Chemistry · The p-Block Elements (Class 11)

Group 13 — Boron Family (General)

Group 13 — the boron family — runs $\ce{B}$, $\ce{Al}$, $\ce{Ga}$, $\ce{In}$, $\ce{Tl}$, all sharing the valence configuration $ns^2np^1$. This subtopic, drawn from the old-NCERT supplement on the p-block (§11.1) and reinforced by NIOS Chapters 18–19, traces how one extra inner-shell core at each step bends the trends in atomic radius, ionisation enthalpy and electronegativity, and why the inert pair effect makes the $+1$ state overtake $+3$ as we descend. Although the chapter has been rationalised out of the current syllabus, its trends, the anomalous behaviour of boron, and the stability of $\ce{Tl+}$ remain recurring NEET fodder.

Members and Electronic Configuration

Group 13 of the periodic table is headed by boron and comprises five elements studied here: boron ($\ce{B}$), aluminium ($\ce{Al}$), gallium ($\ce{Ga}$), indium ($\ce{In}$) and thallium ($\ce{Tl}$). The synthetically prepared radioactive element nihonium ($\ce{Nh}$, $Z=113$) also belongs to the group, but its chemistry is not established and it is left out of property discussions. The family spans the full metallic gradient: boron is a typical non-metal, aluminium is a metal with several chemical similarities to boron, and gallium, indium and thallium are almost exclusively metallic in character.

The defining feature of the group is the outer electronic configuration $ns^2np^1$ — three valence electrons available for bonding. What changes down the group is the inner core beneath those valence electrons. Boron and aluminium sit on a noble-gas core; gallium and indium carry an additional ten $d$-electrons; thallium carries ten $d$- plus fourteen $f$-electrons. This difference in core makes the electronic structure of the heavier members far more complex than that of the group 1 and group 2 elements, and it is the root cause of the irregularities in their atomic and chemical properties.

ElementSymbolAtomic numberValence configurationFull core notation
BoronB5$2s^2 2p^1$$[\ce{He}]2s^2 2p^1$
AluminiumAl13$3s^2 3p^1$$[\ce{Ne}]3s^2 3p^1$
GalliumGa31$4s^2 4p^1$$[\ce{Ar}]3d^{10}4s^2 4p^1$
IndiumIn49$5s^2 5p^1$$[\ce{Kr}]4d^{10}5s^2 5p^1$
ThalliumTl81$6s^2 6p^1$$[\ce{Xe}]4f^{14}5d^{10}6s^2 6p^1$

Atomic and Physical Data

The atomic and physical constants of the group, taken from the supplement's Table 11.2, are the quantitative backbone for every trend discussed below. Read the table not as numbers to memorise but as evidence: the deviations in radius and ionisation enthalpy are exactly where the inner-core $d$- and $f$-electrons leave their fingerprints.

PropertyBAlGaInTl
Atomic mass / g mol⁻¹10.8126.9869.72114.82204.38
Atomic radius / pm143135167170
$\Delta_iH_1$ / kJ mol⁻¹801577579558589
$\Delta_iH_2$ / kJ mol⁻¹24271816197918201971
$\Delta_iH_3$ / kJ mol⁻¹36592744296227042877
Electronegativity (Pauling)2.01.51.61.71.8
Density / g cm⁻³ (298 K)2.352.705.907.3111.85
Melting point / K2453933303430576
$E^\circ$ (M³⁺/M) / V−1.66−0.56−0.34+1.26

Physical character. Boron is non-metallic — an extremely hard, black solid existing in several allotropic forms; its very strong crystalline lattice gives it an unusually high melting point. The remaining members are soft metals of low melting point and high electrical conductivity. Gallium is a striking exception with a melting point of only 303 K, so it can melt in the hand and exist as a liquid in summer; its very high boiling point (2676 K) makes it useful for measuring high temperatures. Density rises steadily from boron to thallium.

Trend in Atomic Radii

On descending a group one extra electron shell is added at each step, so atomic radius is expected to increase smoothly. The boron family obeys this only partly. The genuine anomaly is that the atomic radius of gallium (135 pm) is smaller than that of aluminium (143 pm) — a reversal of the expected trend.

