What Are Alkanes
Alkanes are saturated hydrocarbons in which every carbon atom is $sp^3$ hybridised and joined to its neighbours by single covalent bonds alone. Successive members differ by a $\ce{-CH2-}$ unit, and constructing the family member by member shows that the molecular formula always satisfies the relation $\ce{C_{n}H_{2n+2}}$. Because each carbon already carries the maximum number of hydrogen atoms permitted by its four bonds, alkanes are described as saturated.
The tetrahedral geometry around each carbon dictates a $\ce{C-C-C}$ bond angle close to $109.5^\circ$, so an extended alkane chain is not straight but zig-zag. The C–C and C–H bonds are nearly non-polar because the electronegativity difference between carbon and hydrogen is small, and this electronic character is the root of almost every property discussed below — from low solubility in water to chemical inertness. Alkanes are historically called paraffins, from the Latin parum affinis, meaning of little affinity.
| Property | Description | Underlying reason |
|---|---|---|
| General formula | CnH2n+2 | Each C is fully saturated with single bonds |
| Hybridisation | $sp^3$ at every carbon | Four sigma bonds per carbon |
| Bond angle | $\approx 109.5^\circ$ | Tetrahedral arrangement |
| Polarity | Almost non-polar | Small C–H electronegativity gap |
| Intermolecular force | Weak van der Waals | Non-polar covalent molecules |
Nomenclature and Isomerism
The first three alkanes — methane, ethane and propane — have only one possible structure each. From butane onwards, the same molecular formula can be arranged into more than one skeleton, giving rise to chain (skeletal) isomerism. Butane, $\ce{C4H10}$, exists as the straight-chain n-butane and the branched 2-methylpropane (isobutane); pentane, $\ce{C5H12}$, has three isomers: n-pentane, 2-methylbutane and 2,2-dimethylpropane (neopentane).
In IUPAC nomenclature the longest continuous carbon chain is selected as the parent and numbered so that substituents receive the lowest set of locants. Alkyl groups, obtained by removing one hydrogen from an alkane ($\ce{-CH3}$ methyl, $\ce{-C2H5}$ ethyl), are cited as prefixes with their position numbers. Hydrogen atoms themselves are classified by the carbon they sit on — a point that becomes decisive when we reach halogenation selectivity.
| Hydrogen type | Carbon it is attached to | Example carbon |
|---|---|---|
| Primary (1°) | Carbon bonded to one other carbon | $\ce{-CH3}$ of propane |
| Secondary (2°) | Carbon bonded to two other carbons | Middle $\ce{-CH2-}$ of propane |
| Tertiary (3°) | Carbon bonded to three other carbons | Central C of 2-methylpropane |
Preparation of Alkanes
Petroleum and natural gas are the principal natural sources of alkanes, but several laboratory routes allow targeted synthesis. NCERT §9.2.2 groups them by the starting material: unsaturated hydrocarbons, alkyl halides, and carboxylic acids. Each method has a characteristic constraint that examiners exploit, so the carbon-counting logic matters as much as the equation itself.
1. From unsaturated hydrocarbons (hydrogenation)
Dihydrogen adds across the multiple bonds of alkenes and alkynes over finely divided platinum, palladium or nickel — the Sabatier–Senderens reaction. The metal adsorbs $\ce{H2}$ on its surface and activates the H–H bond. Platinum and palladium operate at room temperature, while nickel needs higher temperature and pressure.
$$\ce{CH2=CH2 + H2 ->[Pt/Pd/Ni] CH3-CH3}$$ $$\ce{CH3-C#C-H + 2H2 ->[Pt/Pd/Ni] CH3-CH2-CH3}$$
2. From alkyl halides
Alkyl halides (except fluorides) on reduction with zinc and dilute hydrochloric acid give alkanes with the same carbon count:
$$\ce{CH3-Cl + H2 ->[Zn, H+] CH4 + HCl}$$
The more important route is the Wurtz reaction: two molecules of an alkyl halide treated with sodium metal in dry ether couple to give a higher alkane containing twice the carbon atoms of the halide. The product therefore always has an even number of carbons and a symmetrical skeleton.
$$\ce{2CH3Br + 2Na ->[dry\ ether] CH3-CH3 + 2NaBr}$$ $$\ce{2C2H5Br + 2Na ->[dry\ ether] CH3-CH2-CH2-CH3 + 2NaBr}$$
The hydrogenation route runs backwards from alkenes — see how addition of $\ce{H2}$ across the double bond fits the wider unsaturation story.
