What Counts as a Transition Element
A transition element is defined as one whose atom has an incompletely filled d subshell, or which can give rise to cations with an incomplete d subshell. The d-block proper spans Groups 3 to 12 across the 3d, 4d and 5d series. Scandium and zinc sit at the boundaries and illustrate the definition sharply: $\ce{Zn}$ ($\ce{[Ar]3d^{10}4s^2}$) and its ion $\ce{Zn^2+}$ ($\ce{3d^{10}}$) have a fully filled d shell, so zinc is not regarded as a typical transition element even though it appears in the block.
Because the general properties below flow almost entirely from partly filled d orbitals, it pays to keep the 3d configurations in view. They are the data set on which NEET trend questions are built.
| Element | Z | Config. (atom) | Common states |
|---|---|---|---|
| Sc | 21 | 3d¹4s² | +3 |
| Ti | 22 | 3d²4s² | +2, +3, +4 |
| V | 23 | 3d³4s² | +2 to +5 |
| Cr | 24 | 3d⁵4s¹ | +2 to +6 |
| Mn | 25 | 3d⁵4s² | +2 to +7 |
| Fe | 26 | 3d⁶4s² | +2, +3 |
| Co | 27 | 3d⁷4s² | +2, +3 |
| Ni | 28 | 3d⁸4s² | +2 |
| Cu | 29 | 3d¹⁰4s¹ | +1, +2 |
| Zn | 30 | 3d¹⁰4s² | +2 |
Metallic Character and Physical Properties
Nearly all transition elements display the classic metallic signature: high tensile strength, ductility, malleability, high thermal and electrical conductivity, and metallic lustre. With the exceptions of $\ce{Zn}$, $\ce{Cd}$, $\ce{Hg}$ and $\ce{Mn}$, they crystallise in one or more of the typical close-packed metallic structures (bcc, hcp or ccp) at ordinary temperatures.
The root cause is the strength of the metallic bond. Transition metals can throw both their ns electrons and a number of their (n−1)d electrons into the delocalised bonding lattice. The more unpaired d electrons available, the stronger the binding — which is why hardness, low volatility and high melting points all peak near the middle of a series and ease off towards the ends.
The same logic explains the soft, volatile outliers. $\ce{Zn}$, $\ce{Cd}$ and $\ce{Hg}$ have a complete $\ce{d^{10}}$ shell with no unpaired d electrons to contribute; mercury is liquid at room temperature, and these three are the softest, lowest-melting metals in the block.
Atomic and Ionic Radii Trends
Two trends matter here: how radius changes across a series, and how it changes down a group.
Across a series, ions of the same charge show a progressive decrease in radius with increasing atomic number, and atomic radii follow the same direction. Each added electron enters an inner (n−1)d orbital. A d electron shields the outer electrons rather poorly, so the effective nuclear charge felt by the outermost electron rises and the size contracts. Crucially, though, the variation within a series is small: the d electrons shield the 4s electrons well enough that the radius falls only gently and is nearly constant through the middle of the row.
Down a group the surprise is that the 4d and 5d elements have almost the same radii. On going from the 3d to the 4d series the size increases as expected, but the 5d radii are virtually identical to their 4d partners. The reason is the intervention of the 4f orbitals, which must fill before the 5d series begins. The poor shielding by 4f electrons produces a steady contraction — the lanthanoid contraction — that cancels the expected size increase. The textbook pairing is $\ce{Zr}$ (160 pm) and $\ce{Hf}$ (159 pm), nearly identical in radius and remarkably alike in chemistry.
The 4d ≈ 5d coincidence has its own full treatment, including consequences for separation chemistry, in Lanthanoid Contraction.
Density, Melting and Boiling Points
Transition metals (except $\ce{Zn}$, $\ce{Cd}$, $\ce{Hg}$) are very hard, of low volatility, and have high melting and boiling points. Across the 3d series the melting points rise to a maximum around $\ce{d^5}$ and then fall regularly, except for the anomalously low values of $\ce{Mn}$ and $\ce{Tc}$. The driving factor is again metallic bonding: the more (n−1)d and ns electrons engaged in interatomic bonding, the higher the melting point. One unpaired electron per d orbital — the situation near the middle of the series — is especially favourable for strong interatomic interaction.