The cause lies in the inner core. Between aluminium and gallium, ten $3d$-electrons are inserted. These $d$-electrons screen the nuclear charge poorly, so the outermost electrons of gallium feel a higher effective nuclear charge and are drawn inward, shrinking the atom. The same poor screening by intervening $d$- and $f$-electrons recurs lower in the group and underlies the irregular ionisation pattern discussed next.

Figure 1 · Schematic radius / pm Al 143 Ga 135 In 167 Tl 170 Ga < Al (d-contraction)

The expected rise in radius down the group is interrupted at gallium: insertion of ten poorly screening $3d$-electrons raises the effective nuclear charge so that $r(\ce{Ga}) < r(\ce{Al})$.

Ionisation Enthalpy and Electronegativity

Ionisation enthalpy does not fall smoothly down the group as the simple "size increases, electrons leave easily" rule would predict. The decrease from $\ce{B}$ to $\ce{Al}$ is associated with the expected increase in size. But there is a clear discontinuity between $\ce{Al}$ and $\ce{Ga}$, and again between $\ce{In}$ and $\ce{Tl}$: at these steps the newly added $d$- (and later $f$-) electrons screen poorly and fail to offset the larger nuclear charge, so ionisation enthalpy does not drop as expected. For each element the order is, predictably, $\Delta_iH_1 < \Delta_iH_2 < \Delta_iH_3$, and the sum of the first three is very high — a fact that decides their chemistry.

Electronegativity follows a matching zig-zag: it first decreases from $\ce{B}$ ($2.0$) to $\ce{Al}$ ($1.5$), then increases marginally down to thallium ($1.8$). This non-monotonic behaviour is again a consequence of the discrepancies in atomic size produced by the inner $d$- and $f$-cores.

NEET Trap

Ionisation enthalpy down group 13 is not a smooth decrease

Students often assume $\Delta_iH_1$ falls steadily $\ce{B} > \ce{Al} > \ce{Ga} > \ce{In} > \ce{Tl}$. It does not: the values dip from $\ce{B}$ to $\ce{Al}$, then rise slightly at $\ce{Ga}$ and again at $\ce{Tl}$ because of poor $d$/$f$ screening. Electronegativity shows the same minimum at $\ce{Al}$, not a clean downward trend.

Remember the shape: minimum at Al, then a marginal rise to Tl — both for ionisation enthalpy and electronegativity.

Oxidation States and the Inert Pair Effect

The group oxidation state is $+3$, matching the three valence electrons. For the lighter members this is the dominant state. As we go down, however, a $+1$ state — two units below the group state — appears and grows in importance. This is the celebrated inert pair effect.

The mechanism is straightforward. Down the group the intervening $d$- and $f$-orbitals shield poorly, so the increased effective nuclear charge holds the $ns^2$ pair tightly and restricts its participation in bonding; only the lone $np^1$ electron is then used. NIOS §18.9 attributes this reluctance to two energetic factors: the high promotion energy needed to reach the bonding-ready valence state, and the poorer orbital overlap (hence weaker bonds) for the large heavy atoms. The relative stability of the $+1$ state therefore rises in the sequence $\ce{Al} < \ce{Ga} < \ce{In} < \ce{Tl}$. In thallium the $+1$ state is predominant, while $\ce{Tl^3+}$ is a powerful oxidising agent.

Figure 2 · Schematic Relative stability of oxidation states down Group 13 B Al Ga In Tl +3 stability decreases → +1 stability increases →

As the inert pair effect strengthens down the group, the $+3$ state loses stability while the $+1$ state gains it; at thallium the two cross over and $\ce{Tl+}$ becomes the favoured state.

The standard electrode potentials make the crossover quantitative. For aluminium $E^\circ(\ce{Al^3+}/\ce{Al}) = -1.66\ \text{V}$, showing a strong drive to form $\ce{Al^3+}(aq)$; aluminium is a highly electropositive metal. For thallium $E^\circ(\ce{Tl^3+}/\ce{Tl}) = +1.26\ \text{V}$, so $\ce{Tl^3+}$ is unstable in solution and a powerful oxidiser — hence $\ce{Tl+}$ is more stable than $\ce{Tl^3+}$. Energetically, compounds in the $+1$ state are more ionic than those in the $+3$ state.

