Chemistry · The p-Block Elements (Class 11)

Group 14 — Carbon Family (General)

Group 14 — carbon, silicon, germanium, tin and lead — is the second of the two p-block families studied in this chapter. Built on the supplementary NCERT treatment (old §11.5) and reinforced by NIOS Chapters 18–19, this note develops the family's $ns^2np^2$ valence configuration and the trends it produces: covalent radius, ionisation enthalpy, electronegativity, the rivalry between the $+4$ and $+2$ oxidation states, the catenating power of carbon and the anomalous behaviour of the first member. These periodic trends are recurring NEET territory, and the inert pair effect in particular surfaces almost every cycle.

The Family at a Glance

The members of Group 14 are carbon (C), silicon (Si), germanium (Ge), tin (Sn) and lead (Pb), together with the synthetic radioactive element flerovium (Fl), whose chemistry has not been established. As one descends this column, the character of the elements shifts steadily from non-metal to metal: carbon and silicon are non-metals, germanium is a metalloid, and tin and lead are soft metals with low melting points. This non-metal-to-metal gradation is the unifying theme of the family, and almost every general trend below traces back to it.

Their natural occurrence underlines their importance. Carbon is the seventeenth most abundant element by mass in the crust and is found free as coal, graphite and diamond and combined as carbonates, hydrocarbons and atmospheric $\ce{CO2}$ (about $0.03\%$). Silicon is the second most abundant crustal element ($27.7\%$ by mass), present as silica and silicates. Germanium occurs only in traces; tin occurs mainly as cassiterite ($\ce{SnO2}$) and lead as galena ($\ce{PbS}$). Ultrapure germanium and silicon are the basis of transistors and semiconductor devices.

ElementSymbolCharacterChief source / form
CarbonCNon-metalCoal, graphite, diamond; carbonates, $\ce{CO2}$
SiliconSiNon-metalSilica, silicates
GermaniumGeMetalloidTraces; semiconductor grade
TinSnSoft metalCassiterite, $\ce{SnO2}$
LeadPbSoft metalGalena, $\ce{PbS}$

Electronic Configuration

The defining feature of the family is its valence-shell electronic configuration, $ns^2np^2$ — four electrons in the outermost shell. What changes down the group is the inner core: silicon onward, completely filled $d$ orbitals appear, and lead additionally carries a filled $4f^{14}$ set. Because these inner $d$ and $f$ electrons screen the nuclear charge poorly, the effective nuclear charge experienced by the valence electrons rises more than a simple shell count would suggest, and this perturbs every property that depends on it — size, ionisation enthalpy and the relative stability of the two oxidation states.

ElementZElectronic configuration
Carbon6$[\text{He}]\,2s^2 2p^2$
Silicon14$[\text{Ne}]\,3s^2 3p^2$
Germanium32$[\text{Ar}]\,3d^{10} 4s^2 4p^2$
Tin50$[\text{Kr}]\,4d^{10} 5s^2 5p^2$
Lead82$[\text{Xe}]\,4f^{14} 5d^{10} 6s^2 6p^2$

Three atomic properties shape the chemistry of Group 14, and each carries a small irregularity worth memorising.

Covalent radius

There is a considerable increase in covalent radius from C to Si, but thereafter, from Si to Pb, only a small increase is observed. The reason is the completely filled $d$ and $f$ orbitals in the heavier members: their poor screening lets the rising nuclear charge pull the outer electrons inward, partly offsetting the size increase expected from adding new shells.

Ionisation enthalpy

The first ionisation enthalpy of every Group 14 element is higher than that of the corresponding Group 13 element, reflecting the smaller size and the influence of the inner core. In general $\Delta_i H$ decreases down the group, but not smoothly: there is a small decrease from Si to Ge to Sn and then a slight increase from Sn to Pb, again the consequence of poor shielding by the intervening $d$ and $f$ orbitals together with the growing atomic size.

Electronegativity

Because of their small size, Group 14 elements are slightly more electronegative than the Group 13 elements. Carbon is distinctly the most electronegative member (2.5 on the Pauling scale), while the values for Si through Pb are almost the same (close to 1.8–1.9). All members of the group are solids; melting and boiling points are much higher than those of the corresponding Group 13 elements.

