start with the preliminary tests overview, then return here for the dilute acid group in depth.

Nitrite — NO₂⁻

A nitrite warmed with dilute H₂SO₄ gives reddish-brown fumes of NO₂. The chemistry runs through unstable nitrous acid, which disproportionates; the colourless NO formed is oxidised by air to the brown NO₂.

$$\ce{2NaNO2 + H2SO4 -> Na2SO4 + 2HNO2}$$

$$\ce{3HNO2 -> HNO3 + 2NO ^ + H2O}$$

$$\ce{2NO + O2 -> 2NO2 ^}$$

The classic detector is potassium iodide–starch paper acidified with acetic acid. Nitrous acid liberates iodine, which strikes the deep blue starch–iodine complex.

$$\ce{2HNO2 + 2KI + 2CH3COOH -> 2CH3COOK + 2H2O + 2NO + I2}$$

The Griess–Ilosvay test is the formal confirmation: in a very dilute, acetic-acid-acidified solution, sulphanilic acid is diazotised by the nitrous acid and couples with 1-naphthylamine to give a red azo-dye. The manual stresses the solution must be dilute, since concentrated solutions stall at diazotisation.

Acetate — CH₃COO⁻

Acetate betrays itself by the smell of vinegar when treated with dilute H₂SO₄, as acetic acid vapours escape and turn blue litmus red. Two confirmatory tests seal the identification.

Ester (fruity-odour) test

Heat the salt with ethanol and a few drops of concentrated H₂SO₄. Acetic acid esterifies to ethyl acetate, whose fruity odour confirms acetate.

$$\ce{2CH3COONa + H2SO4 -> Na2SO4 + 2CH3COOH}$$

$$\ce{CH3COOH + C2H5OH ->[H2SO4] CH3COOC2H5 + H2O}$$

Neutral ferric chloride test

Add neutral ferric chloride to the salt solution: a deep blood-red colour appears from an iron(III)–acetate complex, which on boiling decomposes to a brown-red precipitate of iron(III) dihydroxyacetate.

$$\ce{6CH3COO^- + 3Fe^3+ + 2H2O -> [Fe3(OH)2(CH3COO)6]^+ + 2H+}$$

$$\ce{[Fe3(OH)2(CH3COO)6]^+ + 4H2O ->[\Delta] 3[Fe(OH)2(CH3COO)] v + 3CH3COOH + H+}$$

NEET Trap

"Neutral" ferric chloride is mandatory

Plain $\ce{FeCl3}$ solution is acidic due to hydrolysis, and acid suppresses the blood-red colour. The reagent is neutralised by adding dilute NaOH dropwise until a faint permanent $\ce{Fe(OH)3}$ precipitate forms, then filtering. Examiners test whether you know why neutralisation is required.

Rule: acetate → blood-red with neutral $\ce{FeCl3}$; brown-red ppt on boiling.

Carbonate vs Sulphite vs Bicarbonate

Three close confusions trip students. CO₂ and SO₂ both turn lime water milky, so milkiness alone cannot separate carbonate from sulphite. The split is by smell — CO₂ is odourless, SO₂ is pungent — reinforced by the dichromate test, which only SO₂ (a reducing gas) passes by turning the paper green.

Carbonate vs bicarbonate is the second pair. Both effervesce with dilute acid to give CO₂, but a normal carbonate gives a precipitate with magnesium sulphate in the cold, whereas a bicarbonate does not until the solution is boiled. The dilute acid gas test cannot tell them apart on its own.

PropertyCarbonate $\ce{CO3^2-}$Sulphite $\ce{SO3^2-}$Bicarbonate $\ce{HCO3^-}$
Gas with dil. H₂SO₄$\ce{CO2}$$\ce{SO2}$$\ce{CO2}$
Smell of gasOdourlessPungent (burning sulphur)Odourless
Lime waterMilkyMilkyMilky
Acidified $\ce{K2Cr2O7}$No changeTurns greenNo change
$\ce{MgSO4}$ (cold)White pptNo ppt until boiled

Anion Decision Map

The whole group reduces to a short decision tree driven by what the nose and eye report first, then a single confirming detector. The schematic below condenses the routing.

Figure 2 · Decision map salt + dil. H₂SO₄ → gas? Odourless lime water milky CO₃²⁻ Rotten eggs Pb-acetate black S²⁻ Pungent SO₂ Cr₂O₇²⁻ green SO₃²⁻ Brown fumes KI–starch blue NO₂⁻ Vinegar neutral FeCl₃ red CH₃COO⁻ → then run the one confirmatory test CO₃²⁻: excess CO₂ clears milkiness (Ca(HCO₃)₂) S²⁻: sodium nitroprusside → purple/violet SO₃²⁻: BaSO₃ ppt decolourises acidified KMnO₄ NO₂⁻: Griess–Ilosvay → red azo-dye CH₃COO⁻: ethanol + conc. H₂SO₄ → fruity ester

First read the gas by sight and smell, route to the anion, then commit to the single confirmatory reaction that closes the case.

Observation → Inference Table

The lab-manual record sheet pairs each observation with its inference. This is the format examiners reproduce in match-the-column and assertion–reason items, so internalise the exact wording.

