Chemistry · The p-Block Elements (Class 12)

Group 18 — Noble Gases

Group 18 collects the six chemically reluctant gases — helium, neon, argon, krypton, xenon and radon — whose valence shells are completely filled. This deep-dive follows the old-NCERT supplement (§7.23) and NIOS Chapter 20 to trace why these elements are nearly inert, how their physical properties trend down the group, and how xenon was finally forced into compounds such as $\ce{XeF2}$, $\ce{XeF4}$ and $\ce{XeF6}$. For NEET the group is compact but high-yield: VSEPR shapes of the xenon fluorides and the hydrolysis products are recurring one-mark questions.

Members and Occurrence

Group 18 consists of helium ($\ce{He}$), neon ($\ce{Ne}$), argon ($\ce{Ar}$), krypton ($\ce{Kr}$), xenon ($\ce{Xe}$) and radon ($\ce{Rn}$) — together with the synthetic element oganesson ($\ce{Og}$, $Z=118$), which has been produced only in trace amounts and whose chemistry is mostly predicted. All the naturally occurring members are gases and chemically unreactive, forming very few compounds; hence the family name noble gases.

With the exception of radon, all occur in the atmosphere. Their total abundance in dry air is roughly 1% by volume, of which argon is by far the major constituent. Helium — and sometimes neon — is also found trapped in minerals of radioactive origin such as pitchblende, monazite and cleveite, while the chief commercial source of helium is natural gas. Xenon and radon are the rarest members. Radon is not mined at all; it is generated continuously as a decay product of radium:

$$\ce{^{226}_{88}Ra -> ^{222}_{86}Rn + ^{4}_{2}He}$$

ElementAtomic no.Atmospheric content (% by volume)Note
Helium, $\ce{He}$2$5.24\times10^{-4}$Also in natural gas
Neon, $\ce{Ne}$10$1.82\times10^{-3}$
Argon, $\ce{Ar}$18$0.934$Major constituent
Krypton, $\ce{Kr}$36$1.14\times10^{-4}$
Xenon, $\ce{Xe}$54$8.7\times10^{-6}$Rarest stable member
Radon, $\ce{Rn}$86Radioactive; decay of $\ce{Ra}$

Electronic Configuration

Every noble gas closes a shell. The general valence configuration is $\ce{ns^2 np^6}$ — the stable octet — with the single exception of helium, whose first shell is full at just two electrons, $\ce{1s^2}$. It is precisely this closed-shell architecture that accounts for almost every property of the group, from inertness to the extreme ionisation enthalpies.

ElementElectronic configuration
$\ce{He}$$1s^2$
$\ce{Ne}$$[\ce{He}]\,2s^2 2p^6$
$\ce{Ar}$$[\ce{Ne}]\,3s^2 3p^6$
$\ce{Kr}$$[\ce{Ar}]\,3d^{10} 4s^2 4p^6$
$\ce{Xe}$$[\ce{Kr}]\,4d^{10} 5s^2 5p^6$
$\ce{Rn}$$[\ce{Xe}]\,4f^{14} 5d^{10} 6s^2 6p^6$

Why the Noble Gases Are Inert

The near-total chemical reluctance of Group 18 rests on two linked facts, both flowing from the closed valence shell. First, all noble gases except helium have completely filled $\ce{ns^2 np^6}$ valence orbitals (helium is full at $\ce{1s^2}$), so there is no electronic incentive to bond. Second, this stability shows up quantitatively in two energetic terms.

QuantityBehaviour in Group 18Reason
Ionisation enthalpy Very high; highest in each period. Decreases down the group. Stable closed shell resists electron loss; larger atoms hold electrons more loosely.
Electron gain enthalpy Large positive values. An added electron would have to enter a new, higher shell — energetically unfavourable.

Down the group the ionisation enthalpy falls steadily — from $2372\ \text{kJ mol}^{-1}$ for helium to about $1037\ \text{kJ mol}^{-1}$ for radon — as the valence electrons sit farther from the nucleus. This declining ionisation enthalpy is exactly why xenon, not the lighter members, is the one that yields compounds.

NEET Trap

"Inert" does not mean zero electron affinity is favourable

Students often assume a full shell means a noble gas "does not want" an electron because its affinity is simply zero. The sharper statement is that the electron gain enthalpy is large and positive: forcing an electron in actually costs energy because it must occupy the next shell.

High (positive) electron gain enthalpy + very high ionisation enthalpy ⇒ inertness.

