Chemistry · The p-Block Elements (Class 11)

Allotropes of Carbon (Diamond, Graphite, Fullerenes)

Carbon offers the cleanest illustration of allotropy in the entire syllabus: the same element, $\ce{C}$, builds a transparent gemstone, a black lubricant, and a hollow molecular cage purely by changing how its atoms hybridise and connect. Following the NCERT Group-14 treatment (§11.7), this note develops diamond, graphite and fullerenes from their bonding upward, so that every property — hardness, conductivity, slipperiness — can be read straight off the structure. For NEET this is high-yield: hybridisation, ring count in $\ce{C60}$, and the conductivity contrast are recurring assertion–reason and matching questions.

What allotropy means for carbon

Allotropes are different structural forms of the same element existing in the same physical state. Carbon provides one of the best examples of allotropy because two factors converge in it: its strong tendency towards catenation (the linking of carbon atoms into chains and rings through robust $\ce{C-C}$ bonds) and its ability to form $p\pi\text{-}p\pi$ multiple bonds with itself. Together these allow carbon to adopt several distinct lattices, both crystalline and amorphous.

Diamond and graphite are the two long-known crystalline forms. In 1985 a third form, the fullerenes, was discovered by H. W. Kroto, R. E. Smalley and R. F. Curl — work for which they received the Nobel Prize in 1996. The decisive variable across all three is the hybridisation of the carbon atom: $sp^3$ in diamond, $sp^2$ in graphite and in fullerenes. Once you fix the hybridisation, the geometry, and hence the macroscopic properties, follow inevitably.

AllotropeHybridisationDimensionalityDiscovered / known
Diamondsp³3D rigid networkLong known
Graphitesp²2D layered sheetsLong known
Fullerene ($\ce{C60}$)sp²0D closed cage1985 (Kroto, Smalley, Curl)

Diamond — the sp³ network

In diamond every carbon atom undergoes $sp^3$ hybridisation and is linked to four other carbon atoms through these hybrid orbitals in a tetrahedral arrangement. The $\ce{C-C}$ bond length is 154 pm. Because each atom is bonded tetrahedrally to four neighbours, and each of those to four more, the structure extends through space as a single rigid three-dimensional network of carbon atoms — effectively one giant molecule.

Directional covalent bonds run throughout the entire lattice. To deform or cleave diamond you must break extremely strong $\ce{C-C}$ bonds in every direction at once, and there is no plane of weakness to exploit. This is precisely why diamond is the hardest substance on earth, and why — despite being a purely covalent solid rather than an ionic or metallic one — it has a very high melting point. All four valence electrons of every carbon are committed to localised sigma bonds, so none are free to move; diamond is therefore a non-conductor (electrical insulator).

Figure 1
sp³ C 154 pm C–C, four directions

Figure 1 — Diamond. A central $sp^3$ carbon (teal) is bonded tetrahedrally to four carbons; dashed bonds indicate how the network repeats in all directions, giving a rigid 3D giant covalent lattice with no free electrons.

The hardness of diamond is exploited directly: it is used as an abrasive for sharpening hard tools, in making dies, and in the manufacture of tungsten filaments for electric bulbs. As a precious stone it is used in jewellery, where it is measured in carats (1 carat = 200 mg).

Worked reasoning

Diamond is covalent, yet it has a high melting point. Why?

Diamond is a three-dimensional network involving strong $\ce{C-C}$ bonds that are very difficult to break. Melting requires rupturing these covalent bonds throughout the giant lattice, which demands a large amount of energy — hence the high melting point, even though no ionic or metallic bonding is present.

Graphite — the sp² sheets

Graphite has a layered structure. Each layer is composed of planar hexagonal rings of carbon atoms, and within a layer the $\ce{C-C}$ bond length is 141.5 pm — shorter than in diamond, reflecting partial double-bond character. Successive layers are held to one another only by weak van der Waals forces, and the distance between two adjacent layers is 340 pm, far larger than any bonding distance.

Within each sheet, every carbon atom is $sp^2$ hybridised and makes three sigma bonds with three neighbouring carbon atoms. The fourth valence electron of each carbon enters a $\pi$ bond, and these $\pi$ electrons are delocalised over the whole sheet. Being mobile, they allow graphite to conduct electricity along the plane of the layers. This single fact — mobile delocalised electrons — is what separates graphite from diamond electrically.

