Allotropes of phosphorus: white, red and black
Phosphorus is found in several allotropic forms, the important ones being white, red and black. They share the same element but differ sharply in structure, and that difference dictates everything from reactivity to toxicity. White phosphorus is the reactive, strained form; red and black are progressively more polymerised and far more stable.
White phosphorus is a translucent white waxy solid. It is poisonous, insoluble in water but soluble in carbon disulphide, and glows in the dark (chemiluminescence). It dissolves in boiling NaOH solution in an inert atmosphere, giving phosphine:
$$\ce{P4 + 3NaOH + 3H2O -> PH3 + 3NaH2PO2}$$
Structurally, white phosphorus consists of discrete tetrahedral P4 molecules in which the P–P–P bond angles are only 60°. This angular strain makes it less stable and therefore more reactive than the other forms — it readily catches fire in air to give dense white fumes of P4O10:
$$\ce{P4 + 5O2 -> P4O10}$$
Red phosphorus is obtained by heating white phosphorus at 573 K in an inert atmosphere for several days. It possesses an iron-grey lustre, is odourless, non-poisonous and insoluble in water as well as in carbon disulphide, and does not glow in the dark. It is much less reactive than white phosphorus because it is polymeric — consisting of chains of P4 tetrahedra linked together — so the strain of the isolated tetrahedron is relieved.
Black phosphorus, the most stable form, has two varieties. α-Black phosphorus forms when red phosphorus is heated in a sealed tube at 803 K; it can be sublimed in air, has opaque monoclinic or rhombohedral crystals, and does not oxidise in air. β-Black phosphorus is prepared by heating white phosphorus at 473 K under high pressure, and does not burn in air up to 673 K.
| Property | White P | Red P | Black P |
|---|---|---|---|
| Appearance | Translucent white waxy solid | Iron-grey lustre | Opaque crystals (α: monoclinic/rhombohedral) |
| Structure | Discrete tetrahedral P4 (60° angle) | Polymeric chains of linked P4 tetrahedra | Layered / highly polymeric |
| Toxicity | Poisonous | Non-poisonous | Non-poisonous |
| Solubility in CS2 | Soluble | Insoluble | Insoluble |
| Glow in dark | Yes (chemiluminescence) | No | No |
| Reactivity | Most reactive; ignites in air | Much less reactive | Least reactive; α does not oxidise in air |
Reactivity is a structure argument, not a "type" argument
The reason white phosphorus is more reactive than red is the 60° angular strain in the discrete P4 tetrahedron. Red phosphorus is polymeric (chains of linked tetrahedra), which removes that strain. Do not attribute the difference to "different elements" or to electronegativity — both are pure phosphorus.
White P glows in the dark and is poisonous and CS2-soluble; red P does none of these.
Phosphine (PH3): preparation, structure and properties
Phosphine is the hydride of phosphorus, the Group 15 analogue of ammonia. It is prepared by the action of water or dilute HCl on calcium phosphide:
$$\ce{Ca3P2 + 6H2O -> 3Ca(OH)2 + 2PH3}$$
$$\ce{Ca3P2 + 6HCl -> 3CaCl2 + 2PH3}$$
In the laboratory it is prepared by heating white phosphorus with concentrated NaOH solution in an inert atmosphere of CO2, giving phosphine and sodium hypophosphite:
$$\ce{P4 + 3NaOH + 3H2O -> PH3 + 3NaH2PO2}$$
When pure, phosphine is non-inflammable, but it becomes spontaneously inflammable owing to the presence of traces of P2H4 (diphosphine) or P4 vapour. To purify it, the gas is absorbed in HI to form phosphonium iodide (PH4I), which on treatment with KOH gives off pure phosphine:
$$\ce{PH4I + KOH -> KI + H2O + PH3}$$
Phosphine is a colourless gas with a rotten-fish smell and is highly poisonous. It explodes in contact with traces of oxidising agents such as HNO3, Cl2 and Br2 vapours. It is only slightly soluble in water, and its aqueous solution decomposes in the presence of light to give red phosphorus and H2. When PH3 is absorbed in copper sulphate or mercuric chloride solution, the corresponding phosphides are obtained:
$$\ce{3CuSO4 + 2PH3 -> Cu3P2 + 3H2SO4}$$
$$\ce{3HgCl2 + 2PH3 -> Hg3P2 + 6HCl}$$
Basic character of phosphine
Phosphine is weakly basic and, like ammonia, forms phosphonium compounds with acids. The lone pair on phosphorus lets it act as a Lewis base:
$$\ce{PH3 + HBr -> PH4Br}$$
$$\ce{PH3 + HI -> PH4I}$$
The formation of PH4I from PH3 and HI is the standard proof that PH3 is basic. Note, however, that PH3 is a far weaker base than NH3, and the bond angle in PH4+ is greater than in PH3, because in PH4+ the lone pair is now used in bonding and the four bond pairs spread to the regular tetrahedral angle.