All noble gases are monoatomic, colourless, odourless and tasteless, and are only sparingly soluble in water. Because the only force acting between their atoms is the weak London dispersion force, they have very low melting and boiling points. Atomic radius increases down the group with rising atomic number, and the strengthening dispersion forces in the heavier, more polarisable atoms push the boiling points upward from helium to radon.

Helium holds two records worth memorising. It has the lowest boiling point of any known substance, 4.2 K, and it diffuses readily through ordinary laboratory materials such as rubber, glass and plastics — a property exploited in leak detection and cryogenics.

Property$\ce{He}$$\ce{Ne}$$\ce{Ar}$$\ce{Kr}$$\ce{Xe}$$\ce{Rn}$
Atomic mass / g mol⁻¹4.0020.1839.9583.80131.30222.00
Ionisation enthalpy / kJ mol⁻¹237220801520135111701037
Boiling point / K4.227.187.2119.7165.0

Two trends move in opposite directions and are easy to confuse: ionisation enthalpy falls down the group while boiling point and atomic radius rise. The same closed-shell stability that gives the largest ionisation enthalpy at the top of each period also explains why these gases were the last family to be coaxed into chemistry at all.

Xenon Fluorides — Preparation

For decades every attempt to make a noble-gas compound failed. The breakthrough came in March 1962, when Neil Bartlett noticed that the first ionisation enthalpy of molecular oxygen ($1175\ \text{kJ mol}^{-1}$) was almost identical to that of xenon ($1170\ \text{kJ mol}^{-1}$). Having already made the red salt $\ce{O2^+[PtF6]^-}$, he reasoned xenon should behave likewise — and by mixing $\ce{PtF6}$ with xenon he obtained a red compound formulated as $\ce{Xe^+[PtF6]^-}$. The floodgates opened, and a series of xenon compounds with the most electronegative elements (fluorine and oxygen) followed.

Xenon forms three binary fluorides by direct combination with fluorine; which one results is dictated by the temperature and the $\ce{Xe}:\ce{F2}$ ratio:

$$\ce{Xe(g) + F2(g) ->[673\ K,\ 1\ bar][Xe\ in\ excess] XeF2(s)}$$

$$\ce{Xe(g) + 2F2(g) ->[873\ K,\ 7\ bar][1:5\ ratio] XeF4(s)}$$

$$\ce{Xe(g) + 3F2(g) ->[573\ K,\ 60{-}70\ bar][1:20\ ratio] XeF6(s)}$$

$\ce{XeF6}$ can also be made by the low-temperature reaction of $\ce{XeF4}$ with dioxygen difluoride:

$$\ce{XeF4 + O2F2 ->[143\ K] XeF6 + O2}$$

All three fluorides are colourless crystalline solids that sublime readily at 298 K and are powerful fluorinating agents. They are so reactive that even traces of water hydrolyse them. They also behave amphoterically toward fluoride: with strong fluoride-ion acceptors (Lewis acids) they yield cationic species, and with fluoride-ion donors $\ce{XeF6}$ yields fluoroanions.

$$\ce{XeF2 + PF5 -> [XeF]^+[PF6]^-} \qquad \ce{XeF4 + SbF5 -> [XeF3]^+[SbF6]^-}$$

$$\ce{XeF6 + MF -> M^+[XeF7]^-}\quad(\ce{M = Na, K, Rb, Cs})$$

Build the contrast

The "most electronegative partner" logic that makes $\ce{XeF6}$ possible is the same chemistry that drives the Group 17 — Halogen Family. Revise the halogens to see why fluorine and oxygen are xenon's only real partners.

VSEPR Structures of Xenon Compounds

The shapes of the xenon fluorides follow directly from VSEPR once the lone pairs on the central xenon are counted. $\ce{XeF2}$ has two bond pairs and three lone pairs (five electron pairs, $sp^3d$); the lone pairs take the equatorial positions, leaving the two fluorines axial — hence a linear molecule. $\ce{XeF4}$ has four bond pairs and two lone pairs (six electron pairs, $sp^3d^2$) with the lone pairs trans to each other, giving a square planar shape.

Figure 1 — XeF₂ and XeF₄ geometries XeF₂ — linear F Xe F 3 lone pairs (equatorial) 180° · sp³d XeF₄ — square planar Xe F F F F 2 lone pairs (axial, trans) 90° · sp³d²

$\ce{XeF2}$: linear; equatorial lone pairs separate the axial $\ce{F}$ atoms by 180°. $\ce{XeF4}$: square planar; the two lone pairs occupy trans positions above and below the plane.