NEET Trap

$\ce{Tl+}$ is more stable than $\ce{Tl^3+}$ — stability of dihalides vs trihalides

Because of the inert pair effect at its strongest in thallium, the lower-state compound is favoured: $\ce{TlI}$ is more stable than $\ce{TlI3}$, and $\ce{TlCl}$ is more stable than $\ce{TlCl3}$. Contrast this with the lighter members, where the trihalide is the stable form — for aluminium $\ce{AlCl3}$ is far more stable than $\ce{AlCl}$, and for indium $\ce{InI3} > \ce{InI}$.

Down the group the $+1$ halide wins; up the group the $+3$ halide wins. The crossover is essentially at Tl.

Go deeper

The electron deficiency that makes these +3 species Lewis acids is fully developed in the chemistry of borax, boric acid and diborane — see Important Compounds of Boron.

Chemical Reactivity

The high sum of the first three ionisation enthalpies dictates the bonding mode. In boron this sum is so large that $\ce{B^3+}$ ions never form; boron is forced into purely covalent compounds. From $\ce{B}$ to $\ce{Al}$ the sum falls considerably, so aluminium readily forms $\ce{Al^3+}$ and acts as a highly electropositive metal. In trivalent compounds the central atom carries only six electrons (as in $\ce{BF3}$); such electron-deficient molecules accept a lone pair to complete the octet and so behave as Lewis acids, the strength of which falls as size grows down the group.

Lewis acid behaviour

How does $\ce{BF3}$ react with ammonia, and why?

$\ce{BF3}$ has only six electrons around boron — it is electron deficient. Ammonia donates its lone pair to complete boron's octet, forming a stable adduct:

$$\ce{BF3 + :NH3 -> F3B<-NH3}$$

Likewise $\ce{BCl3}$ accepts a lone pair from ammonia to give $\ce{BCl3.NH3}$.

Reactivity towards air

Crystalline boron is unreactive. Aluminium develops a thin protective oxide layer that shields the metal from further attack. On heating in air, amorphous boron and aluminium form their oxides, and with dinitrogen at high temperature they form nitrides:

$$\ce{4Al + 3O2 ->[\Delta] 2Al2O3} \qquad \ce{2Al + N2 ->[\Delta] 2AlN}$$

The acid–base character of the oxides shifts down the group: $\ce{B2O3}$ is acidic and reacts with basic oxides to give borates; $\ce{Al2O3}$ and $\ce{Ga2O3}$ are amphoteric; the oxides of indium and thallium are basic.

Reactivity towards acids and alkalies

Boron does not react with acids or alkalies even at moderate temperature. Aluminium, by contrast, is amphoteric — it dissolves in both mineral acids and aqueous alkalies, liberating dihydrogen:

$$\ce{2Al + 6HCl -> 2AlCl3 + 3H2}$$

$$\ce{2Al + 2NaOH + 6H2O -> 2Na[Al(OH)4] + 3H2}$$

Concentrated nitric acid, however, renders aluminium passive by building a protective oxide film, which is why $\ce{conc. HNO3}$ can be transported in aluminium containers.

Reactivity towards halogens

All these elements react with halogens to form trihalides (the lone exception being $\ce{TlI3}$, which does not exist as a true thallium(III) iodide):

$$\ce{2E + 3X2 -> 2EX3} \quad (\text{E = element; X = F, Cl, Br, I})$$

The monomeric trihalides are electron deficient and act as strong Lewis acids. Boron's maximum covalence is fixed at four ($\ce{BF4-}$) for want of $d$-orbitals, but heavier members complete their octet by halogen bridging — aluminium chloride dimerises to $\ce{Al2Cl6}$, each aluminium accepting electrons from a bridging chlorine.

Anomalous Behaviour of Boron

As the first member of the group, boron differs markedly from its heavier congeners. The reasons echo the lithium–beryllium diagonal anomaly of the s-block: boron's small size, high ionisation enthalpy, high electronegativity, and crucially the absence of $d$-orbitals in its valence shell.