PH3 has a lower boiling point than NH3
Unlike NH3, PH3 molecules are not associated through hydrogen bonding in the liquid state, because phosphorus is much less electronegative than nitrogen. With no intermolecular hydrogen bonding, PH3 boils lower than NH3. The general thermal stability of Group 15 hydrides also falls down the group: NH3 > PH3 > AsH3 > SbH3 > BiH3.
"Lower boiling point" is a hydrogen-bonding answer, not a molecular-mass answer.
PH3 vs NH3 is a recurring NEET comparison. Revise the parent hydride alongside the group trends in Group 15: the Nitrogen Family.
Phosphorus halides: PCl3 and PCl5
Phosphorus forms two series of halides, the trihalides PX3 (X = F, Cl, Br, I) and the pentahalides PX5 (X = F, Cl, Br). The two best-studied — and the two NEET asks about — are phosphorus trichloride and phosphorus pentachloride. Both fume in moist air because they hydrolyse, and both are workhorses for converting –OH groups to –Cl.
Phosphorus trichloride, PCl3
PCl3 is obtained by passing dry chlorine over heated white phosphorus, or by the action of thionyl chloride on white phosphorus:
$$\ce{P4 + 6Cl2 -> 4PCl3}$$
$$\ce{P4 + 8SOCl2 -> 4PCl3 + 4SO2 + 2S2Cl2}$$
It is a colourless oily liquid that hydrolyses in moisture, which is why it fumes in damp air (the fumes are HCl):
$$\ce{PCl3 + 3H2O -> H3PO3 + 3HCl}$$
It also reacts with organic compounds containing the –OH group, such as acetic acid and ethanol:
$$\ce{3CH3COOH + PCl3 -> 3CH3COCl + H3PO3}$$
$$\ce{3C2H5OH + PCl3 -> 3C2H5Cl + H3PO3}$$
Its shape is pyramidal with phosphorus sp3 hybridised — three P–Cl bonds and one lone pair, the same geometry family as PH3 and NH3.
Phosphorus pentachloride, PCl5
PCl5 is prepared by the reaction of white phosphorus with an excess of dry chlorine, or by the action of SO2Cl2:
$$\ce{P4 + 10Cl2 -> 4PCl5}$$
$$\ce{P4 + 10SO2Cl2 -> 4PCl5 + 10SO2}$$
It is a yellowish-white powder. In moist air it hydrolyses first to phosphoryl chloride (POCl3) and finally to phosphoric acid:
$$\ce{PCl5 + H2O -> POCl3 + 2HCl}$$
$$\ce{POCl3 + 3H2O -> H3PO4 + 3HCl}$$
On heating it sublimes, but on stronger heating it decomposes back to PCl3 and chlorine:
$$\ce{PCl5 ->[\Delta] PCl3 + Cl2}$$
It converts –OH-bearing organics to chloro-derivatives, and finely divided metals on heating give the corresponding chlorides:
$$\ce{C2H5OH + PCl5 -> C2H5Cl + POCl3 + HCl}$$
$$\ce{2Ag + PCl5 -> 2AgCl + PCl3}$$
The five P–Cl bonds in PCl5 are NOT all equivalent
In the gas and liquid phases PCl5 is trigonal bipyramidal. The three equatorial bonds (202 pm) are equivalent and shorter, while the two axial bonds (240 pm) are longer because the axial bond pairs suffer more repulsion than the equatorial bond pairs. A common distractor claims all five bonds are identical — they are not.
PCl3 → pyramidal, sp3. PCl5 → trigonal bipyramidal, sp3d, two bond lengths.
Oxoacids of phosphorus: the master pattern
Phosphorus forms a large family of oxoacids, and their compositions are interrelated by the loss or gain of a water molecule or an oxygen atom. There is one structural rule that ties them all together: in every oxoacid, phosphorus is tetrahedrally surrounded, and each acid contains at least one P=O bond and at least one P–OH bond.
For acids in which phosphorus has a lower oxidation state (less than +5), there is, in addition to P=O and P–OH, either a P–P bond (e.g. H4P2O6) or a P–H bond (e.g. H3PO2) — but not both. These +3 acids tend to disproportionate to higher and lower oxidation states; orthophosphorous acid, for instance, disproportionates on heating into phosphoric acid and phosphine:
$$\ce{4H3PO3 -> 3H3PO4 + PH3}$$
| Name | Formula | Oxidation state of P | Characteristic bonds | Basicity |
|---|---|---|---|---|
| Hypophosphorous (phosphinic) | H3PO2 | +1 | One P–OH, Two P–H, One P=O | Monobasic |
| Orthophosphorous (phosphonic) | H3PO3 | +3 | Two P–OH, One P–H, One P=O | Dibasic |
| Pyrophosphorous | H4P2O5 | +3 | Two P–OH, Two P–H, Two P=O | Dibasic |
| Hypophosphoric | H4P2O6 | +4 | Four P–OH, Two P=O, One P–P | Tetrabasic |
| Orthophosphoric | H3PO4 | +5 | Three P–OH, One P=O | Tribasic |
| Pyrophosphoric | H4P2O7 | +5 | Four P–OH, Two P=O, One P–O–P | Tetrabasic |
| Metaphosphoric* | (HPO3)n | +5 | Three P–OH, Three P=O, Three P–O–P (per ring unit) | — |
*Metaphosphoric acid exists in polymeric forms only; the bonds quoted are for the (HPO3)3 ring unit.