PropertyCSiGeSnPb
Valence configuration$2s^2 2p^2$$3s^2 3p^2$$4s^2 4p^2$$5s^2 5p^2$$6s^2 6p^2$
Covalent radiusLarge jump C → Si, then only a small increase Si → Pb
$\Delta_i H_1$Highest at C; decreases C → Sn, slight rise Sn → Pb
Electronegativity (Pauling)2.51.81.81.81.9
Common characterNon-metalNon-metalMetalloidMetalMetal
Stable oxidation state+4+4+4+4 / +2+2

Oxidation States and the Inert Pair

With four valence electrons, the family exhibits the common oxidation states $\mathbf{+4}$ and $\mathbf{+2}$ (carbon additionally shows negative states, as in $\ce{CH4}$). Because the sum of the first four ionisation enthalpies is very high, $+4$ compounds are essentially covalent, not ionic; for example, $\ce{CCl4}$ has eight electrons around carbon and is electron-precise.

The decisive trend is the growing stability of the lower $+2$ state on descending the group, expressed as $\ce{Ge < Sn < Pb}$. This is the inert pair effect: the $ns^2$ pair of the valence shell becomes increasingly reluctant to participate in bonding. NIOS Chapter 18 ascribes this to two factors — the rising promotion energy needed to take an atom from the ground state $ns^2np^2$ to a bonding state, and the poorer overlap of orbitals for the larger atoms, which yields weaker bonds that no longer repay the cost of unpairing. The net result is the lesser stability of the higher oxidation state with increasing atomic number.

Figure 1 · Trend schematic Relative stability Down the group → C Si Ge Sn Pb +4 +2

Schematic of the inert pair effect: the $+4$ state (solid teal) is most stable for the light members and weakens toward lead, while the $+2$ state (dashed coral) gains stability down the group until $\ce{Pb^2+}$ dominates.

The practical consequences are sharp. Carbon and silicon show essentially only the $+4$ state. Germanium forms stable $+4$ compounds and only a few in the $+2$ state. Tin uses both states, and $\ce{Sn^2+}$ is a reducing agent (readily oxidised to $\ce{Sn^4+}$). Lead is the opposite extreme: $\ce{Pb^2+}$ compounds are stable, whereas $\ce{Pb^4+}$ compounds are strong oxidising agents.

NEET Trap

Two trends that run in opposite directions

Examiners pair the inert pair effect with stability comparisons. Keep the two halves separate: the $+4$ state weakens down the group while the $+2$ state strengthens. So $\ce{Sn^2+}$ is a reducing agent (it wants to reach the still-favoured $+4$ state), but $\ce{Pb^4+}$ is an oxidising agent (it wants to fall to the favoured $+2$ state). Tendency to the $+2$ state increases as $\ce{Ge < Sn < Pb}$.

Carbon & silicon → +4 only · Sn²⁺ = reducing agent · Pb²⁺ stable, Pb⁴⁺ = strong oxidiser.

Catenation Down the Group

Catenation is the tendency of identical atoms to link through covalent bonds into chains and rings. Carbon does this prolifically — it is the foundation of the whole of organic chemistry — because the C–C bond is very strong. Down the group the atomic size increases and electronegativity decreases, so the M–M bond enthalpy falls and the catenating tendency declines steeply. The order established by bond enthalpies is:

$$\ce{C} \;\gg\; \ce{Si} \;>\; \ce{Ge} \;\approx\; \ce{Sn}$$

and lead does not show catenation at all. (The chapter summary writes the same order as $\ce{C} > \ce{Si} > \ce{Ge} \approx \ce{Sn} > \ce{Pb}$.)

Figure 2 · Catenation tendency M–M bond strength / catenation C Si Ge Sn Pb

Catenation falls off rapidly after carbon; Ge and Sn are nearly equal and weak, while lead (negligible bar) shows none. The single tall carbon bar captures why organic chemistry is the chemistry of carbon chains.