The lack of $d$-orbitals caps boron's covalence at four — it can hold only four electron pairs, so it forms $\ce{BF4-}$ but never $\ce{BF6^3-}$. Aluminium and the heavier elements, having vacant $d$-orbitals, expand their covalence to six and form ions such as $\ce{AlF6^3-}$. This single structural fact explains a whole cluster of boron's peculiarities and is a favourite NEET discriminator.

FeatureBoron (first member)Aluminium and heavier members
Metallic characterNon-metal, hard, high m.p.Metals, soft, lower m.p.
Valence $d$-orbitalsAbsent → max covalence 4Available → covalence up to 6
Highest fluoro-complex$\ce{BF4-}$ only (no $\ce{BF6^3-}$)$\ce{AlF6^3-}$ exists
Bonding mode in +3Always covalent ($\Delta_iH$ sum very high)$\ce{Al}$ forms ionic $\ce{Al^3+}$
Action of acids/alkaliesUnreactive at moderate temp.$\ce{Al}$ amphoteric, dissolves in both
Nature of oxide$\ce{B2O3}$ acidic$\ce{Al2O3}$ amphoteric; $\ce{In, Tl}$ oxides basic
Quick Recap

Group 13 in one screen

  • Members $\ce{B}, \ce{Al}, \ce{Ga}, \ce{In}, \ce{Tl}$; common valence configuration $ns^2np^1$; inner core changes (noble gas → $+10d$ → $+10d, 14f$).
  • Atomic radius rises down the group except $r(\ce{Ga}) < r(\ce{Al})$, owing to poor screening by $3d$-electrons.
  • Ionisation enthalpy and electronegativity dip to a minimum at $\ce{Al}$, then rise marginally — not a smooth fall.
  • Oxidation states $+3$ (group state) and $+1$; inert pair effect makes $+1$ stability rise $\ce{Al} < \ce{Ga} < \ce{In} < \ce{Tl}$, so $\ce{Tl+} > \ce{Tl^3+}$ in stability.
  • Trivalent species are electron-deficient Lewis acids; $\ce{Al}$ is amphoteric ($\ce{2Al + 6HCl -> 2AlCl3 + 3H2}$; $\ce{2Al + 2NaOH + 6H2O -> 2Na[Al(OH)4] + 3H2}$).
  • Boron is anomalous: small, no $d$-orbitals, covalence capped at 4, no $\ce{BF6^3-}$; $\ce{B2O3}$ acidic.

NEET PYQ Snapshot — Group 13 — Boron Family (General)

Real NEET questions on the inert pair effect, the stability of $\ce{Tl+}$, and the anomalous covalence of boron.

NEET 2023 · Q.80

Taking stability as the factor, which one of the following represents the correct relationship?

  1. $\ce{TlI} > \ce{TlI3}$
  2. $\ce{TlCl3} > \ce{TlCl}$
  3. $\ce{InI3} > \ce{InI}$
  4. $\ce{AlCl} > \ce{AlCl3}$
Answer: (1)

Down the group, poor shielding by intervening $d$ and $f$ orbitals raises the effective nuclear charge, holding the $ns$ electrons tightly and restricting their participation in bonding (inert pair effect). The $+1$ state therefore becomes more stable for the heavier elements. With $E^\circ(\ce{Tl^3+}/\ce{Tl+}) = +1.6\ \text{V}$, $\ce{Tl^3+}$ is a strong oxidiser, so $\ce{Tl+}$ is more stable — hence $\ce{TlI} > \ce{TlI3}$. Options (2) and (3) correctly favour $+1$ for Tl yet are written backwards, and Al/In favour the $+3$ form.

NEET 2018 · Q.63

Which one of the following elements is unable to form an $\ce{MF6^3-}$ ion?