Basicity from the number of P–OH groups
This is the single most examined idea in the entire topic. The hydrogen atoms in an oxoacid are not all equivalent. Only the hydrogen attached to oxygen — in the P–OH (P–O–H) form — is ionisable and releases H+. The hydrogen attached directly to phosphorus in a P–H bond is not ionisable and plays no part in basicity.
That is why the basicity (number of replaceable hydrogens) equals the number of P–OH groups, not the number of hydrogen atoms in the formula:
| Acid | H atoms in formula | P–OH groups | P–H bonds | Basicity |
|---|---|---|---|---|
| H3PO2 (phosphinic) | 3 | 1 | 2 | Monobasic |
| H3PO3 (phosphonic) | 3 | 2 | 1 | Dibasic |
| H3PO4 (phosphoric) | 3 | 3 | 0 | Tribasic |
All three have the same three hydrogen atoms, yet their basicities are 1, 2 and 3 — entirely set by how many of those hydrogens sit on oxygen rather than on phosphorus. Thus H3PO3 is dibasic and H3PO4 tribasic, because their structures contain two and three P–OH bonds respectively.
Count P–OH bonds, never the hydrogens in the formula
The classic trap: a student sees three H in H3PO3 and calls it tribasic. Wrong — one of those hydrogens is a non-ionisable P–H, so H3PO3 is dibasic. Likewise H3PO2 has two P–H bonds and is monobasic, despite its three hydrogens.
Basicity = number of P–OH groups. P–H hydrogens do not ionise.
Reducing power comes from the P–H bond
The same P–H bond that is silent for basicity is decisive for redox behaviour. Acids that contain a P–H bond have strong reducing properties. Hypophosphorous acid (H3PO2) carries two P–H bonds and is a particularly good reducing agent — it reduces silver nitrate to metallic silver:
$$\ce{4AgNO3 + 2H2O + H3PO2 -> 4Ag + 4HNO3 + H3PO4}$$
H3PO3, with one P–H bond, is also a reducing agent, though weaker than H3PO2. By contrast, H3PO4 has no P–H bond and is not a reducing agent — phosphorus is already at its maximum +5 oxidation state. The pattern is clean: more P–H bonds (and lower oxidation state) means stronger reducing power.
Q. Arrange H3PO2, H3PO3 and H3PO4 in order of (a) basicity and (b) reducing power, and justify.
Basicity: count P–OH groups → H3PO2 (1) < H3PO3 (2) < H3PO4 (3), i.e. mono- < di- < tri-basic.
Reducing power: count P–H bonds → H3PO4 (0, not reducing) < H3PO3 (1) < H3PO2 (2, strongest reducing agent). Note the two orders run in opposite directions.
Key oxoacid structures to memorise
Three structures unlock the whole family. In each, phosphorus sits at the centre of a tetrahedron, double-bonded to one oxygen (P=O), and the remaining three positions are filled by P–OH groups and/or P–H bonds.
Read the figure as a single diagnostic: count the teal P–OH arms for basicity, count the coral P–H arms for reducing power. Hypophosphorous acid is the extreme reducing, weakly acidic end; phosphoric acid is the strongly tribasic, non-reducing end.
Phosphorus in one screen
- Allotropes: white (discrete P4, 60° strain, reactive, poisonous, glows, CS2-soluble) → red (polymeric chains, unreactive) → black (most stable).
- PH3: from Ca3P2 + water/HCl, or white P + conc. NaOH (gives NaH2PO2). Weakly basic (forms PH4I). Lower b.p. than NH3 — no H-bonding.
- PCl3: pyramidal, sp3; hydrolyses to H3PO3 + HCl.
- PCl5: trigonal bipyramidal, sp3d; equatorial 202 pm, axial 240 pm (not all equivalent); hydrolyses via POCl3 to H3PO4.
- Basicity = number of P–OH groups: H3PO2 mono, H3PO3 di, H3PO4 tri.
- Reducing power = number of P–H bonds: H3PO2 > H3PO3 > H3PO4 (none).
- +3 acids (e.g. H3PO3) disproportionate: $\ce{4H3PO3 -> 3H3PO4 + PH3}$.