Two further generalisations from the enthalpy-of-atomisation data deserve attention. First, the enthalpies of atomisation peak in the middle of each series, confirming that one unpaired d electron per orbital maximises metal–metal bonding. Second, the 4d and 5d metals have greater enthalpies of atomisation than their 3d counterparts, which is why metal–metal bonding is far more common in compounds of the heavier transition metals.
Density rises across the 3d series. The metallic radius shrinks while atomic mass climbs, so mass is packed into a smaller volume. From $\ce{Ti}$ (Z = 22) to $\ce{Cu}$ (Z = 29) the increase is marked — densities run from about 4.1 to nearly 8.9 g cm⁻³.
| Property | Trend across 3d series | Underlying reason |
|---|---|---|
| Atomic radius | Gentle decrease, nearly flat mid-series | Added e⁻ enters inner 3d; weak d shielding; small ΔZeff |
| Density | Increases (≈4.1 → 8.9 g cm⁻³) | Shrinking radius + rising atomic mass |
| Melting / boiling point | Rise to max near d⁵, then fall | Number of unpaired d e⁻ in metallic bonding |
| Enthalpy of atomisation | Maximum near the middle | One unpaired e⁻ per d orbital = strongest bonding |
"Highest melting point = highest atomic number" — wrong
Melting point does not climb monotonically across a series. It peaks near the middle ($\ce{d^5}$ region) and then falls, with $\ce{Mn}$ and $\ce{Tc}$ sitting below the smooth curve. $\ce{Zn}$, with no unpaired d electrons, is the lowest-melting 3d metal.
Tie melting/boiling point to unpaired d electrons in metallic bonding, not to atomic number.
Ionisation Enthalpies
Along each series the ionisation enthalpy generally increases left to right, because nuclear charge rises as the inner d orbitals fill. But two features set transition metals apart from main-group elements. The increase is far less steep than across a typical period of non-transition elements, and the first-ionisation trend across the 3d row is distinctly irregular rather than smooth.
The irregularity comes from the shifting balance of three terms: the attraction of each electron to the nucleus, inter-electronic repulsion, and exchange energy. Exchange energy stabilises configurations with many parallel spins, so half-filled ($\ce{d^5}$) and fully filled ($\ce{d^{10}}$) sets resist losing an electron more than a smooth nuclear-charge argument would predict. This is why the trend breaks at points such as the second ionisation enthalpy of $\ce{Cr}$ (its $\ce{Cr+}$ would be $\ce{d^5}$) and $\ce{Cu}$ (its $\ce{Cu+}$ is $\ce{d^{10}}$), which are unusually high.
The successive enthalpies also behave characteristically: the second and third ionisation enthalpies rise much more sharply than the first because, once the 4s electrons are gone, every further electron is pulled from a $\ce{d^n}$ core where d–d shielding is poor. The high third ionisation enthalpies of $\ce{Cu}$, $\ce{Ni}$ and $\ce{Zn}$ are precisely why oxidation states above +2 are hard to reach for these elements.
| Observation | Cause |
|---|---|
| Overall gentle rise across series | Rising nuclear charge, but d shielding cushions ΔZeff |
| Less steep than non-transition periods | Electrons added to inner shell, not outer |
| High i.e.2 for Cr and Cu | Removing e⁻ from stable d⁵ / d¹⁰ ($\ce{Cr+}$, $\ce{Cu+}$) |
| High i.e.3 for Cu, Ni, Zn | Why states > +2 are difficult here |
Mixing up the i.e.₂ anomalies of Cr and Mn
The unusually high second ionisation enthalpy of $\ce{Cr}$ arises because $\ce{Cr+}$ ($\ce{d^5}$) is stable; for $\ce{Cu}$ it is $\ce{Cu+}$ ($\ce{d^{10}}$). Separately, the third ionisation enthalpy of $\ce{Mn}$ is high because $\ce{Mn^2+}$ ($\ce{d^5}$) is stable, whereas $\ce{Fe^3+}$ ($\ce{d^5}$) explains why $\ce{Fe}$'s third ionisation enthalpy is comparatively low.
