Chemistry · The p-Block Elements (Class 12)

Group 15 — Nitrogen Family: General Characteristics

Group 15 of the periodic table runs nitrogen, phosphorus, arsenic, antimony and bismuth — a single column that travels from a diatomic gas to a frank metal. This deep dive consolidates the general characteristics of the nitrogen family as set out in the old-NCERT p-block supplement (§7.1) and NIOS Chemistry: the $ns^2np^3$ configuration, periodic trends, oxidation states, the anomalous behaviour of nitrogen, and the graded properties of the $\ce{EH3}$ hydrides — the exact territory NEET mines for statement-match questions.

Members and Occurrence

Group 15 comprises nitrogen, phosphorus, arsenic, antimony, bismuth and the synthetic radioactive element moscovium (Mc). The defining narrative of the group is a steady shift from non-metallic to metallic character: nitrogen and phosphorus are non-metals, arsenic and antimony are metalloids, and bismuth is a typical metal. Because moscovium has a very short half-life and is available only in trace amounts, its chemistry is not yet established, so it is set aside in NEET-level study.

The occurrence of the two lightest members reflects their biological importance. Molecular nitrogen makes up about 78% by volume of the atmosphere, and in the earth's crust it occurs as sodium nitrate $\ce{NaNO3}$ (Chile saltpetre) and potassium nitrate (Indian saltpetre); it is also bound in the proteins of plants and animals. Phosphorus occurs in minerals of the apatite family such as fluorapatite $\ce{Ca9(PO4)6.CaF2}$, the main component of phosphate rocks, and is an essential constituent of bones and living cells. Arsenic, antimony and bismuth occur mainly as sulphide minerals.

ElementSymbolZCharacterPrincipal source
NitrogenN7Non-metalAtmosphere (78% by vol.), nitrates
PhosphorusP15Non-metalApatite / phosphate rock
ArsenicAs33MetalloidSulphide minerals
AntimonySb51MetalloidSulphide minerals
BismuthBi83MetalSulphide minerals

Electronic Configuration

The valence-shell electronic configuration of every Group 15 element is $ns^2np^3$. The $s$ orbital is completely filled and the three $p$ orbitals are each singly occupied — a half-filled $p$ subshell. This half-filled arrangement carries extra exchange-energy stability, and the consequences of that stability ripple through almost every trend in the group, most visibly in the unusually high ionisation enthalpy.

ElementConfiguration
N[He] 2s² 2p³
P[Ne] 3s² 3p³
As[Ar] 3d¹⁰ 4s² 4p³
Sb[Kr] 4d¹⁰ 5s² 5p³
Bi[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p³

Covalent and ionic radii increase down the group, but not uniformly. There is a considerable jump in covalent radius from N to P; from As to Bi, however, only a small increase is observed because the heavier members carry completely filled $d$ and/or $f$ orbitals that screen the nuclear charge poorly, pulling the outer shell inward.

Ionisation enthalpy decreases down the group as atomic size grows. Two points carry NEET weight. First, owing to the extra-stable half-filled $p$ configuration and smaller size, the ionisation enthalpy of Group 15 elements is markedly greater than that of the Group 14 elements in the same period. Second, successive ionisation enthalpies follow the expected order $\Delta_iH_1 < \Delta_iH_2 < \Delta_iH_3$.

Figure 1 · Trend chart

First ionisation enthalpy of Group 15 elements ($\Delta_iH_1$ in kJ mol⁻¹), showing the overall decrease down the group with the characteristic high N value.

ΔiH₁ / kJ mol⁻¹ 1402 1012 947 834 703 N P As Sb Bi

Electronegativity generally decreases down the group with increasing atomic size, though among the heavier elements the difference is not pronounced (As, Sb and Bi cluster near 1.9–2.0). Metallic character increases down the group, a direct consequence of the falling ionisation enthalpy and rising atomic size. All Group 15 elements are polyatomic: dinitrogen is a diatomic gas while the rest are solids. Boiling points generally rise down the group, whereas the melting point rises up to arsenic and then falls towards bismuth.

NEET Trap

Ionisation enthalpy: Group 15 vs Group 14 and 16

Students often assume ionisation enthalpy falls smoothly across a period. It does not for Group 15. The half-filled $ns^2np^3$ shell is extra stable, so removing an electron is harder than expected — the ionisation enthalpy of Group 15 elements exceeds that of the neighbouring Group 14 (and even Group 16) elements in the same period.