3. From carboxylic acids
Heating the sodium salt of a carboxylic acid with soda lime (sodium hydroxide and calcium oxide, typically in a 3:1 ratio) eliminates carbon dioxide and yields an alkane with one carbon atom fewer than the acid. This loss of $\ce{CO2}$ is called decarboxylation.
$$\ce{CH3COONa + NaOH ->[CaO][\Delta] CH4 + Na2CO3}$$
Kolbe's electrolytic method takes the aqueous sodium or potassium salt of a carboxylic acid and electrolyses it. At the anode the carboxylate loses an electron and then $\ce{CO2}$ to give an alkyl free radical; two such radicals combine, so the alkane formed has an even number of carbon atoms.
$$\ce{2CH3COONa + 2H2O ->[electrolysis] C2H6 + 2CO2 + H2 + 2NaOH}$$
| Method | Reagent / condition | Carbon-count rule |
|---|---|---|
| Hydrogenation (Sabatier–Senderens) | $\ce{H2}$, Pt / Pd / Ni | Same as parent alkene/alkyne |
| Reduction of alkyl halide | Zn + dilute HCl | Same as halide |
| Wurtz reaction | Na, dry ether | Double the halide; even, symmetrical |
| Decarboxylation (soda lime) | NaOH + CaO, $\Delta$ | One carbon less than acid |
| Kolbe electrolysis | Electrolysis of carboxylate salt | Even; couples two alkyl radicals |
Wurtz works only for symmetrical, even-carbon alkanes
Because Wurtz couples two alkyl halides, the product is restricted to an even number of carbons and a symmetrical chain. Attempting an unsymmetrical (often odd-carbon) alkane from two different halides yields a mixture of all three coupling products plus side-reaction alkenes and alkanes, so the target is impure and low-yielding.
Memory hook: n-heptane (7 C, odd) cannot be made cleanly by Wurtz — this exact framing was asked in NEET 2020.
Physical Properties
Alkanes are colourless, odourless and almost non-polar; they dissolve in non-polar solvents but are essentially insoluble in water, following the rule like dissolves like. Their molecules attract one another only through weak van der Waals forces, which is why the lightest members are gases. The first four members $\ce{C1}$ to $\ce{C4}$ are gases, $\ce{C5}$ to $\ce{C17}$ are liquids, and those with 18 or more carbons are solids at 298 K.
Boiling point rises steadily with molecular mass because the van der Waals forces grow with molecular size and surface area. Among isomers, branching lowers the boiling point: as a molecule becomes more branched it approaches a spherical shape, reducing the surface area available for contact and weakening the intermolecular attraction. Hence the three isomeric pentanes boil in the order $n\text{-pentane} > 2\text{-methylbutane} > 2{,}2\text{-dimethylpropane}$.
Why neopentane boils lower than n-pentane
The same five carbons pack very differently: the extended chain offers a long line of contact, the spherical isomer only a near-point of contact.
Chemical Properties
Alkanes are generally inert towards acids, bases, oxidising agents and reducing agents — the very inertness implied by the name paraffin. Under forcing conditions, however, they undergo a defined set of reactions. The most heavily examined of these is the substitution reaction, in which one or more hydrogen atoms are replaced by halogen, nitro or sulphonic acid groups.
Halogenation proceeds in diffused sunlight or ultraviolet light, or at high temperature ($573$–$773$ K). Chlorination of methane does not stop cleanly at one stage but proceeds through successive substitution to a mixture of products:
$$\ce{CH4 + Cl2 ->[h\nu] CH3Cl + HCl}$$ $$\ce{CH3Cl + Cl2 ->[h\nu] CH2Cl2 + HCl}$$ $$\ce{CH2Cl2 + Cl2 ->[h\nu] CHCl3 + HCl}$$ $$\ce{CHCl3 + Cl2 ->[h\nu] CCl4 + HCl}$$
The reactivity of the halogens themselves follows $\ce{F2 > Cl2 > Br2 > I2}$. Fluorination is too violent to control, while iodination is slow and reversible — it must be driven by an oxidising agent such as $\ce{HIO3}$ or $\ce{HNO3}$ to remove the $\ce{HI}$ produced. The ease with which different hydrogens are replaced follows the order $3^\circ > 2^\circ > 1^\circ$, which governs the major product when an alkane has more than one type of hydrogen.
Halogenation selectivity: tertiary beats secondary beats primary
When an alkane carries different kinds of hydrogen, the radical preferentially abstracts the one that gives the most stable carbon radical. Stability order $3^\circ > 2^\circ > 1^\circ$ therefore sets the order of replacement $3^\circ > 2^\circ > 1^\circ$. Do not confuse this with halogen reactivity, which runs $\ce{F2 > Cl2 > Br2 > I2}$.
