Chemistry · The p-Block Elements (Class 12)

Group 17 — Halogen Family

Group 17 — fluorine, chlorine, bromine, iodine and astatine — are the halogens, the most reactive non-metals in the periodic table. This deep dive follows the supplementary old-NCERT treatment (§7.18–7.19) and the NIOS account of fluorine and chlorine, covering the $ns^2np^5$ configuration, periodic trends, the two famous anomalies (Cl > F electron gain enthalpy, F₂ bond enthalpy), oxidising power and the preparation, properties and uses of chlorine — all high-frequency NEET territory.

Occurrence and electronic configuration

The name halogen comes from the Greek halo (salt) and genes (born) — the "salt-producers". The group comprises fluorine, chlorine, bromine, iodine, astatine and the synthetic tennessine; astatine and tennessine are radioactive, and tennessine's chemistry has never been established because only milligram-scale amounts with millisecond half-lives exist. Members of Group 17 show closer family resemblance, with a more regular gradation of properties, than any other group of the periodic table.

Fluorine and chlorine are fairly abundant; bromine and iodine less so. Fluorine occurs mainly as insoluble fluorides — fluorspar $\ce{CaF2}$, cryolite $\ce{Na3AlF6}$ and fluoroapatite $\ce{3Ca3(PO4)2.CaF2}$. Sea water is essentially a sodium chloride solution (about 2.5% by mass) but also carries bromides and iodides, while dried-up sea deposits supply carnallite $\ce{KCl.MgCl2.6H2O}$. Iodine appears in marine life: certain seaweeds contain up to 0.5% iodine and Chile saltpetre up to 0.2% sodium iodate.

Every halogen has the valence configuration $ns^2np^5$ — seven electrons in the outermost shell, exactly one short of the next noble gas. That single-electron deficit is the master key to almost all halogen chemistry: it explains the high electronegativity, the strongly negative electron gain enthalpy and the dominant $-1$ oxidation state.

ElementZValence config.State (RT)Colour
Fluorine (F)9[He]2s²2p⁵GasPale / yellow
Chlorine (Cl)17[Ne]3s²3p⁵GasGreenish-yellow
Bromine (Br)35[Ar]3d¹⁰4s²4p⁵LiquidRed
Iodine (I)53[Kr]4d¹⁰5s²5p⁵SolidViolet
Astatine (At)85[Xe]4f¹⁴5d¹⁰6s²6p⁵Solid (radioactive)

Halogens have the smallest atomic radii in their respective periods because the maximum effective nuclear charge for that period pulls the valence shell inward. Fluorine, being a second-period element, is extremely small. Both atomic and ionic radii increase from F to I as successive quantum shells are added.

Because each atom is only one electron short of a stable octet, halogens have very little tendency to lose electrons, hence very high ionisation enthalpy. Ionisation enthalpy falls down the group as the atom enlarges and the outer electrons become easier to remove. Electronegativity follows the same downward trend: fluorine is the most electronegative element in the periodic table.

PropertyFClBrI
Ionisation enthalpy / kJ mol⁻¹1680125611421008
Electron gain enthalpy / kJ mol⁻¹−333−349−325−296
Electronegativity (Pauling)4.0*3.23.02.7
X–X bond enthalpy / kJ mol⁻¹158.8242.6192.8151.1
E°(X₂/X⁻) / V+2.87+1.36+1.09+0.54

*Fluorine is conventionally assigned 4.0 on the Pauling scale, the highest of any element; the supplementary table tabulates Cl 3.2, Br 3.0, I 2.7. All other figures are from Table 7.8 of the supplementary text.

Electron gain enthalpy and the Cl > F anomaly

Halogens have the most negative (maximum) electron gain enthalpy in their respective periods, because adding one electron completes a stable noble-gas configuration. Down the group the electron gain enthalpy becomes less negative as size increases. But there is a celebrated exception at the top: the negative electron gain enthalpy of fluorine is smaller than that of chlorine ($-333$ vs $-349$ kJ mol⁻¹).

The reason is fluorine's tiny size. Its 2p orbitals are so compact that the electrons already present crowd together, producing strong inter-electronic repulsions. An incoming electron entering these small 2p orbitals is repelled and does not feel the full nuclear attraction, so less energy is released than in chlorine, whose larger 3p orbitals accommodate the extra electron more comfortably. Chlorine therefore holds the record for the most negative electron gain enthalpy of all the elements.