$\ce{XeF6}$ is the awkward one. It has six bond pairs and one lone pair — seven electron pairs in all. Rather than a regular octahedron, the extra lone pair distorts the geometry, and experimentally in the gas phase $\ce{XeF6}$ is a distorted octahedron.

Figure 2 — XeF₆ distorted octahedron Xe F F F F F F lp 7 electron pairs (6 bp + 1 lp) · sp³d³

The seventh (lone) pair on xenon distorts the six $\ce{Xe-F}$ bonds away from a perfect octahedron — the source of the "distorted octahedral" description.

Hydrolysis and Xenon–Oxygen Compounds

Because the fluorides are such strong fluorinating agents, their reactions with water are central to the xenon–oxygen chemistry. $\ce{XeF2}$ hydrolyses slowly to give the free element, hydrogen fluoride and oxygen — a clean way to recover xenon:

$$\ce{2XeF2(s) + 2H2O(l) -> 2Xe(g) + 4HF(aq) + O2(g)}$$

$\ce{XeF4}$ and $\ce{XeF6}$ react with water far more vigorously. Complete hydrolysis builds the colourless, explosive solid xenon trioxide, $\ce{XeO3}$:

$$\ce{6XeF4 + 12H2O -> 4Xe + 2XeO3 + 24HF + 3O2}$$

$$\ce{XeF6 + 3H2O -> XeO3 + 6HF}$$

Crucially, the partial hydrolysis of $\ce{XeF6}$ stops short of the trioxide and yields oxyfluorides — the volatile liquid $\ce{XeOF4}$ and $\ce{XeO2F2}$:

$$\ce{XeF6 + H2O -> XeOF4 + 2HF} \qquad \ce{XeF6 + 2H2O -> XeO2F2 + 4HF}$$

NEET Trap

Hydrolysis of XeF₆ is NOT a redox reaction

It is tempting to mark the formation of $\ce{XeOF4}$ or $\ce{XeO2F2}$ as a redox change because new elements appear. Check the oxidation states: xenon stays the same on both sides, and so do oxygen and fluorine. No element is oxidised or reduced — it is a substitution/hydrolysis, not a redox reaction.

Same oxidation states before and after ⇒ hydrolysis, not redox.

$\ce{XeO3}$ has a pyramidal molecular structure (three bond pairs, one lone pair — analogous to $\ce{NH3}$), while $\ce{XeOF4}$ is a colourless volatile liquid with a square pyramidal shape. These two shapes, alongside the linear/square-planar/distorted-octahedral fluorides, are the exact set NEET likes to test in match-the-column form.

SpeciesElectron pairs (bp + lp)HybridisationShape
$\ce{XeF2}$2 + 3$sp^3d$Linear
$\ce{XeF4}$4 + 2$sp^3d^2$Square planar
$\ce{XeF6}$6 + 1$sp^3d^3$Distorted octahedral
$\ce{XeO3}$3 + 1$sp^3$Pyramidal
$\ce{XeOF4}$5 + 1$sp^3d^2$Square pyramidal

Uses of the Noble Gases

Although the heavy members are chemically interesting, the light noble gases are the ones with broad practical value. Their applications follow straight from their physical properties — inertness, low density, low blood solubility and characteristic discharge colours.

GasUses
$\ce{He}$ Non-inflammable, light gas for weather balloons; coolant in gas-cooled nuclear reactors; liquid helium (b.p. 4.2 K) as a cryogenic agent and to sustain the superconducting magnets in NMR spectrometers and MRI scanners; diluent for oxygen in diving apparatus owing to low solubility in blood.
$\ce{Ne}$ Discharge tubes and fluorescent bulbs for advertisement displays; neon bulbs in botanical gardens and greenhouses.
$\ce{Ar}$ Inert atmosphere for high-temperature metallurgy (arc welding) and for filling electric bulbs; laboratory handling of air-sensitive substances.
$\ce{Xe},\ \ce{Kr}$ No significant uses; employed in light bulbs designed for special purposes.
Quick Recap

Group 18 in one screen

  • Members $\ce{He, Ne, Ar, Kr, Xe, Rn}$; argon is the most abundant in air (~0.93%); radon comes from decay of $\ce{^{226}Ra}$.
  • Configuration $\ce{ns^2 np^6}$ (helium $\ce{1s^2}$): very high ionisation enthalpy (falls down the group) and large positive electron gain enthalpy ⇒ inertness.
  • Monoatomic, only dispersion forces ⇒ very low boiling points; helium is the lowest of any substance (4.2 K).
  • Bartlett (1962) made $\ce{Xe^+[PtF6]^-}$ because IE of $\ce{Xe}$ ≈ IE of $\ce{O2}$.
  • $\ce{XeF2}$ linear, $\ce{XeF4}$ square planar, $\ce{XeF6}$ distorted octahedral; $\ce{XeO3}$ pyramidal, $\ce{XeOF4}$ square pyramidal.
  • $\ce{XeF6}$ hydrolysis: complete → $\ce{XeO3}$; partial → $\ce{XeOF4}$, $\ce{XeO2F2}$ (no oxidation-state change).