Half-filled stability ⇒ anomalously high ionisation enthalpy for the N family.

Oxidation States

The common oxidation states of Group 15 elements are −3, +3 and +5. Two opposing trends govern them. The tendency to show the −3 state decreases down the group as size and metallic character grow — bismuth scarcely forms any −3 compound. The stability of the +5 state also decreases down the group, while the +3 state becomes more stable, owing to the inert pair effect: the $ns^2$ pair becomes increasingly reluctant to participate in bonding. The only well-characterised Bi(V) compound is $\ce{BiF5}$.

Nitrogen is exceptionally versatile with oxygen, additionally showing +1, +2 and +4 states (as in its various oxides). It does not, however, form compounds in the +5 state with halogens, because it lacks $d$ orbitals to accommodate the extra bonding electrons. Phosphorus also shows +1 and +4 states in some oxoacids.

A signature reactivity pattern is disproportionation. For nitrogen, all oxidation states from +1 to +4 tend to disproportionate in acid solution, for example:

$$\ce{3HNO2 -> HNO3 + H2O + 2NO}$$

Nearly all intermediate oxidation states of phosphorus disproportionate into +5 and −3, in both alkali and acid. For arsenic, antimony and bismuth, by contrast, the +3 state becomes increasingly stable against disproportionation down the group.

NEET Trap

Covalency ceiling of nitrogen

Nitrogen is restricted to a maximum covalency of four — only one $s$ and three $p$ orbitals are available for bonding. The heavier elements have vacant $d$ orbitals and can expand their covalence, as in $\ce{PF6^-}$. This is why $\ce{NCl5}$ does not exist but $\ce{PCl5}$ does.

No $d$ orbitals in N ⇒ covalency ≤ 4 ⇒ no pentahalide of nitrogen.

Go deeper

The +5/+3 oxidation interplay drives the chemistry of ammonia and nitric acid — the most heavily tested compounds of nitrogen.

Anomalous Behaviour of Nitrogen

Nitrogen differs sharply from the rest of its group because of four linked features: small size, high electronegativity, high ionisation enthalpy and the absence of $d$ orbitals. The most consequential effect is nitrogen's unique ability to form $p\pi$–$p\pi$ multiple bonds with itself and with other small, electronegative atoms such as carbon and oxygen. Heavier Group 15 atoms have orbitals so large and diffuse that effective $p\pi$–$p\pi$ overlap is not possible.

Consequently, nitrogen exists as a diatomic molecule with a triple bond — one $\sigma$ and two $\pi$ — and a very high bond enthalpy of 941.4 kJ mol⁻¹:

$$\ce{N#N} \qquad (\Delta_{diss}H = 941.4~\text{kJ mol}^{-1})$$

Phosphorus, arsenic and antimony instead form single bonds (P–P, As–As, Sb–Sb), and bismuth forms metallic bonds in the elemental state. Curiously, the single N–N bond is weaker than the single P–P bond, because the short N–N bond length forces strong interelectronic repulsion between the non-bonding lone pairs. This weak single bond is exactly why nitrogen has a poor catenation tendency compared with phosphorus.

The absence of $d$ orbitals also means nitrogen cannot form $d\pi$–$p\pi$ bonds, which the heavier members manage in species such as $\ce{R3P=O}$ and $\ce{R3P=CH2}$. Phosphorus and arsenic can even form $d\pi$–$d\pi$ bonds with transition metals when ligands like $\ce{P(C2H5)3}$ and $\ce{As(C6H5)3}$ coordinate.

Hydrides of Group 15

Every Group 15 element forms a hydride of the type $\ce{EH3}$ — $\ce{NH3}$, $\ce{PH3}$, $\ce{AsH3}$, $\ce{SbH3}$ and $\ce{BiH3}$ — and these show a remarkably regular gradation. Stability, measured by the E–H bond dissociation enthalpy, decreases from $\ce{NH3}$ to $\ce{BiH3}$. As the bond weakens, the hydride gives up hydrogen more readily, so reducing character increases down the series: ammonia is only a mild reducing agent whereas $\ce{BiH3}$ is the strongest reducing agent among them. Basicity falls in the order:

$$\ce{NH3 > PH3 > AsH3 > SbH3 > BiH3}$$

Two further trends matter. The bond angle (H–E–H) decreases from 107.8° in $\ce{NH3}$ to roughly 91° by $\ce{SbH3}$, as the bonding shifts toward almost pure $p$ orbitals down the group. Boiling points show an anomaly at the top: $\ce{NH3}$ has a higher melting and boiling point than $\ce{PH3}$ because the small, highly electronegative nitrogen lets $\ce{NH3}$ associate through intermolecular hydrogen bonding in the solid and liquid states.