Two separate orders: which halogen reacts fastest ($\ce{F2>Cl2>Br2>I2}$) vs which H is replaced fastest ($3^\circ>2^\circ>1^\circ$).
Free-Radical Halogenation Mechanism
Halogenation proceeds by a free-radical chain mechanism in three phases: initiation, propagation and termination. The chain is set off because the weak $\ce{Cl-Cl}$ bond breaks more easily than the stronger $\ce{C-C}$ and $\ce{C-H}$ bonds when energised by light or heat.
Initiation — homolysis of chlorine produces two chlorine radicals: $$\ce{Cl2 ->[h\nu] 2Cl^.}$$ Propagation — a chlorine radical abstracts a hydrogen from methane to give a methyl radical; this radical then attacks a fresh chlorine molecule, forming the product and regenerating a chlorine radical, so the chain continues: $$\ce{CH4 + Cl^. -> CH3^. + HCl}$$ $$\ce{CH3^. + Cl2 -> CH3Cl + Cl^.}$$ Termination — the chain stops when two radicals combine, consuming radicals without making new ones. Combination of two methyl radicals explains why ethane appears as a by-product of methane chlorination: $$\ce{Cl^. + Cl^. -> Cl2}$$ $$\ce{CH3^. + CH3^. -> CH3-CH3}$$ $$\ce{CH3^. + Cl^. -> CH3Cl}$$
Initiation → Propagation → Termination flow for $\ce{CH4 + Cl2}$
The propagation step is self-sustaining: each turn consumes one radical and makes another, so a single initiation event can convert many molecules before termination breaks the chain.
Combustion, Oxidation and Cracking
Beyond substitution, alkanes undergo combustion, controlled oxidation, isomerisation, aromatisation, reaction with steam and pyrolysis. These define their industrial value as fuels and feedstocks.
Combustion — in excess air or oxygen, alkanes are completely oxidised to $\ce{CO2}$ and water with the release of a large amount of heat, which is why they are used as fuels. The general equation is: $$\ce{C_{n}H_{2n+2} + ( \frac{3n+1}{2} )O2 -> nCO2 + (n+1)H2O}$$ With insufficient air, incomplete combustion gives carbon black, used in inks and pigments: $$\ce{CH4 + O2 -> C + 2H2O}$$
| Reaction | Conditions | Representative equation |
|---|---|---|
| Controlled oxidation to methanol | Cu, 523 K, 100 atm | $\ce{2CH4 + O2 -> 2CH3OH}$ |
| Oxidation to methanal | $\ce{Mo2O3}$, $\Delta$ | $\ce{CH4 + O2 -> HCHO + H2O}$ |
| 3° H to alcohol | $\ce{KMnO4}$ | $\ce{(CH3)3CH -> (CH3)3COH}$ |
| Isomerisation | Anhydrous $\ce{AlCl3}$/HCl | $n$-hexane → 2- & 3-methylpentane |
| Aromatisation (reforming) | 773 K, 10–20 atm, oxide catalyst | $\ce{C6H14 -> C6H6 + 4H2}$ |
| Reaction with steam | Ni, 1273 K | $\ce{CH4 + H2O -> CO + 3H2}$ |
| Pyrolysis (cracking) | High temperature | $\ce{C12H26 -> C7H16 + C5H10}$ |
Controlled oxidation with a regulated supply of oxygen and the right catalyst halts at a useful intermediate such as methanol, methanal or acetic acid. Isomerisation over anhydrous aluminium chloride converts straight-chain into branched alkanes (raising the octane number of fuel), while aromatisation dehydrogenates and cyclises $\ce{C6+}$ alkanes into benzene and its homologues over oxides of vanadium, molybdenum or chromium on alumina. Finally, pyrolysis (cracking) breaks higher alkanes into smaller alkanes and alkenes by heat, the basis of converting kerosene into oil gas and lighter fuels.
Alkanes in one screen
- General formula $\ce{C_{n}H_{2n+2}}$; all $sp^3$, non-polar, weak van der Waals forces, hence inert "paraffins".
- Preparation: hydrogenation of alkenes/alkynes (Pt/Pd/Ni), reduction of alkyl halides (Zn/HCl), Wurtz (Na, dry ether → even, symmetrical), decarboxylation with soda lime (one C less), Kolbe electrolysis (even C).
- Boiling point rises with mass; branching lowers it: $n$-pentane > 2-methylbutane > neopentane.
- Halogenation = free-radical chain (initiation, propagation, termination); halogen reactivity $\ce{F2>Cl2>Br2>I2}$; H replacement $3^\circ>2^\circ>1^\circ$.
- Other reactions: combustion (fuel), controlled oxidation, isomerisation, aromatisation, steam reforming, pyrolysis (cracking).