NEET PYQ Snapshot — Group 18 — Noble Gases

Shapes and hybridisation of xenon compounds are the workhorse of this subtopic.

NEET — PYQ

Match the compounds in Column I with the hybridisation and shape in Column II and mark the correct option.

(a) $\ce{XeF6}$ — (i) distorted octahedral
(b) $\ce{XeO3}$ — (ii) square planar
(c) $\ce{XeOF4}$ — (iii) pyramidal
(d) $\ce{XeF4}$ — (iv) square pyramidal

(1) (a)-i, (b)-ii, (c)-iv, (d)-iii    (2) (a)-iv, (b)-iii, (c)-i, (d)-ii
(3) (a)-iv, (b)-i, (c)-ii, (d)-iii    (4) (a)-i, (b)-iii, (c)-iv, (d)-ii

Answer: (4)

$\ce{XeF6}$ ($sp^3d^3$) is distorted octahedral; $\ce{XeO3}$ ($sp^3$) is pyramidal; $\ce{XeOF4}$ ($sp^3d^2$) is square pyramidal; $\ce{XeF4}$ ($sp^3d^2$) is square planar. The matching is (a)-i, (b)-iii, (c)-iv, (d)-ii.

Concept

Which statement about the noble gases is correct?

(1) Their electron gain enthalpies are large and negative
(2) Ionisation enthalpy increases down the group
(3) They have very high ionisation enthalpy and large positive electron gain enthalpy
(4) Helium has the configuration $\ce{1s^2 2s^2}$

Answer: (3)

Closed-shell stability gives very high ionisation enthalpy (which actually decreases down the group) and large positive electron gain enthalpy. Helium is $\ce{1s^2}$. Together these explain the family's inertness.

FAQs — Group 18 — Noble Gases

The high-frequency conceptual queries on this subtopic.

Why are the elements of Group 18 called noble gases?

The elements of Group 18 have completely filled valence-shell orbitals (ns²np⁶, helium 1s²). This closed-shell configuration is exceptionally stable, so the atoms have very high ionisation enthalpy and large positive electron gain enthalpy and react only with a few elements under special conditions. Because of this near-inertness they are termed noble gases.

Why do noble gases have very low boiling points?

Noble gases are monoatomic and the only interatomic interaction between their atoms is weak dispersion (London) forces. These forces are extremely feeble, so the gases liquefy only at very low temperatures and hence have very low boiling points. Helium has the lowest boiling point of any known substance, 4.2 K.

What are the shapes of XeF2, XeF4 and XeF6 by VSEPR?

XeF2 is linear (sp³d, three lone pairs in the equatorial plane). XeF4 is square planar (sp³d², two lone pairs trans to each other). XeF6 has seven electron pairs — six bond pairs and one lone pair — and is therefore a distorted octahedron, as found experimentally in the gas phase.

What are the products of hydrolysis of XeF6?

Complete hydrolysis of XeF6 with excess water gives xenon trioxide: XeF6 + 3H2O → XeO3 + 6HF. Partial hydrolysis gives oxyfluorides: XeF6 + H2O → XeOF4 + 2HF and XeF6 + 2H2O → XeO2F2 + 4HF. Hydrolysis is not a redox reaction because the oxidation states of all elements remain unchanged.

Which noble gases form compounds and which do not?

Xenon forms the largest number of compounds, chiefly with the most electronegative elements fluorine and oxygen. Krypton forms only the difluoride KrF2. Radon compounds such as RnF2 have been identified only by radiotracer techniques because radon is radioactive with short-lived isotopes. No true compounds of helium, neon or argon are yet known.

Why is helium used in diving apparatus?

Helium has very low solubility in blood, so it is used as a diluent for oxygen in modern diving apparatus. This avoids the painful and dangerous bubbles of dissolved gas (decompression sickness) that would form on rapid ascent if a more soluble gas were used.