Figure 1

Electron gain enthalpy down Group 17 — the F → Cl dip.

−ΔₑgH kJ/mol 0 150 300 333 F 349 Cl 325 Br 296 I anomaly

Cl has a more negative electron gain enthalpy than F; from Cl onward the value becomes less negative down the group.

Bond enthalpy and the F₂ anomaly

A second curiosity sits in the X–X bond enthalpies. One would expect bond strength to fall steadily down the group, yet the dissociation enthalpy of $\ce{F2}$ (158.8 kJ mol⁻¹) is smaller than that of $\ce{Cl2}$ (242.6) and $\ce{Br2}$ (192.8). From chlorine onward the expected order returns: $\text{Cl–Cl} > \text{Br–Br} > \text{I–I}$. The complete order is therefore

$\text{Cl–Cl} > \text{Br–Br} > \text{F–F} > \text{I–I}$

The anomaly arises because the two fluorine atoms in $\ce{F2}$ are so small that their non-bonding lone pairs are forced very close together. The resulting large lone-pair / lone-pair (electron-electron) repulsion weakens the F–F bond — an effect far less pronounced in the larger $\ce{Cl2}$ molecule.

Figure 2

X–X bond dissociation enthalpy: the F₂ dip below Cl₂ and Br₂.

ΔdissH kJ/mol 100 200 158.8 242.6 192.8 151.1 F₂ Cl₂ Br₂ I₂ lp–lp repulsion

The maximum is at Cl₂, not F₂. The dip at F₂ comes from severe lone-pair repulsion in the very small molecule.

NEET Trap

Two different anomalies, two different reasons

Candidates routinely confuse the electron gain enthalpy anomaly with the bond enthalpy anomaly. They both involve fluorine being "less than chlorine", but the causes differ. The electron gain enthalpy of F is less negative because of repulsion in the small 2p orbital of the atom. The bond enthalpy of $\ce{F2}$ is low because of lone-pair repulsion between the two bonded atoms in the molecule.

EGE anomaly → small atom, compact 2p orbital. Bond-enthalpy anomaly → lone pairs too close in the F₂ molecule.

Physical states, colour and oxidation states

Halogens display a smooth gradation of physical properties. Down the group fluorine and chlorine are gases, bromine a liquid and iodine a solid, with melting and boiling points rising steadily as molar mass and van der Waals forces increase. All halogens are coloured: they absorb radiation in the visible region, exciting outer electrons to higher levels, and the quantum of radiation absorbed sets the colour seen — yellow $\ce{F2}$, greenish-yellow $\ce{Cl2}$, red $\ce{Br2}$ and violet $\ce{I2}$. Bromine and iodine are only sparingly soluble in water but dissolve readily in organic solvents such as chloroform and carbon tetrachloride to give coloured solutions.

All halogens exhibit the $-1$ oxidation state. Chlorine, bromine and iodine additionally show $+1, +3, +5$ and $+7$ states because their atoms can be promoted to excited states with three, five and seven unpaired electrons, the extra electrons occupying available $d$ orbitals. These higher states appear only in combination with the small, highly electronegative oxygen and fluorine atoms — in interhalogens, oxides and oxoacids. Fluorine, lacking $d$ orbitals and being the most electronegative element, can neither expand its octet nor take a positive oxidation state, so it is restricted to $-1$.

Oxidising power and reactivity

The ready acceptance of an electron makes all halogens strong oxidising agents, and reactivity decreases down the group. $\ce{F2}$ is the strongest oxidising halogen: a halogen will oxidise the halide ion of any halogen of higher atomic number.

$\ce{F2 + 2X^- -> 2F^- + X2}$ (X = Cl, Br or I)
$\ce{Cl2 + 2X^- -> 2Cl^- + X2}$ (X = Br or I)
$\ce{Br2 + 2I^- -> 2Br^- + I2}$

The decreasing oxidising ability in aqueous solution is mirrored by the standard electrode potentials $E^\circ(\ce{X2}/\ce{X^-})$, which fall from $+2.87$ V for fluorine to $+0.54$ V for iodine. The electrode potential depends on three energy terms in sequence: bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy of the halide ion.