Catenation, combined with carbon's ability to form $p\pi$–$p\pi$ multiple bonds, is precisely what gives carbon its allotropy — the diamond, graphite and fullerene structures explored in the sibling note on the allotropes of carbon.

Go deeper

Catenation and $p\pi$–$p\pi$ bonding underpin the three crystalline forms of carbon — see Allotropes of Carbon for diamond, graphite and fullerene structures.

Anomalous Behaviour of Carbon

Like the first member of every p-block group, carbon stands apart from the rest of its family. The supplementary NCERT text and NIOS Chapter 18 attribute this to four interlinked causes: carbon's small size, higher electronegativity, higher ionisation enthalpy and the unavailability of $d$ orbitals in its valence shell. Two consequences are tested repeatedly.

First, with only $2s$ and $2p$ orbitals available, carbon can accommodate at most four electron pairs and so is limited to a maximum covalence of four. Heavier members expand their covalence using vacant $d$ orbitals — hence species such as $\ce{[SiF6]^2-}$, $\ce{[GeCl6]^2-}$ and $\ce{[Sn(OH)6]^2-}$ exist (with $sp^3d^2$ hybridisation of the central atom), while no analogous $\ce{[CF6]^2-}$ can form. The same limitation explains why $\ce{CCl4}$ resists hydrolysis whereas $\ce{SiCl4}$ hydrolyses readily.

Worked Example

$\ce{[SiF6]^2-}$ is known whereas $\ce{[SiCl6]^2-}$ is not. Why?

Two reasons (per the supplement): (i) six large chloride ions cannot be accommodated around the small $\ce{Si^4+}$ centre — a size limitation; and (ii) the interaction between the chloride lone pair and $\ce{Si^4+}$ is not strong enough. The compact fluoride ion has no such problem, so $\ce{[SiF6]^2-}$ forms while $\ce{[SiCl6]^2-}$ does not.

Second, only carbon (and the other small second-period elements) forms strong $p\pi$–$p\pi$ multiple bonds, both to itself and to small, electronegative partners: $\ce{C=C}$, $\ce{C#C}$, $\ce{C=O}$, $\ce{C=S}$ and $\ce{C#N}$. The heavier elements do not form such $p\pi$–$p\pi$ bonds because their atomic orbitals are too large and diffuse for effective sideways overlap.

NEET Trap

Carbon's "no d-orbital" rule cuts two ways

The absence of valence $d$ orbitals in carbon both caps its covalence at four and denies it $d\pi$–$p\pi$ bonding. That is why $\ce{CCl4}$ will not hydrolyse (no vacant orbital to accept water's lone pair) but $\ce{SiCl4}$ does, and why carbon makes $\ce{CO2}$ a discrete linear molecule while $\ce{SiO2}$ is a giant three-dimensional network solid.

No d-orbitals ⇒ max covalence 4 ⇒ CCl₄ inert to hydrolysis; SiCl₄ hydrolyses via d-orbitals.

General Chemical Reactivity

The general reactions of the family fall into three blocks, and the trends within each track the oxidation-state and acidity ideas above.

With oxygen

All members form oxides on heating, chiefly monoxides ($\ce{MO}$) and dioxides ($\ce{MO2}$). Oxides in the higher oxidation state are generally more acidic than those in the lower state. Among dioxides, $\ce{CO2}$, $\ce{SiO2}$ and $\ce{GeO2}$ are acidic, while $\ce{SnO2}$ and $\ce{PbO2}$ are amphoteric. Among monoxides, $\ce{CO}$ is neutral, $\ce{GeO}$ is distinctly acidic, and $\ce{SnO}$ and $\ce{PbO}$ are amphoteric.