PropertyNH₃PH₃AsH₃SbH₃BiH₃
Boiling point / K238.5185.5210.6254.6
E–H distance / pm101.7141.9151.9170.7
H–E–H angle / °107.893.691.891.3
ΔfH° / kJ mol⁻¹−46.1+13.4+66.4+145.1
StabilityDecreases NH₃ → BiH₃ (reducing power increases in the same direction)
Figure 2 · Hydride property trend

Two coupled trends across the $\ce{EH3}$ series: H–E–H bond angle (filled markers, left) collapses toward 90°, while reducing character (open arrow, right) rises.

H–E–H angle (°) 107.8 93.6 91.8 91.3 reducing character increases NH₃ PH₃ AsH₃ SbH₃
NEET Trap

Boiling point: NH₃ is the exception, not the rule

Down the $\ce{EH3}$ series the boiling point order is $\ce{NH3 > PH3 < AsH3 < SbH3}$ — $\ce{PH3}$ dips below $\ce{NH3}$ because $\ce{PH3}$ has no hydrogen bonding. Do not blindly extend "boiling point increases with molar mass": hydrogen bonding lifts $\ce{NH3}$ out of order, exactly as $\ce{H2O}$ stands out in Group 16.

$\ce{NH3}$ H-bonds ⇒ b.p.($\ce{NH3}$) > b.p.($\ce{PH3}$).

Oxides and Oxoacids

Each Group 15 element forms two principal oxide types, $\ce{E2O3}$ and $\ce{E2O5}$, corresponding to the +3 and +5 states. The oxide in the higher oxidation state is more acidic than that in the lower state, and acidic character of the oxides decreases down the group. The $\ce{E2O3}$ oxides trace the metal–non-metal trend precisely: those of nitrogen and phosphorus are purely acidic, arsenic and antimony are amphoteric, and bismuth is predominantly basic.

ElementE₂O₃ (lower)E₂O₅ (higher)Acid–base nature of E₂O₃
N$\ce{N2O3}$$\ce{N2O5}$Acidic
P$\ce{P2O3}$$\ce{P2O5}$Acidic
As$\ce{As2O3}$$\ce{As2O5}$Amphoteric
Sb$\ce{Sb2O3}$$\ce{Sb2O5}$Amphoteric
Bi$\ce{Bi2O3}$(only $\ce{BiF5}$ for +5)Basic

Reactivity toward halogens parallels this: the elements form $\ce{EX3}$ and $\ce{EX5}$ halides, except that nitrogen forms no pentahalide. Pentahalides are more covalent than trihalides because the element in the +5 state has greater polarising power than in the +3 state. All trihalides except those of nitrogen are stable. The corresponding oxoacids — $\ce{HNO2}$, $\ce{HNO3}$ and the family of phosphorus oxoacids — are treated separately in the sibling notes.

Allotropy

Except nitrogen, all the elements of Group 15 show allotropy. Nitrogen exists only as the diatomic $\ce{N2}$ molecule; its strong $p\pi$–$p\pi$ triple bond leaves no room for the structural variation seen further down. Phosphorus is the textbook case, with white, red and black allotropes built from $\ce{P4}$ tetrahedra and chains. Arsenic and antimony display grey (metallic) and yellow forms, and the metallic grey allotrope dominates as one moves toward bismuth.

The progression from a single molecular form (N) to multiple solid allotropes mirrors the rising metallic character of the group: the heavier the element, the more readily it adopts extended, metal-like solid structures.

