Chemistry · Equilibrium

Equilibrium in Physical Processes

Before a single bond is broken or formed, equilibrium already governs the simple physical changes around us — melting, evaporation, sublimation and dissolution. NCERT Class 11 Chemistry (§6.1) opens the chapter on Equilibrium with exactly these phase transformations because they reveal, in their purest form, what a state of dynamic equilibrium really means. Mastering the characteristics of each physical equilibrium is the conceptual foundation on which equilibrium constants, the law of mass action and Le Chatelier's principle are later built, and NEET frequently tests these definitions directly.

Why begin with physical equilibria

When a liquid evaporates inside a closed container, molecules with relatively higher kinetic energy escape from the liquid surface into the vapour phase, while molecules already in the vapour strike the liquid surface and are retained. A constant vapour pressure arises because the number of molecules leaving the liquid eventually equals the number returning to it. At this stage we say the system has reached an equilibrium state. The defining insight of NCERT §6.1 is that this is not a static equilibrium: there is intense, continuous activity at the boundary between the two phases even though no net change is visible.

Equilibrium can be established for both physical processes and chemical reactions. Physical equilibria are introduced first because they involve no change in chemical identity — only the distribution of a substance between phases changes. The familiar examples are the phase transformations represented as $\ce{solid <=> liquid}$, $\ce{liquid <=> gas}$ and $\ce{solid <=> gas}$. The double half-arrows ($\ce{<=>}$) signal that the processes in both directions proceed simultaneously, and the coexisting mixture is called an equilibrium mixture.

Physical processRepresentationForward / reverse
Melting / freezing$\ce{H2O(s) <=> H2O(l)}$melting / freezing
Evaporation / condensation$\ce{H2O(l) <=> H2O(g)}$evaporation / condensation
Sublimation / deposition$\ce{I2(s) <=> I2(g)}$sublimation / deposition
Dissolution / crystallisation$\ce{Sugar(s) <=> Sugar(aq)}$dissolution / crystallisation

Solid–liquid equilibrium

Consider ice and water kept together in a perfectly insulated thermos flask — one that allows no exchange of heat with the surroundings — at 273 K and atmospheric pressure. The system is at equilibrium, and we observe that the mass of ice and the mass of water do not change with time while the temperature remains constant. Yet the equilibrium is not static. Intense activity can be noticed at the boundary between ice and water: molecules from the liquid collide against the ice and adhere to it, while some molecules of ice escape into the liquid phase. The masses stay constant only because the rate of transfer of molecules from ice into water exactly equals the rate of the reverse transfer.

This balance can be written as $\ce{H2O(s) <=> H2O(l)}$. Ice and water are in equilibrium only at one particular temperature and pressure. For any pure substance at atmospheric pressure, the temperature at which the solid and liquid phases are in equilibrium is called the normal melting point (equivalently, the normal freezing point) of that substance.

Figure 1 Dynamic transfer of molecules at the ice–water boundary ICE (solid) WATER (liquid) boundary melting freezing rate of melting = rate of freezing → mass constant at 273 K

Figure 1 — At the ice–water boundary, melting and freezing occur simultaneously and at equal rates. The masses of the two phases stay constant, but molecular exchange across the boundary never stops.

Two conclusions follow for this dynamic equilibrium: both opposing processes occur simultaneously, and both occur at the same rate, so that the amount of ice and the amount of water remain constant. The condition of an insulated flask matters — if no heat is exchanged with the surroundings, the mass of the two phases stays fixed.

Liquid–vapour equilibrium

This equilibrium is best understood through a closed-vessel experiment. A transparent box fitted with a mercury manometer is first dried thoroughly with a drying agent such as anhydrous calcium chloride. A watch glass containing water is then placed inside and the box is sealed. As water evaporates, the pressure inside the box rises and the mercury level in the manometer climbs, while the volume of water in the watch glass falls. The rate of evaporation stays constant, but the rate at which pressure increases slows down as condensation of vapour back into water sets in. Finally a state is reached where there is no net evaporation.

Figure 2 Equalising rates of evaporation and condensation in a closed vessel liquid vapour closed container time rate evaporation condensation equilibrium

Figure 2 — In a closed vessel the rate of evaporation stays constant while the rate of condensation rises until the two become equal. At that point the vapour pressure reaches its constant equilibrium value.