The same trend shows in reactions with water. Fluorine oxidises water all the way to oxygen, whereas chlorine and bromine only partly react to give a hydrohalic and a hypohalous acid; iodine cannot oxidise water at all — in fact dissolved oxygen oxidises $\ce{I^-}$ in acid solution, the exact reverse of the fluorine reaction.

$\ce{2F2 + 2H2O -> 4H^+ + 4F^- + O2}$
$\ce{X2 + H2O -> HX + HOX}$ (X = Cl or Br)
$\ce{4I^- + 4H^+ + O2 -> 2I2 + 2H2O}$

Worked example

Why is fluorine a stronger oxidising agent than chlorine, even though Cl has the more negative electron gain enthalpy?

Oxidising power in solution is set by the sum of three steps — dissociation of $\ce{X2}$, electron gain to form $\ce{X^-}$, and hydration of $\ce{X^-}$. Fluorine wins on two of the three: its F–F bond dissociation enthalpy is unusually low, and the small $\ce{F^-}$ ion has a very high (most negative) hydration enthalpy. These two favourable terms outweigh fluorine's slightly less negative electron gain enthalpy, giving $\ce{F2}$ the highest $E^\circ$ ($+2.87$ V) and the title of strongest oxidising halogen.

Build on this

Once oxidation states click, the acid strengths and structures follow naturally — see Hydrogen Halides & Oxoacids of Halogens.

Anomalous behaviour of fluorine

As the head element of the group and a second-period p-block element, fluorine breaks the smooth trends in several ways. Its ionisation enthalpy, electronegativity and electrode potential are all higher than the group trend would predict, while its ionic and covalent radii, melting and boiling points, bond dissociation enthalpy and electron gain enthalpy are all lower than expected. The root causes are its small size, highest electronegativity, low F–F bond dissociation enthalpy and the absence of $d$ orbitals in its valence shell.

AnomalyFluorineOther halogens
Oxidation statesOnly −1−1, +1, +3, +5, +7
Number of oxoacidsOnly one (HOF)Several oxoacids each
Hydrogen halide stateHF is a liquid (H-bonding, b.p. 293 K)HCl, HBr, HI are gases
ReactionsMostly exothermic (small, strong bonds)Less exothermic

Hydrogen fluoride is a liquid (b.p. 293 K) because the small, highly electronegative fluorine forms strong intermolecular hydrogen bonds; the larger, less electronegative halogens give gaseous $\ce{HCl}$, $\ce{HBr}$ and $\ce{HI}$. Note also the acid-strength order $\ce{HF} < \ce{HCl} < \ce{HBr} < \ce{HI}$, which tracks the falling H–X bond dissociation enthalpy down the group.

Chlorine — preparation, properties and uses

Chlorine was discovered by Scheele in 1774 from the action of $\ce{HCl}$ on $\ce{MnO2}$; Davy established its elementary nature in 1810 and named it after its colour (Greek chloros, greenish-yellow).

Preparation and manufacture

In the laboratory chlorine is made by oxidising concentrated $\ce{HCl}$ (or a salt + $\ce{H2SO4}$ mixture) with $\ce{MnO2}$ or $\ce{KMnO4}$:

$\ce{MnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O}$
$\ce{4NaCl + MnO2 + 4H2SO4 -> MnCl2 + 4NaHSO4 + 2H2O + Cl2}$
$\ce{2KMnO4 + 16HCl -> 2KCl + 2MnCl2 + 8H2O + 5Cl2}$

Industrially it is obtained by Deacon's process — air oxidation of $\ce{HCl}$ over a $\ce{CuCl2}$ catalyst at 723 K — and chiefly by the electrolysis of brine (concentrated $\ce{NaCl}$ solution), where chlorine is liberated at the anode. It also arises as a by-product in many chemical industries.