The mechanical behaviour follows from the layering. Because adjacent sheets are bound only by weak van der Waals forces, the layers slide over one another readily; graphite therefore cleaves easily between the layers and is soft and slippery. For this reason it serves as a dry lubricant in machines running at high temperature, where ordinary oil cannot be used.

Figure 2
sp² sheet 340 pm van der Waals 141.5 pm in-plane C–C

Figure 2 — Graphite. Planar hexagonal sheets of $sp^2$ carbons (in-plane $\ce{C-C}$ = 141.5 pm) stack 340 pm apart, held only by weak van der Waals forces. Delocalised $\pi$ electrons make the sheets conducting; weak interlayer forces make them slide and lubricate.

NEET Trap

Graphite conducts, diamond insulates — and the reason is the spare electron

The classic confusion: students remember "graphite is sp², diamond is sp³" but reverse the conductivity, or attribute graphite's conduction to its layers rather than to its electrons. Pin it to the fourth electron. In graphite ($sp^2$) each carbon uses three electrons in sigma bonds and the fourth electron is delocalised — these mobile $\pi$ electrons carry current. In diamond ($sp^3$) all four electrons are locked in localised sigma bonds, so none are free — diamond is an insulator.

Mnemonic: sp² → spare electron → conducts (graphite, fullerene π-system); sp³ → spent fully → insulates (diamond).

Graphite has further uses that flow from its conductivity and inertness. Graphite fibres embedded in plastic form high-strength, lightweight composites used in tennis rackets, fishing rods, aircraft and canoes. Being a good conductor, graphite is used for electrodes in batteries and in industrial electrolysis, and crucibles made of graphite are inert to dilute acids and alkalies.

Keep building the family

Allotropy is rooted in carbon's catenation and small size — the same anomalies that define the whole group. See Group 14: The Carbon Family for the trends behind it.

Fullerenes and the C₆₀ cage

Fullerenes are made by heating graphite in an electric arc in the presence of inert gases such as helium or argon. The sooty material formed by condensation of vapourised $\ce{C}_n$ small molecules consists mainly of $\ce{C60}$, with a smaller quantity of $\ce{C70}$ and traces of fullerenes containing even numbers of carbon atoms up to 350 or above. Unusually, fullerenes are the only pure form of carbon, because their smooth closed structure has no "dangling" bonds at the edges — unlike a graphite sheet, which terminates somewhere.

The $\ce{C60}$ molecule is cage-like and shaped like a soccer ball; it is named Buckminsterfullerene. It contains twenty six-membered rings and twelve five-membered rings. The fusion rule is specific and examinable: a six-membered ring is fused with six- or five-membered rings, but a five-membered ring can only fuse with six-membered rings. All sixty carbon atoms are equivalent and all undergo $sp^2$ hybridisation.

Each carbon forms three sigma bonds with three other carbons, and the remaining electron at each carbon is delocalised in molecular orbitals, which imparts aromatic character to the molecule. The ball has 60 vertices, each occupied by one carbon atom, and it contains both single and double bonds with $\ce{C-C}$ distances of 143.5 pm (single) and 138.3 pm (double). Spherical fullerenes are also called bucky balls.

Figure 3
5-ring 20 hexagons + 12 pentagons, 60 vertices

Figure 3 — $\ce{C60}$ Buckminsterfullerene (schematic). A central five-membered ring (purple) fuses only with six-membered rings; each of the 60 vertices is an $sp^2$ carbon forming three sigma bonds, with the remaining electrons delocalised over the cage.

NEET Trap

Count the rings the right way: 20 six-membered, 12 five-membered

NEET 2020 set a statement claiming $\ce{C60}$ "contains twelve six carbon rings and twenty five carbon rings" — the numbers are swapped, so the statement is wrong. The correct count is twenty six-membered rings and twelve five-membered rings. Also keep the fusion rule straight: a five-membered ring fuses only with six-membered rings, never with another pentagon.

Memory hook: "twenty hexagons, twelve pentagons" — like a stitched football. Total faces 32, total vertices 60.

Master comparison table

The single table below collapses the entire subtopic into a structure-to-property map. Reading it left to right reproduces nearly every objective question asked on carbon allotropes: hybridisation, geometry, the consequence for conductivity and hardness, and the use that follows.