Oxide typeCGeSn / Pb
Dioxide ($\ce{MO2}$)$\ce{CO2}$ acidic$\ce{GeO2}$ acidic$\ce{SnO2},\ \ce{PbO2}$ amphoteric
Monoxide ($\ce{MO}$)$\ce{CO}$ neutral$\ce{GeO}$ acidic$\ce{SnO},\ \ce{PbO}$ amphoteric

With water

Carbon, silicon and germanium are not affected by water. Tin decomposes steam to give the dioxide and dihydrogen, while lead is unaffected, probably because of a protective oxide film.

$$\ce{Sn + 2H2O ->[\Delta] SnO2 + 2H2}$$

With halogens

These elements form halides of types $\ce{MX2}$ and $\ce{MX4}$. Most tetrahalides are covalent and tetrahedral with $sp^3$ hybridisation of the central atom; exceptions $\ce{SnF4}$ and $\ce{PbF4}$ are ionic. Among the dihalides, stability increases down the group — consistent with the inert pair effect — so $\ce{GeX4}$ is more stable than $\ce{GeX2}$, whereas $\ce{PbX2}$ is more stable than $\ce{PbX4}$. Notably $\ce{PbI4}$ does not exist, because the $\ce{Pb-I}$ bond energy is too small to unpair and excite the $6s^2$ electrons needed for four bonds. Except $\ce{CCl4}$, the tetrachlorides hydrolyse, the central atom accepting the water oxygen's lone pair into a $d$ orbital, as illustrated by silicon:

$$\ce{SiCl4 + 4H2O -> Si(OH)4 + 4HCl}$$

Quick Recap

Group 14 in one screen

  • Members C, Si, Ge, Sn, Pb; valence configuration $ns^2np^2$; character grades non-metal → metalloid → metal.
  • Covalent radius jumps C → Si, then increases only slightly to Pb; $\Delta_i H$ falls C → Sn with a slight rise to Pb.
  • Common states $+4$ and $+2$; $+4$ compounds are covalent (high $\Sigma\Delta_i H$).
  • Inert pair effect: $+2$ stability rises $\ce{Ge < Sn < Pb}$; $\ce{Sn^2+}$ reduces, $\ce{Pb^4+}$ oxidises, $\ce{Pb^2+}$ is stable.
  • Catenation order $\ce{C} \gg \ce{Si} > \ce{Ge} \approx \ce{Sn}$; lead shows none.
  • Carbon anomaly: small size, no $d$ orbitals → max covalence 4 and strong $p\pi$–$p\pi$ bonds; $\ce{CCl4}$ resists hydrolysis, $\ce{SiCl4}$ does not.

NEET PYQ Snapshot — Group 14 — Carbon Family (General)

Group 14 general questions cluster on allotrope identity, oxidation-state stability and the inert pair effect. The first card below is from the official 2023 paper; the rest are concept cards drawn from the chapter's standard ideas.

NEET 2023

Match List-I (forms of carbon) with List-II and choose the correct option: A. Coke, B. Diamond, C. Fullerene, D. Graphite — with (I) carbon atoms $sp^3$ hybridised, (II) used as a dry lubricant, (III) used as reducing agent, (IV) cage-like molecules.

  • (1) A-III, B-IV, C-I, D-II
  • (2) A-II, B-IV, C-I, D-III
  • (3) A-IV, B-I, C-II, D-III
  • (4) A-III, B-I, C-IV, D-II
Answer: (4) A-III, B-I, C-IV, D-II

Coke is a metallurgical reducing agent (III); diamond is $sp^3$, tetrahedral (I); fullerene is a cage-like molecule (IV); graphite is soft and slippery, a dry lubricant (II). The catenating, $sp^3/sp^2$ versatility of carbon underlies all four forms.

Concept

Group 14 elements characteristically:

  • (1) exhibit oxidation state of $+4$ only
  • (2) exhibit oxidation states of $+2$ and $+4$
  • (3) form $\ce{M^2-}$ and $\ce{M^4+}$ ions
  • (4) form $\ce{M^2+}$ and $\ce{M^4+}$ ions
Answer: (2) +2 and +4

With four valence electrons ($ns^2np^2$) the common oxidation states are $+4$ and $+2$; high $\Sigma\Delta_i H$ makes ionic $\ce{M^4+}$ unfavourable, so the $+4$ compounds are covalent rather than ionic.

Concept

Which represents the correct order of catenation tendency in Group 14?