$\ce{4HCl + O2 ->[CuCl2][723\,K] 2Cl2 + 2H2O}$

Properties

Chlorine is a greenish-yellow gas with a pungent, suffocating odour, about 2.5 times heavier than air, easily liquefied to a greenish-yellow liquid (b.p. 239 K) and soluble in water. It reacts directly with metals and non-metals to give chlorides, and has a strong affinity for hydrogen:

$\ce{2Al + 3Cl2 -> 2AlCl3}$    $\ce{P4 + 6Cl2 -> 4PCl3}$
$\ce{2Fe + 3Cl2 -> 2FeCl3}$    $\ce{H2 + Cl2 -> 2HCl}$

With alkalis the outcome depends on conditions — dilute/cold alkali gives chloride + hypochlorite, hot/concentrated alkali gives chloride + chlorate. Both are disproportionations, with chlorine going from the 0 state to $-1$ and $+1$ (or $+5$):

$\ce{2NaOH + Cl2 -> NaCl + NaOCl + H2O}$ (cold, dilute)
$\ce{6NaOH + 3Cl2 -> 5NaCl + NaClO3 + 3H2O}$ (hot, conc.)

With dry slaked lime it gives bleaching powder, $\ce{Ca(OCl)2.CaCl2.Ca(OH)2.2H2O}$:

$\ce{2Ca(OH)2 + 2Cl2 -> Ca(OCl)2 + CaCl2 + 2H2O}$

Oxidising and bleaching action — nascent oxygen

Chlorine water on standing loses its yellow colour as it forms $\ce{HCl}$ and hypochlorous acid $\ce{HOCl}$; the $\ce{HOCl}$ supplies nascent oxygen $[\ce{O}]$, which is responsible for both the oxidising and bleaching properties of chlorine. As an oxidant, chlorine converts ferrous to ferric, sulphite to sulphate, $\ce{SO2}$ to $\ce{H2SO4}$ and $\ce{I2}$ to iodate:

$\ce{2FeSO4 + H2SO4 + Cl2 -> Fe2(SO4)3 + 2HCl}$
$\ce{SO2 + 2H2O + Cl2 -> H2SO4 + 2HCl}$
$\ce{I2 + 6H2O + 5Cl2 -> 2HIO3 + 10HCl}$

Its bleaching action is due to oxidation and requires moisture. Nascent oxygen oxidises the coloured matter to a colourless product, and because the colour is destroyed rather than masked, the bleaching is permanent:

$\ce{Cl2 + H2O -> 2HCl + [O]}$
Coloured substance $+\ [\ce{O}] \longrightarrow$ Colourless substance

NEET Trap

Chlorine bleaches by oxidation; SO₂ bleaches by reduction

Both gases are bleaching agents but by opposite mechanisms. Chlorine releases nascent oxygen and bleaches by oxidation — the effect is permanent. $\ce{SO2}$ (covered in Group 16) releases nascent hydrogen and bleaches by reduction — that effect is temporary, since atmospheric oxygen slowly restores the colour.

Cl₂ → oxidation → permanent bleach. SO₂ → reduction → temporary bleach.

Uses

Chlorine is used for bleaching wood-pulp (paper and rayon) and cotton textiles; in the extraction of gold and platinum; in manufacturing dyes, drugs and organic compounds such as $\ce{CCl4}$, $\ce{CHCl3}$, DDT and refrigerants; in sterilising drinking water; and in preparing poisonous gases including phosgene $\ce{COCl2}$, tear gas $\ce{CCl3NO2}$ and mustard gas $\ce{ClCH2CH2SCH2CH2Cl}$.

Quick Recap

Group 17 in one screen

  • Configuration $ns^2np^5$; smallest atoms of their periods; very high IE; F is the most electronegative element.
  • EGE most negative in the period but Cl > F (compact 2p orbital repulsion in fluorine).
  • Bond enthalpy order $\text{Cl–Cl} > \text{Br–Br} > \text{F–F} > \text{I–I}$ — F₂ is low due to lone-pair repulsion.
  • States: F, Cl gases; Br liquid; I solid. Colours yellow → greenish-yellow → red → violet.
  • Oxidising power $\ce{F2} > \ce{Cl2} > \ce{Br2} > \ce{I2}$; $E^\circ$ falls $+2.87$ → $+0.54$ V; F₂'s strength comes from low bond enthalpy + high F⁻ hydration enthalpy.
  • Fluorine anomalies: only $-1$ state, only one oxoacid (HOF), HF a liquid, mostly exothermic reactions.
  • Chlorine: prep by $\ce{MnO2}/\ce{KMnO4}$ on HCl, Deacon's process, brine electrolysis. Bleaches permanently via nascent oxygen.