Always ask: what configuration is the ion being formed? A $\ce{d^5}$ or $\ce{d^{10}}$ product is extra stable.
Standard Electrode Potentials (E°)
The lowest common oxidation state of these metals is +2. Forming $\ce{M^2+(aq)}$ from the gaseous atom needs the enthalpy of atomisation plus the first and second ionisation enthalpies, offset by the hydration enthalpy of $\ce{M^2+}$. The $\ce{E^\circ}$(M²⁺/M) value is set by how these terms balance, so it is a thermochemical composite rather than a single quantity.
The general trend is towards less negative $\ce{E^\circ}$ values across the series, mirroring the increasing sum of the first and second ionisation enthalpies. But the curve is not smooth — $\ce{Mn}$, $\ce{Ni}$ and $\ce{Zn}$ are more negative than the trend predicts:
| Couple | E° / V | Note |
|---|---|---|
| $\ce{Sc^2+/Sc}$ | — | +2 state not characteristic |
| $\ce{Ti^2+/Ti}$ | −1.63 | |
| $\ce{V^2+/V}$ | −1.18 | |
| $\ce{Cr^2+/Cr}$ | −0.90 | |
| $\ce{Mn^2+/Mn}$ | −1.18 | More negative — stable d⁵ in $\ce{Mn^2+}$ |
| $\ce{Fe^2+/Fe}$ | −0.44 | |
| $\ce{Co^2+/Co}$ | −0.28 | |
| $\ce{Ni^2+/Ni}$ | −0.25 | More negative — highest hydration enthalpy |
| $\ce{Cu^2+/Cu}$ | +0.34 | Positive — does not displace H₂ |
| $\ce{Zn^2+/Zn}$ | −0.76 | More negative — stable d¹⁰ in $\ce{Zn^2+}$ |
Copper is the standout: its $\ce{E^\circ}$ is positive (+0.34 V). The high energy needed to convert $\ce{Cu(s) -> Cu^2+(aq)}$ — a large enthalpy of atomisation plus high ionisation enthalpies — is not balanced by its hydration enthalpy, so copper cannot liberate hydrogen from non-oxidising acids. Only oxidising acids attack it:
$\ce{3Cu + 8HNO3(dilute) -> 3Cu(NO3)2 + 2NO ^ + 4H2O}$
The $\ce{E^\circ}$(M³⁺/M²⁺) values tell a parallel story driven by ion stability. The low value for $\ce{Sc}$ reflects the noble-gas stability of $\ce{Sc^3+}$; the high value for $\ce{Mn}$ shows that $\ce{Mn^2+}$ ($\ce{d^5}$) resists oxidation; the comparatively low value for $\ce{Fe}$ reflects the extra stability of $\ce{Fe^3+}$ ($\ce{d^5}$). These same energetics make $\ce{Cr^2+}$ a reducing agent (it moves to the half-filled $t_{2g}$ $\ce{d^3}$) while $\ce{Mn^3+}$ is oxidising (it falls to $\ce{Mn^2+}$, $\ce{d^5}$).
Why is the stability of $\ce{Cu^2+}$ salts in aqueous solution greater than that of $\ce{Cu+}$ salts? (NEET 2023)
Although the second ionisation enthalpy of copper is large (+1960 kJ mol⁻¹), the hydration enthalpy of $\ce{Cu^2+(aq)}$ (about −2121 kJ mol⁻¹) is far more negative than that of $\ce{Cu+(aq)}$. The much greater hydration energy of the doubly charged, smaller $\ce{Cu^2+}$ ion more than compensates for the extra ionisation energy, so $\ce{Cu^2+(aq)}$ is the more stable species. This is why $\ce{Cu+}$ disproportionates in water: $\ce{2Cu+ -> Cu^2+ + Cu}$.