AllotropeHybridisationStructureKey bond dataPropertiesUses
Diamond sp³ Rigid 3D tetrahedral network; each C bonded to 4 C $\ce{C-C}$ = 154 pm Hardest known substance; very high m.p.; electrical insulator (no free electrons) Abrasive, sharpening tools, dies, tungsten filaments; gemstone (carats)
Graphite sp² Planar hexagonal layers; 3 sigma bonds + 1 delocalised $\pi$ electron; layers held by van der Waals forces In-plane $\ce{C-C}$ = 141.5 pm; interlayer = 340 pm Soft and slippery; conducts electricity along sheets; cleaves between layers Dry lubricant; battery and electrolysis electrodes; composites; graphite crucibles
Fullerene ($\ce{C60}$) sp² Closed soccer-ball cage; 20 six-membered + 12 five-membered rings; 60 vertices; 3 sigma bonds per C + delocalised electron $\ce{C-C}$ single = 143.5 pm; double = 138.3 pm Only pure form of carbon (no dangling bonds); aromatic character; cage-like molecule Bucky balls; precursor for fullerene chemistry and materials

Stability and impure forms

Although diamond looks the most "permanent" of the three, it is graphite that is thermodynamically the most stable allotrope of carbon. By convention the standard enthalpy of formation $\Delta_f H^{\circ}$ of graphite is taken as zero. Relative to it, diamond and fullerene $\ce{C60}$ lie higher in energy, with $\Delta_f H^{\circ}$ values of 1.90 and 38.1 kJ mol⁻¹ respectively. Diamond persists in everyday conditions only because its conversion to graphite is kinetically extremely slow, not because it is the lower-energy form.

Several familiar "forms" of carbon are not separate allotropes at all but impure variants of graphite or fullerenes. Carbon black is obtained by burning hydrocarbons in a limited supply of air; charcoal and coke are obtained by heating wood or coal respectively at high temperature in the absence of air. Each finds use according to its texture: activated charcoal, being highly porous, adsorbs poisonous gases and is used in water filters and air-conditioning systems to control odour; carbon black is a black pigment in inks and a filler in tyres; and coke is used as a fuel and largely as a reducing agent in metallurgy.

Worked reasoning

State the hybridisation of carbon in (a) diamond and (b) graphite, and use it to explain why one cleaves while the other resists abrasion.

(a) Diamond — $sp^3$: four equivalent tetrahedral sigma bonds form a rigid 3D network with no plane of weakness, so diamond resists abrasion and is the hardest substance. (b) Graphite — $sp^2$: three in-plane sigma bonds give strong sheets, but adjacent sheets are held only by weak van der Waals forces 340 pm apart, so they slide and the crystal cleaves easily. The same $sp^2$ carbon also leaves one delocalised electron per atom, which is why graphite conducts.

Quick Recap

Allotropes of carbon at a glance

  • Diamond: $sp^3$, 3D tetrahedral network, $\ce{C-C}$ 154 pm — hardest substance, high m.p., electrical insulator; used as abrasive and gemstone.
  • Graphite: $sp^2$, planar hexagonal layers (in-plane 141.5 pm, interlayer 340 pm, van der Waals) — soft, slippery, conducts along sheets via the delocalised fourth electron; dry lubricant and electrode.
  • Fullerene $\ce{C60}$: $sp^2$, soccer-ball cage, 20 hexagons + 12 pentagons, 60 vertices, $\ce{C-C}$ 143.5/138.3 pm — only pure form of carbon, aromatic character.
  • Conductivity rule: $sp^2$ leaves a spare delocalised electron (graphite, fullerene conduct/are aromatic); $sp^3$ spends all four electrons (diamond insulates).
  • Stability: graphite is thermodynamically most stable ($\Delta_f H^{\circ}=0$); diamond 1.90, $\ce{C60}$ 38.1 kJ mol⁻¹. Coke/charcoal/carbon black are impure forms.

NEET PYQ Snapshot — Allotropes of Carbon (Diamond, Graphite, Fullerenes)

Real NEET questions where structure–property reasoning for carbon's allotropes decided the answer.

NEET 2023

Match List-I with List-II.
A. Coke — I. Carbon atoms are sp³ hybridised.
B. Diamond — II. Used as a dry lubricant
C. Fullerene — III. Used as reducing agent
D. Graphite — IV. Cage like molecules

  • (1) A-III, B-IV, C-I, D-II
  • (2) A-II, B-IV, C-I, D-III
  • (3) A-IV, B-I, C-II, D-III
  • (4) A-III, B-I, C-IV, D-II
Answer: (4) A-III, B-I, C-IV, D-II

Coke is largely used as a reducing agent in metallurgy (III). In diamond each carbon is $sp^3$ and tetrahedrally bonded to four carbons (I). Buckminsterfullerene is a cage-like molecule of six- and five-membered rings (IV). Graphite is soft and slippery, hence a dry lubricant (II).