Observation with dilute H₂SO₄Gas / vapourInference (anion)Confirmatory test
Brisk effervescence; colourless, odourless gas turns lime water milky$\ce{CO2}$CarbonateExcess CO₂ removes the milkiness
Colourless gas, rotten-egg smell, blackens lead acetate paper$\ce{H2S}$SulphideSodium nitroprusside → purple/violet
Pungent gas, burning-sulphur smell, turns acidified $\ce{K2Cr2O7}$ green$\ce{SO2}$SulphiteDecolourises acidified $\ce{KMnO4}$
Reddish-brown fumes; turn acidified KI–starch paper blue$\ce{NO2}$NitriteGriess–Ilosvay → red azo-dye
Colourless vapours, smell of vinegar; turn blue litmus red$\ce{CH3COOH}$AcetateNeutral $\ce{FeCl3}$ → blood-red colour
Quick Recap

The dilute acid anion group in one screen

  • Five anions — $\ce{CO3^2-}$, $\ce{S^2-}$, $\ce{SO3^2-}$, $\ce{NO2^-}$, $\ce{CH3COO^-}$ — evolve a gas with dilute H₂SO₄; this is Step I of anion analysis.
  • $\ce{CO2}$ (odourless) and $\ce{SO2}$ (pungent) both cloud lime water; separate them by smell and the dichromate-green test.
  • $\ce{H2S}$ blackens lead acetate paper and gives purple sodium nitroprusside; brown $\ce{NO2}$ turns KI–starch blue.
  • Acetate smells of vinegar; confirm by the fruity ester test and the blood-red colour with neutral ferric chloride.
  • Excess CO₂ clears lime-water milkiness via $\ce{Ca(HCO3)2}$ — a confirmatory cue, not a weakness of the test.

NEET PYQ Snapshot — Anion Tests (Dilute Acid Group)

NEET salt-analysis items so far have targeted cation grouping; the dilute acid anion tests are tested as concept-level lab-manual recall. Practise with these grounded concept cards.

Concept

A colourless salt gives a colourless, odourless gas with dilute H₂SO₄ that turns lime water milky; the milkiness vanishes when the gas is passed in excess. The anion is:

  • (1) Sulphite
  • (2) Carbonate
  • (3) Nitrite
  • (4) Acetate
Answer: (2) Carbonate

Odourless gas + lime water milky points to CO₂; excess CO₂ redissolves CaCO₃ as Ca(HCO₃)₂, removing the milkiness. SO₂ would also cloud lime water but is pungent.

Concept

Which observation specifically distinguishes a sulphite from a carbonate, given that both turn lime water milky?

  • (1) Brisk effervescence with dilute acid
  • (2) Pungent gas turning acidified K₂Cr₂O₇ paper green
  • (3) White precipitate with BaCl₂
  • (4) Gas turns blue litmus red
Answer: (2)

SO₂ is a reducing gas: it reduces Cr(VI) to green Cr(III). CO₂ does not. Both can give effervescence and BaCl₂ precipitates, so those are not distinguishing.

Concept

An acetate salt gives a blood-red colour with neutral ferric chloride. The reagent must be neutral because:

  • (1) Acid hydrolyses acetate to acetic acid
  • (2) Acid present in ordinary FeCl₃ suppresses the iron–acetate complex
  • (3) Neutral FeCl₃ is more concentrated
  • (4) Acetate reacts only in basic medium
Answer: (2)

Ordinary FeCl₃ is acidic from hydrolysis; the acid prevents formation of the red [Fe₃(OH)₂(CH₃COO)₆]⁺ complex. Neutralising with dilute NaOH (faint Fe(OH)₃ ppt, then filter) restores the diagnostic red colour.

FAQs — Anion Tests (Dilute Acid Group)

Common doubts on the carbonate, sulphide, sulphite, nitrite and acetate gas tests.

Why is dilute sulphuric acid used as the first reagent for anion detection?

Carbonate, sulphide, sulphite, nitrite and acetate all react with dilute sulphuric acid at room temperature or on gentle warming to release a characteristic gas. Because these reactions are perceptible to sight and smell, a single dilute acid test screens for an entire family of anions in one step before any confirmatory work begins. Dilute HCl can be used similarly, but dilute H2SO4 is the NCERT lab manual standard.

How do you distinguish CO2 from SO2 when both turn lime water milky?

Both gases turn lime water milky, so milkiness alone is not decisive. CO2 is colourless and completely odourless, whereas SO2 has a sharp pungent smell of burning sulphur. SO2 also turns acidified potassium dichromate paper green and decolourises acidified potassium permanganate, while CO2 does neither. Smell and the dichromate test together separate the two.

What is the confirmatory test for the sulphide ion?

Warm dilute H2SO4 on a sulphide releases H2S with a rotten-egg smell that blackens lead acetate paper through formation of black PbS. The confirmatory wet test uses sodium nitroprusside: the alkaline salt solution or sodium carbonate extract gives a purple to violet colour due to the complex Na4[Fe(CN)5NOS].

How is acetate confirmed after the vinegar smell appears?

Two confirmatory tests are used. The ester (fruity-odour) test heats the salt with ethanol and a little concentrated H2SO4 to form ethyl acetate, which smells fruity. The neutral ferric chloride test gives a deep blood-red colour with the salt solution that turns brown-red and forms a precipitate of iron(III) dihydroxyacetate on boiling.

Why must the ferric chloride used for the acetate test be neutral?

Ordinary ferric chloride solution is acidic because of partial hydrolysis. Acid suppresses the deep red iron-acetate complex and can give a misleading colour. Neutral ferric chloride is prepared by adding dilute NaOH dropwise until a faint permanent precipitate of ferric hydroxide forms, then filtering and using the filtrate, so the blood-red colour is genuinely diagnostic of acetate.

What gas confirms nitrite in the dilute acid test and how is it tested?

On warming a nitrite with dilute H2SO4, brown fumes of NO2 are evolved. The gas turns acidified potassium iodide-starch paper blue because liberated iodine forms a blue complex with starch. The Griess-Ilosvay test, using sulphanilic acid and 1-naphthylamine in a very dilute solution, gives a red azo-dye as further confirmation.