Formation of Coloured Ions
Most transition metal ions are coloured in the solid state and in solution — one of the most visible signatures of the block. The mechanism is a d–d transition: when the ion has partly filled d orbitals, an electron can be promoted from a lower-energy d orbital to a higher-energy d orbital. The energy gap corresponds to a frequency in the visible region, so visible light is absorbed and the ion appears in the complementary colour of the light absorbed. The size of the gap, and hence the colour, is governed by the nature of the surrounding ligand (in aqueous solution, water).
| Ion | d-configuration | Colour (aqueous) |
|---|---|---|
| $\ce{Sc^3+}$ | d⁰ | Colourless |
| $\ce{Ti^3+}$ | d¹ | Purple |
| $\ce{V^3+}$ | d² | Green |
| $\ce{Cr^3+}$ | d³ | Violet |
| $\ce{Mn^2+}$ | d⁵ | Pink |
| $\ce{Fe^2+}$ | d⁶ | Green |
| $\ce{Fe^3+}$ | d⁵ | Yellow |
| $\ce{Co^2+}$ | d⁷ | Pink |
| $\ce{Ni^2+}$ | d⁸ | Green |
| $\ce{Cu^2+}$ | d⁹ | Blue |
| $\ce{Zn^2+}$ | d¹⁰ | Colourless |
d⁰ and d¹⁰ ions are colourless
No partly filled d set means no d–d transition. $\ce{Sc^3+}$ ($\ce{d^0}$), $\ce{Ti^4+}$ ($\ce{d^0}$), $\ce{Zn^2+}$ ($\ce{d^{10}}$) and $\ce{Cu+}$ ($\ce{d^{10}}$) are all colourless. Note also that the intense colours of $\ce{MnO4^-}$ (purple) and $\ce{Cr2O7^2-}$ (orange) arise from charge-transfer, not d–d transitions, since their metal centres are d⁰.
Colour from d–d transition requires 1 ≤ d electrons ≤ 9.
The mechanics of how the d orbitals split into two energy sets under a ligand field — and how the gap controls colour and magnetism — belongs to crystal field theory and the magnetism discussion. For the energetic basis of paramagnetism and the spin-only formula, see the dedicated note linked below.
Complex Formation
Transition metals form an enormous number of complex compounds — species in which a metal ion binds several anions or neutral molecules (ligands). Familiar examples include $\ce{[Fe(CN)6]^3-}$, $\ce{[Fe(CN)6]^4-}$, $\ce{[Cu(NH3)4]^2+}$ and $\ce{[PtCl4]^2-}$.
Three features of the metal ions explain this readiness to complex: their comparatively small size, their high ionic charge, and the availability of vacant d orbitals of suitable energy to accept lone pairs from ligands. Together these give a high charge density and the right orbitals for coordinate bonding. The detailed bonding, geometry, isomerism and nomenclature of these species are taken up fully in Coordination Compounds.
General properties at a glance
- Metallic character: hard, lustrous, conducting; (n−1)d + ns electrons in metallic bonding. Zn, Cd, Hg, Mn are exceptions.
- Atomic radius: small, gentle decrease across a series; 4d ≈ 5d radii because of the lanthanoid contraction (Zr ≈ Hf).
- Density / m.p. / b.p.: high; melting point peaks near d⁵, dips at Mn; density rises across the 3d row.
- Ionisation enthalpy: rises gently and irregularly; anomalies tied to stable d⁵ / d¹⁰ ions.
- E°(M²⁺/M): generally less negative across the series; Cu positive (+0.34 V); Mn, Ni, Zn more negative than trend.
- Colour: from d–d transitions; d⁰ and d¹⁰ ions are colourless.
- Complexes: favoured by small size, high charge and vacant d orbitals.