At equilibrium, $\ce{H2O(l) <=> H2O(g)}$ with the rate of evaporation equal to the rate of condensation. The pressure exerted by the water molecules at a given temperature then stays constant and is called the equilibrium vapour pressure of water (or simply its vapour pressure). Vapour pressure increases with temperature. Different liquids have different equilibrium vapour pressures at the same temperature: the liquid with the higher vapour pressure is more volatile and has a lower boiling point.

Water and water vapour are in equilibrium at atmospheric pressure (1.013 bar) and 100 °C in a closed vessel; the boiling point of water is therefore 100 °C at 1.013 bar. For any pure liquid at one atmospheric pressure, the temperature at which the liquid and its vapour are at equilibrium is the normal boiling point. Because boiling point depends on atmospheric pressure, it falls with altitude — at high altitude, where pressure is lower, water boils below 100 °C.

NEET Trap

Open systems never reach equilibrium

If acetone, ethyl alcohol or water is left on an open watch glass, the liquid eventually disappears entirely. In an open system the vapour molecules disperse into the large volume of the room, so the rate of condensation stays far below the rate of evaporation. The two rates can never become equal.

A constant equilibrium vapour pressure can be measured only in a closed container. "Equilibrium in an open system" is a contradiction the examiner will exploit.

Solid–vapour equilibrium

Some solids pass directly into the vapour phase without melting — a process called sublimation. If solid iodine is placed in a closed vessel, the vessel gradually fills with violet vapour whose colour intensifies with time; once the intensity becomes constant, equilibrium is attained. Solid iodine sublimes to give iodine vapour, and the vapour deposits back to solid iodine, so the equilibrium is $\ce{I2(s) <=> I2(g)}$.

SystemEquilibriumObservation at equilibrium
Iodine$\ce{I2(s) <=> I2(g)}$Intensity of violet vapour becomes constant
Camphor$\ce{Camphor(s) <=> Camphor(g)}$Vapour concentration becomes constant
Ammonium chloride$\ce{NH4Cl(s) <=> NH4Cl(g)}$Vapour concentration becomes constant

The situation is closely analogous to the liquid–vapour case: in a closed container at constant temperature the rate of sublimation and the rate of the reverse deposition become equal, and the concentration of vapour above the solid attains a fixed value. Sublimation is also the basis of an important purification technique, as a recent NEET question on the purification of solids that pass directly from solid to vapour confirms.

Build on this

The same dynamic balance of opposing rates underlies chemical reactions. See Equilibrium in Chemical Processes — Dynamic Equilibrium.

Dissolution of solids and gases in liquids

Solids in liquids

Only a limited amount of salt or sugar dissolves in a given quantity of water at a fixed temperature. If a thick syrup is made by dissolving sugar at a higher temperature and then cooled, sugar crystals separate out. A solution in which no more solute can dissolve at a given temperature is called a saturated solution, and the concentration of solute in it depends only on temperature. In a saturated solution a dynamic equilibrium exists between solute in the solid state and solute in solution: $\ce{Sugar(s) <=> Sugar(aq)}$, with the rate of dissolution equal to the rate of crystallisation.

The dynamic nature of this equilibrium has been confirmed using radioactive sugar. When radioactive sugar is dropped into a saturated solution of ordinary, non-radioactive sugar, radioactivity later appears in both the solution and the solid. Although the masses do not change, molecules are continuously exchanged between the two phases until the ratio of radioactive to non-radioactive molecules in solution reaches a constant value.

Gases in liquids

When a soda-water bottle is opened, dissolved carbon dioxide fizzes out rapidly because gas solubility depends on pressure. In the sealed bottle an equilibrium exists between gaseous and dissolved carbon dioxide, $\ce{CO2(g) <=> CO2(aq)}$, established under high pressure. This equilibrium is governed by Henry's law: the mass of a gas dissolved in a given mass of solvent at any temperature is proportional to the pressure of the gas above the solvent, and the dissolved amount decreases as temperature rises.

On opening the bottle, the pressure above the liquid drops to the low partial pressure of CO2 in the atmosphere, so dissolved gas escapes until a new equilibrium is reached for the lower pressure. This is exactly why an open soda-water bottle goes "flat" over time.