NEET 2020

Identify the correct statements from the following:
(a) $\ce{CO2}$(g) is used as refrigerant for ice-cream and frozen food.
(b) The structure of $\ce{C60}$ contains twelve six carbon rings and twenty five carbon rings.
(c) ZSM-5, a type of zeolite, is used to convert alcohols into gasoline.
(d) CO is colourless and odourless gas.

  • (1) (a) and (c) only
  • (2) (b) and (c) only
  • (3) (c) and (d) only
  • (4) (a), (b) and (c) only
Answer: (3) (c) and (d) only

Statement (b) is the trap: $\ce{C60}$ actually contains twenty six-membered rings and twelve five-membered rings — the numbers in the statement are swapped, so (b) is incorrect. (c) and (d) are correct, giving option (3).

Concept · NCERT

Thermodynamically the most stable form of carbon is:

  • (a) diamond
  • (b) graphite
  • (c) fullerenes
  • (d) coal
Answer: (b) graphite

Graphite is the thermodynamically most stable allotrope, so $\Delta_f H^{\circ}(\text{graphite}) = 0$. Diamond (1.90 kJ mol⁻¹) and $\ce{C60}$ (38.1 kJ mol⁻¹) lie higher in energy. Diamond survives only because its conversion to graphite is kinetically very slow.

Concept

What is the state of hybridisation of carbon in (a) diamond and (b) graphite?

Answer: (a) sp³  ·  (b) sp²

In diamond each carbon is $sp^3$, bonded tetrahedrally to four neighbours. In graphite each carbon is $sp^2$, forming three sigma bonds within a planar hexagonal sheet with the fourth electron delocalised. Fullerene carbons are likewise $sp^2$.

FAQs — Allotropes of Carbon (Diamond, Graphite, Fullerenes)

The high-yield doubts examiners convert into assertion–reason and matching questions.

Why does graphite conduct electricity while diamond does not?
In graphite each carbon is sp2 hybridised, makes three sigma bonds and contributes its fourth electron to a delocalised pi system spread over the whole sheet. These mobile electrons let graphite conduct electricity along the layers. In diamond every carbon is sp3 hybridised and uses all four valence electrons in localised sigma C-C bonds, leaving no free electrons, so diamond is a non-conductor (insulator).
What is the hybridisation of carbon in diamond, graphite and fullerene?
Carbon is sp3 hybridised in diamond, and sp2 hybridised in both graphite and fullerene (C60). The sp3 carbon of diamond is tetrahedrally bonded to four neighbours, whereas the sp2 carbon of graphite and fullerene forms three sigma bonds and retains one electron for pi bonding.
Why is diamond the hardest natural substance but has a high melting point despite being covalent?
Diamond is a rigid three-dimensional network in which directional covalent C-C bonds extend throughout the lattice. Breaking this giant covalent network requires breaking very strong C-C bonds in every direction, which makes diamond the hardest substance on earth and also gives it a very high melting point even though the bonding is purely covalent.
Why is graphite soft and used as a dry lubricant?
Graphite has a layered structure in which planar hexagonal sheets are held together only by weak van der Waals forces, with the layers 340 pm apart. Because these forces are weak, the layers slide over one another easily, so graphite cleaves readily, feels soft and slippery, and is used as a dry lubricant in high-temperature machinery where oil cannot be used.
What is the structure of C60 buckminsterfullerene?
C60 is a cage-like molecule shaped like a soccer ball, with 60 vertices each occupied by an sp2 carbon. It contains twenty six-membered rings and twelve five-membered rings; a six-membered ring fuses with five- or six-membered rings, while a five-membered ring fuses only with six-membered rings. Each carbon forms three sigma bonds and its remaining electron is delocalised, giving aromatic character. The C-C distances are 143.5 pm (single) and 138.3 pm (double).
Which allotrope of carbon is thermodynamically the most stable?
Graphite is the thermodynamically most stable allotrope of carbon, so its standard enthalpy of formation is taken as zero. By comparison the standard enthalpies of formation of diamond and fullerene C60 are 1.90 and 38.1 kJ per mole respectively, both higher in energy than graphite.