Quick Recap

Group 15 in one screen

  • Configuration: $ns^2np^3$ — half-filled $p$ gives extra stability and an anomalously high ionisation enthalpy (higher than Groups 14 and 16).
  • Down the group: radii ↑, ionisation enthalpy ↓, electronegativity ↓, metallic character ↑; non-metal → metalloid → metal.
  • Oxidation states: −3, +3, +5. Stability of +5 ↓ and +3 ↑ down the group (inert pair effect); only stable Bi(V) species is $\ce{BiF5}$.
  • Anomalous N: small size, no $d$ orbitals ⇒ covalency ≤ 4, no pentahalide, strong $p\pi$–$p\pi$ triple bond ($\ce{N2}$, 941.4 kJ mol⁻¹), weak catenation, no allotropy.
  • Hydrides $\ce{EH3}$: stability and basicity ↓, reducing power ↑, bond angle ↓ from $\ce{NH3}$ to $\ce{BiH3}$; $\ce{NH3}$ b.p. > $\ce{PH3}$ due to H-bonding.
  • Oxides: $\ce{E2O3}$ and $\ce{E2O5}$; higher state more acidic; acidity ↓ down the group (acidic → amphoteric → basic).

NEET PYQ Snapshot — Group 15 Nitrogen Family

Real NEET items that test the general characteristics of Group 15. Where the bank holds no direct match, a concept drill is provided.

NEET 2025 · Q.70

Statement I: Like nitrogen that can form ammonia, arsenic can form arsine. Statement II: Antimony cannot form antimony pentoxide. In the light of the above statements, choose the most appropriate answer.

  1. Statement I is incorrect but Statement II is correct
  2. Both Statement I and Statement II are correct
  3. Both Statement I and Statement II are incorrect
  4. Statement I is correct but Statement II is incorrect
Answer: (4)

All Group 15 elements form $\ce{EH3}$ hydrides, so nitrogen forms $\ce{NH3}$ and arsenic forms arsine $\ce{AsH3}$ — Statement I is correct. They also form two oxide types $\ce{E2O3}$ and $\ce{E2O5}$, so antimony does form antimony pentoxide $\ce{Sb2O5}$ — Statement II is incorrect.

Concept · Anomalous N

Though nitrogen exhibits the +5 oxidation state, it does not form a pentahalide. The correct reason is:

  1. Nitrogen has no $d$ orbitals to expand its covalence beyond four
  2. Nitrogen is too electropositive
  3. The +5 state of nitrogen is unstable to disproportionation
  4. Halogens cannot oxidise nitrogen
Answer: (1)

With $n = 2$, nitrogen has only $s$ and $p$ orbitals; it has no $d$ orbitals to accommodate the extra bonding electrons, so its maximum covalency is four and $\ce{NCl5}$ does not exist while $\ce{PCl5}$ does.

FAQs — Group 15 Nitrogen Family

High-yield conceptual questions on the general characteristics of the nitrogen family.

Why does nitrogen not form a pentahalide while phosphorus does?
Nitrogen has only n = 2 with s and p orbitals available; it has no d orbitals to expand its covalence beyond four. Phosphorus and the heavier elements have vacant d orbitals in the outermost shell that can be used for bonding, so they form pentahalides such as PCl5 while nitrogen is restricted to a maximum covalency of four.
Why is the boiling point of NH3 higher than that of PH3?
Because of the high electronegativity and small size of nitrogen, NH3 molecules are associated through intermolecular hydrogen bonding in the solid and liquid states. PH3 molecules are not hydrogen bonded, so the boiling point of PH3 is lower than that of NH3.
How does the stability of the +5 oxidation state change down Group 15?
The stability of the +5 oxidation state decreases down the group while that of the +3 state increases, due to the inert pair effect. The only well characterised Bi(V) compound is BiF5, showing how unstable +5 is at the bottom of the group.
Why does the reducing character of Group 15 hydrides increase from NH3 to BiH3?
The stability of the hydrides decreases from NH3 to BiH3, as seen from their decreasing E–H bond dissociation enthalpy. As the bond weakens, the hydride releases hydrogen more readily, so the reducing character increases. Ammonia is only a mild reducing agent while BiH3 is the strongest reducing agent among the hydrides.
Why does nitrogen exist as a diatomic gas while phosphorus is a solid?
Nitrogen, being small and highly electronegative, forms strong pπ–pπ multiple bonds, so two N atoms share a triple bond giving the very stable diatomic N2 molecule with a high bond enthalpy of 941.4 kJ per mol. Heavier elements have large diffuse orbitals that cannot overlap effectively for pπ–pπ bonding, so phosphorus forms P–P single bonds in a polyatomic solid (P4).