NEET PYQ Snapshot — Group 17 — Halogen Family

Verified previous-year questions from the NEET p-block bank for this subtopic.

NEET 2018

Which of the following statements is not true for halogens?

  1. All form monobasic oxyacids
  2. All are oxidizing agents
  3. All but fluorine show positive oxidation states
  4. Chlorine has the highest electron-gain enthalpy
Official key: Bonus

The question was awarded a bonus. The clearly incorrect statement is (1): fluorine forms only one oxoacid (HOF), and not all halogen oxoacids are monobasic. Statement (3) is correct because fluorine, being most electronegative with no d orbitals, shows only the −1 state while the others show positive states; statement (4) is correct since chlorine indeed has the most negative (highest) electron gain enthalpy.

NEET PYQ

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?

  1. Cl₂ > Br₂ > F₂ > I₂
  2. Br₂ > I₂ > F₂ > Cl₂
  3. F₂ > Cl₂ > Br₂ > I₂
  4. I₂ > Br₂ > Cl₂ > F₂
Answer: (1) Cl₂ > Br₂ > F₂ > I₂

The bond dissociation enthalpy of F₂ is lower than that of Cl₂ and Br₂ because the small fluorine atoms force their lone pairs close together, producing strong lone-pair repulsion that weakens the F–F bond. Hence F₂ falls between Br₂ and I₂ instead of topping the list.

FAQs — Group 17 — Halogen Family

The anomalies and chlorine reactions examiners return to most often.

Why is the electron gain enthalpy of fluorine less negative than that of chlorine?

Fluorine has the smallest size in the group, so its 2p orbitals are very compact. When an extra electron enters, the strong interelectronic repulsions in these small 2p orbitals oppose its addition, so the incoming electron does not experience as much attraction as expected. As a result the negative electron gain enthalpy of fluorine (−333 kJ/mol) is less than that of chlorine (−349 kJ/mol), making chlorine the halogen with the most negative electron gain enthalpy.

Why does F2 have a lower bond dissociation enthalpy than Cl2 and Br2?

In F2 the two fluorine atoms are very small, so the lone pairs of electrons on the bonded atoms lie much closer together than in Cl2. The resulting large lone-pair, lone-pair (electron-electron) repulsion weakens the F-F bond. Hence the bond dissociation enthalpy order is Cl-Cl > Br-Br > F-F > I-I rather than a smooth decrease down the group.

Why is fluorine a stronger oxidising agent than chlorine even though its electron gain enthalpy is less negative?

Oxidising power in aqueous solution depends on three steps: bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy. Fluorine has a very low F-F bond dissociation enthalpy and the F- ion has a very high (most negative) hydration enthalpy because of its small size. These two factors more than offset its less negative electron gain enthalpy, giving F2 the highest standard electrode potential (+2.87 V) and making it the strongest oxidising halogen.

How is the bleaching action of chlorine explained?

Bleaching by chlorine is due to oxidation and requires moisture. Chlorine reacts with water to give nascent oxygen, Cl2 + H2O -> 2HCl + O. This nascent oxygen oxidises the coloured substance to a colourless one. Because the colour is destroyed by oxidation rather than merely masked, the bleaching effect of chlorine is permanent.

Why does fluorine show only the -1 oxidation state while other halogens show +1, +3, +5 and +7?

Fluorine is the most electronegative element and has no d orbitals in its valence shell, so it cannot expand its octet and cannot exhibit any positive oxidation state. Chlorine, bromine and iodine have accessible d orbitals, allowing the octet to expand, so they show +1, +3, +5 and +7 states in combination with the more electronegative oxygen and fluorine atoms in addition to -1.

What is nascent oxygen and why is it important for chlorine?

Nascent oxygen is freshly liberated atomic oxygen, written as [O], produced when chlorine water decomposes: Cl2 + H2O -> 2HCl + O. It is far more reactive than molecular O2 and is responsible for the oxidising and bleaching properties of chlorine. Hypochlorous acid (HOCl) formed in chlorine water also releases this nascent oxygen on standing.