  • (1) $\ce{Pb > Sn > Ge > Si > C}$
  • (2) $\ce{C > Si > Ge \approx Sn}$, Pb negligible
  • (3) $\ce{Si > C > Ge > Sn}$
  • (4) all members catenate equally
Answer: (2)

M–M bond enthalpy falls as size increases and electronegativity decreases down the group, so catenation decreases as $\ce{C} \gg \ce{Si} > \ce{Ge} \approx \ce{Sn}$, with lead showing essentially none.

Concept

Taking stability into account, which species is the more stable in each case as a consequence of the inert pair effect?

  • (1) $\ce{Pb^4+}$ over $\ce{Pb^2+}$
  • (2) $\ce{Sn^4+}$ unstable relative to $\ce{Sn^2+}$ in every compound
  • (3) $\ce{Pb^2+}$ stable; $\ce{Pb^4+}$ a strong oxidising agent
  • (4) carbon prefers the $+2$ state
Answer: (3)

The $+2$ state strengthens down the group ($\ce{Ge < Sn < Pb}$). For lead the $6s^2$ pair is inert, so $\ce{Pb^2+}$ is the stable state and $\ce{Pb^4+}$ acts as a strong oxidising agent; carbon, by contrast, is firmly $+4$.

FAQs — Group 14 — Carbon Family (General)

High-yield clarifications on the carbon family's trends, drawn from the supplementary NCERT text and NIOS Chapters 18–19.

What is the correct order of catenation in Group 14?

The tendency to catenation decreases down the group as C >> Si > Ge ≈ Sn, and lead does not show catenation. This follows the fall in M–M bond enthalpy as atomic size increases and electronegativity decreases down the group. Carbon's exceptionally strong C–C bonds make its catenation far greater than that of every heavier member.

Why does the stability of the +2 oxidation state increase down Group 14?

Down the group the ns² electrons of the valence shell become increasingly reluctant to take part in bonding, an effect called the inert pair effect. This arises from the rise in promotion energy from ns²np² to the bonding state and from poorer orbital overlap for the larger atoms. As a result the tendency to show the +2 state increases as Ge < Sn < Pb, and Pb²⁺ is the stable state of lead, whereas Pb⁴⁺ acts as a strong oxidising agent.

What is the valence-shell electronic configuration of Group 14 elements?

Every Group 14 element has the valence-shell configuration ns²np², with four electrons in the outermost shell. The configurations are C [He]2s²2p², Si [Ne]3s²3p², Ge [Ar]3d¹⁰4s²4p², Sn [Kr]4d¹⁰5s²5p² and Pb [Xe]4f¹⁴5d¹⁰6s²6p². The differing inner cores influence the size, ionisation enthalpy and chemistry of the heavier members.

Why does carbon differ so markedly from the rest of its group?

Carbon shows anomalous behaviour because of its small size, higher electronegativity, higher ionisation enthalpy and the absence of d orbitals in its valence shell. Having only 2s and 2p orbitals, carbon is limited to a maximum covalence of four, whereas heavier members can expand their covalence using d orbitals. Carbon's small size also lets it form strong pπ–pπ multiple bonds (C=C, C≡C, C=O, C≡N) that the heavier elements cannot.

Why is the covalent radius increase from C to Si large but small from Si to Pb?

There is a considerable increase in covalent radius from carbon to silicon, but only a small increase thereafter from Si to Pb. This is because the heavier members carry completely filled d (and, for Pb, f) orbitals in their inner core. These inner electrons screen the nuclear charge poorly, so the increased effective nuclear charge holds the outer electrons more tightly and suppresses the size increase expected from adding new shells.

Why do tetrahalides such as SiCl₄ hydrolyse while CCl₄ does not?

In CCl₄ the carbon atom is surrounded by eight electrons and, lacking d orbitals, cannot accept a lone pair from water, so it resists hydrolysis. Silicon and the heavier members possess vacant d orbitals into which the oxygen lone pair of water can be accepted; SiCl₄ therefore hydrolyses readily to give Si(OH)₄. This contrast is a direct consequence of carbon's anomalous inability to expand its covalence beyond four.