  1. $\ce{Ga}$
  2. $\ce{Al}$
  3. $\ce{B}$
  4. $\ce{In}$
Answer: (3)

Boron ($1s^2 2s^2 2p^1$) is a second-period element with no $d$-orbitals in its valence shell, so it cannot expand its octet beyond a covalence of four. It forms $\ce{BF4-}$ but never $\ce{BF6^3-}$. Aluminium, gallium and indium have accessible $d$-orbitals and can reach a covalence of six.

Concept · Inert pair effect

Standard electrode potentials are $E^\circ(\ce{Al^3+}/\ce{Al}) = -1.66\ \text{V}$ and $E^\circ(\ce{Tl^3+}/\ce{Tl}) = +1.26\ \text{V}$. Comment on the formation of $\ce{M^3+}$ ions and the electropositive character of the two metals.

Answer: $\ce{Al^3+}$ readily forms; $\ce{Tl^3+}$ does not

The large negative $E^\circ$ for aluminium shows a strong tendency to form $\ce{Al^3+}(aq)$, so aluminium is highly electropositive. The positive $E^\circ$ for thallium shows $\ce{Tl^3+}$ is unstable in solution and acts as a powerful oxidising agent, so $\ce{Tl+}$ is the favoured state. Aluminium is therefore more electropositive than thallium — a direct consequence of the inert pair effect.

Concept · Atomic radius

Why is the atomic radius of gallium lower than that of aluminium, despite gallium lying below aluminium in the group?

Answer: poor screening by 3d electrons

Going from $\ce{Al}$ to $\ce{Ga}$, ten $3d$-electrons are added to the core. These screen the nuclear charge poorly, so gallium's outer electrons feel a higher effective nuclear charge and are pulled inward. The radius of $\ce{Ga}$ (135 pm) is thus slightly less than that of $\ce{Al}$ (143 pm).

FAQs — Group 13 — Boron Family (General)

Common doubts on group 13 trends, the inert pair effect and anomalous boron.

Why is the atomic radius of gallium less than that of aluminium?

Going from aluminium to gallium, ten 3d electrons are added to the inner core. These d electrons offer only a poor screening effect, so the outer electrons of gallium experience a higher effective nuclear charge and are pulled in tightly. As a result the atomic radius of gallium (135 pm) is slightly less than that of aluminium (143 pm), against the usual expectation that radius increases down a group.

What is the inert pair effect in group 13?

The inert pair effect is the reluctance of the two ns electrons to take part in chemical bonding as we descend the group. Because of the poor shielding by intervening d and f orbitals, the increased effective nuclear charge holds the ns electrons tightly, so only the np electron is used in bonding. This makes the +1 oxidation state progressively more stable for the heavier elements in the order Al < Ga < In < Tl, with thallium showing a predominant +1 state.

Why is Tl+ more stable than Tl3+?

In thallium the inert pair effect is at its maximum, so the 6s2 pair resists bonding and the +1 state predominates. The standard electrode potential E° for Tl3+/Tl+ is about +1.6 V, showing that Tl3+ is a powerful oxidising agent that is readily reduced to Tl+. Hence Tl+ is more stable than Tl3+, and a relation such as TlI > TlI3 holds for stability.

Why is boron unable to form the BF6 3– ion?

Boron is a second period element with valence electronic configuration 2s2 2p1 and has no d orbitals available in its valence shell. Without d orbitals it cannot expand its octet, so its maximum covalence is limited to four (as in BF4–). Heavier members such as aluminium, having vacant d orbitals, can reach a covalence of six and form ions like AlF6 3–.

Why does boron form only covalent compounds while aluminium can form Al3+ ions?

Boron has a very small size, so the sum of its first three ionisation enthalpies is extremely high. This prevents the formation of B3+ ions and forces boron to bond covalently. On moving to aluminium the sum of the first three ionisation enthalpies falls considerably, so aluminium is able to form Al3+ ions and behaves as a highly electropositive metal.

Why do trivalent group 13 compounds behave as Lewis acids?

In the +3 state the central atom has only six electrons around it, for example boron in BF3, making these molecules electron deficient. To complete a stable octet they accept a lone pair of electrons from a donor, so they act as Lewis acids. For instance BF3 reacts with ammonia to form the adduct F3B–NH3. This Lewis acid strength decreases as size increases down the group.