ProcessEquilibriumConclusion (Table 6.1, NCERT)
Liquid ⇌ Vapour$\ce{H2O(l) <=> H2O(g)}$$p_{\ce{H2O}}$ constant at a given temperature
Solid ⇌ Liquid$\ce{H2O(s) <=> H2O(l)}$Melting point fixed at constant pressure
Solute(s) ⇌ Solute (solution)$\ce{Sugar(s) <=> Sugar(aq)}$Solubility constant at a given temperature
Gas(g) ⇌ Gas(aq)$\ce{CO2(g) <=> CO2(aq)}$$[\text{gas(aq)}]/[\text{gas(g)}]$ constant at a given temperature

The four general statements that summarise these systems are worth memorising: for solid ⇌ liquid there is a single temperature (the melting point) at 1.013 bar at which the two phases coexist; for liquid ⇌ vapour the vapour pressure is constant at a given temperature; for dissolution of a solid the solubility is constant at a given temperature; and for dissolution of a gas the concentration in the liquid is proportional to the pressure of the gas above it.

General characteristics of physical equilibria

Across all the physical processes above, NCERT §6.1.5 identifies five features common to every system at equilibrium. These are the statements most often quoted verbatim in objective questions, so they reward precise recall.

#CharacteristicWhat it means
1Closed system, fixed temperatureEquilibrium is possible only in a closed system at a given temperature.
2Dynamic but stableBoth opposing processes occur at the same rate; the condition is dynamic yet stable.
3Constant macroscopic propertiesAll measurable properties of the system remain constant.
4Characteristic parameterEquilibrium is marked by a constant value of one parameter at a given temperature (see the conclusions table).
5Indicator of extentThe magnitude of that parameter shows how far the physical process has proceeded before reaching equilibrium.
NEET Trap

"Reaction stopped" is the wrong picture

Constancy of mass, vapour pressure, colour or concentration does not mean the forward and reverse processes have ceased. They proceed at full speed but at equal rates, leaving no net change. Mistaking "no net change" for "no activity" is the classic conceptual error punished in both physical and chemical equilibrium questions.

Equilibrium = equal opposing rates, not zero rates. The radioactive-sugar experiment is the standard proof.

Worked Example

Q. A drop of radioactive sugar is added to a saturated solution of non-radioactive sugar already in equilibrium with solid sugar. After some time, where is radioactivity detected, and why?

A. Radioactivity is detected in both the solution and the solid sugar. At equilibrium $\ce{Sugar(s) <=> Sugar(aq)}$ the rate of dissolution equals the rate of crystallisation, but molecular exchange between phases continues. Radioactive molecules therefore distribute themselves across both phases until the ratio of radioactive to non-radioactive molecules in solution becomes constant — direct evidence that the equilibrium is dynamic, not static.

Quick Recap

Equilibrium in Physical Processes

  • Phase equilibria — $\ce{H2O(s) <=> H2O(l)}$, $\ce{H2O(l) <=> H2O(g)}$, $\ce{I2(s) <=> I2(g)}$ — are all dynamic: opposing processes run at equal rates.
  • Solid–liquid: the normal melting point is the single temperature at 1.013 bar where solid and liquid coexist.
  • Liquid–vapour: equilibrium vapour pressure is constant at a given temperature and rises with temperature; the normal boiling point of water is 100 °C at 1.013 bar.
  • Solid–vapour: sublimation ⇌ deposition reaches constant vapour concentration; it is the basis of purification by sublimation.
  • Dissolution: solubility of a solid is constant at fixed temperature; for a gas, dissolved amount ∝ pressure (Henry's law) and falls as temperature rises.
  • Five characteristics: closed system, dynamic-but-stable, constant macroscopic properties, a characteristic constant parameter, and that parameter indicating the extent of the process.

NEET PYQ Snapshot — Equilibrium in Physical Processes

Physical-equilibrium ideas — sublimation, phase coexistence and dynamic balance — as tested by NTA. Years are from the official papers; conceptual cards are labelled "Concept".

NEET 2024

On heating, some solid substances change from solid to vapour state without passing through liquid state. The technique used for the purification of such solid substances based on the above principle is known as

  • (1) Crystallization
  • (2) Sublimation
  • (3) Distillation
  • (4) Chromatography
Answer: (2) Sublimation

The direct solid → vapour transition is sublimation, and the solid–vapour equilibrium $\ce{I2(s) <=> I2(g)}$ is the basis of purification by sublimation for substances such as iodine, camphor and ammonium chloride.

NEET 2017

A 20 litre container at 400 K contains $\ce{CO2(g)}$ at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is decreased by moving a piston. The maximum volume of the container when the pressure of $\ce{CO2}$ attains its maximum value will be, given $\ce{SrCO3(s) <=> SrO(s) + CO2(g)}$, $K_p = 1.6$ atm:

  • (1) 2 litre
  • (2) 5 litre
  • (3) 10 litre
  • (4) 4 litre
Answer: (2) 5 litre

A solid in equilibrium with its vapour/gas fixes a constant pressure at a given temperature — the heterogeneous analogue of constant vapour pressure. At maximum $p_{\ce{CO2}}$, the value equals $K_p = 1.6$ atm. With temperature constant, $p_1V_1 = p_2V_2$: $0.4 \times 20 = 1.6 \times V_2$, giving $V_2 = 5$ L.

Concept

Ice and water are kept in a perfectly insulated thermos flask at 273 K and 1.013 bar. Which statement is correct about this system?

  • (1) Melting has stopped and the system is static
  • (2) The masses of ice and water change continuously
  • (3) Rate of melting equals rate of freezing; masses stay constant
  • (4) Equilibrium exists at every temperature, not just 273 K
Answer: (3)

At the solid–liquid equilibrium $\ce{H2O(s) <=> H2O(l)}$, melting and freezing proceed simultaneously at equal rates, so the masses remain constant. The equilibrium holds only at the normal melting point (273 K) at 1.013 bar — not at every temperature — and it is dynamic, not static.

FAQs — Equilibrium in Physical Processes

Common conceptual doubts on phase equilibria, drawn from NCERT Class 11 §6.1.

Why is physical equilibrium described as dynamic rather than static?
Although measurable properties such as mass, vapour pressure and concentration stay constant at equilibrium, the two opposing physical processes do not stop. At the ice–water boundary, molecules of water continually freeze onto the ice while molecules of ice melt into the water at exactly the same rate. The constancy is the result of two equal and opposite rates, not the absence of activity, which is precisely why the equilibrium is called dynamic. Radioactive tracer experiments with sugar confirm that exchange between phases continues even after equilibrium is reached.
Why can equilibrium not be reached in an open container for a liquid–vapour system?
In an open system the vapour molecules disperse into the large volume of the surrounding atmosphere, so the rate of condensation back into the liquid stays much smaller than the rate of evaporation. The two rates can never become equal, the liquid eventually disappears completely, and no constant vapour pressure is established. A constant equilibrium vapour pressure can be measured only in a closed vessel where escaping molecules are retained and can return to the liquid.
What is the normal melting point and the normal boiling point?
For any pure substance at atmospheric pressure (1.013 bar), the normal melting point (also the normal freezing point) is the single temperature at which the solid and liquid phases coexist in equilibrium. The normal boiling point is the temperature at which the liquid and its vapour are in equilibrium at 1.013 bar; for water this is 100 °C. The boiling point depends on atmospheric pressure, so at high altitude where pressure is lower the boiling point decreases.
How does Henry's law govern the dissolution of a gas in a liquid?
Henry's law states that the mass of a gas dissolved in a given mass of solvent at a particular temperature is proportional to the pressure of the gas above the solvent. A sealed soda-water bottle holds carbon dioxide dissolved under high pressure. When opened, the pressure above the liquid falls to its low partial pressure in the atmosphere, so dissolved CO2 escapes until a new equilibrium is reached; this is why an open bottle goes flat. The dissolved amount also decreases as temperature is raised.
What does the magnitude of the equilibrium parameter tell us about a physical process?
Each physical equilibrium is characterised by a constant value of one parameter at a given temperature: vapour pressure for liquid–vapour, a fixed melting point for solid–liquid, solubility for dissolution of a solid, and the ratio of concentrations for a dissolved gas. The magnitude of this quantity at any stage indicates the extent to which the physical process has proceeded before reaching equilibrium, and it depends only on temperature for a given substance.