Chemistry · Coordination Compounds

Crystal Field Theory (CFT)

Valence bond theory tells us how a complex is held together, but it cannot say why $\ce{[Ti(H2O)6]^3+}$ is violet or why $\ce{[CoF6]^3-}$ is paramagnetic while $\ce{[Co(NH3)6]^3+}$ is not. Crystal Field Theory (CFT) — developed in NCERT Class 12 Chemistry §5.5.4–5.5.6 and supplemented in NIOS §22.5 — supplies the missing electronic picture. By treating ligands as point charges that split the d orbitals, CFT explains the colour, magnetism and relative stability of coordination compounds, and it has anchored a steady stream of NEET questions on splitting, the spectrochemical series and high-spin versus low-spin behaviour.

The Basic Idea of CFT

Crystal Field Theory is an electrostatic model. It considers the metal–ligand bond to be ionic, arising purely from electrostatic interactions between the central metal ion and the surrounding ligands. The ligands are not treated as atoms with their own orbitals; they are reduced to point charges (for anionic ligands such as $\ce{Cl-}$ and $\ce{CN-}$) or point dipoles (for neutral ligands such as $\ce{NH3}$ and $\ce{H2O}$, whose negative ends face the metal).

The starting point is the five d orbitals of an isolated gaseous metal ion. These are degenerate — all of identical energy. If we imagine the metal ion surrounded by a perfectly spherical shell of negative charge, all five orbitals are raised in energy by the same amount and remain degenerate. The crucial step comes when that negative field is supplied by ligands placed at definite positions: the field becomes asymmetric, the degeneracy is lifted, and the d orbitals split into sets of unequal energy. The exact pattern of this splitting depends on the geometry of the ligand field.

The whole edifice of CFT rests on one physical fact: a d orbital that points towards an approaching ligand is repelled strongly and rises in energy, while a d orbital that points between the ligands is repelled less and is lowered relative to the average. Everything that follows — colour, magnetism, stability — is a consequence of how the d electrons distribute themselves over these split levels.

NEET Trap

CFT is ionic, VBT is covalent

Students often blur the two bonding models. Valence Bond Theory describes hybridised orbitals overlapping with ligand lone pairs — a covalent picture. CFT throws bonding away entirely and treats the interaction as pure electrostatic repulsion between point charges and d electrons.

Remember: CFT does not use hybridisation. If a question speaks of t₂g/eg sets and Δ, it is CFT; if it speaks of $d^2sp^3$ or $sp^3d^2$, it is VBT.

Splitting in an Octahedral Field

In an octahedral coordination entity, six ligands approach the metal ion along the $\pm x$, $\pm y$ and $\pm z$ axes. The repulsion between the d electrons and the ligand charges is greater for orbitals that point along these axes. The $d_{x^2-y^2}$ and $d_{z^2}$ orbitals point directly at the ligands and are therefore raised in energy; collectively they form the higher-energy $e_g$ set. The $d_{xy}$, $d_{yz}$ and $d_{xz}$ orbitals point between the axes, away from the ligands, and are lowered; they form the lower-energy $t_{2g}$ set.

The energy separation between the $t_{2g}$ and $e_g$ sets is the crystal field splitting energy, written $\Delta_o$ (the subscript o for octahedral). The splitting conserves the average energy (the "barycentre"): the two $e_g$ orbitals rise by $\tfrac{3}{5}\Delta_o$ each, while the three $t_{2g}$ orbitals fall by $\tfrac{2}{5}\Delta_o$ each, so the total energy is unchanged.

Figure 1

d-orbital splitting in an octahedral crystal field

5 degenerate d orbitals (free / spherical field) barycentre eₜ dₓ²−ₙ², dₘ² t₂ₘ dₓₙ, dₙ₧, dₓ₧ Δₒ + (3/5)Δₒ − (2/5)Δₒ

The two $e_g$ orbitals rise by $\tfrac{3}{5}\Delta_o$; the three $t_{2g}$ orbitals fall by $\tfrac{2}{5}\Delta_o$. The gap $\Delta_o$ is the octahedral crystal field splitting energy.

Spectrochemical Series & Δo

The size of $\Delta_o$ is not fixed; it depends on the field produced by the ligand and on the charge on the metal ion. Some ligands produce strong fields and a large splitting; others produce weak fields and a small splitting. Arranging ligands in order of increasing field strength gives the spectrochemical series, an experimentally determined ordering based on the light absorbed by complexes:

$\ce{I- < Br- < SCN- < Cl- < S^2- < F- < OH- < C2O4^2- < H2O < NCS- < edta^4- < NH3 < en < CN- < CO}$

Ligands at the left (the halides, $\ce{S^2-}$) are weak-field; those at the right ($\ce{NH3}$, $\ce{en}$, $\ce{CN-}$, $\ce{CO}$) are strong-field. The position of a ligand in this series controls $\Delta_o$, which in turn controls colour and magnetism. Note that a higher metal oxidation state also increases $\Delta_o$.

PropertyWeak-field ligandStrong-field ligand
ExamplesI⁻, Br⁻, F⁻, H₂ONH₃, en, CN⁻, CO
Splitting $\Delta_o$SmallLarge
Relation to pairing energy $P$$\Delta_o < P$$\Delta_o > P$
Spin state (d⁴–d⁷)High spinLow spin
Unpaired electronsMaximumMinimum

High-Spin vs Low-Spin

For configurations $d^1$, $d^2$ and $d^3$ there is no ambiguity: the electrons enter the three $t_{2g}$ orbitals singly, obeying Hund's rule. The interesting choice appears at $d^4$. The fourth electron has two options. It can pair up in a $t_{2g}$ orbital, paying the price of the pairing energy $P$, or it can jump to the higher $e_g$ level, paying the price of $\Delta_o$. Which route is cheaper decides the spin state:

Conditiond⁴ configurationField typeResult
$\Delta_o < P$$t_{2g}^{3}\,e_g^{1}$Weak fieldHigh spin (4 unpaired)
$\Delta_o > P$$t_{2g}^{4}\,e_g^{0}$Strong fieldLow spin (2 unpaired)

When $\Delta_o$ is small (weak-field ligand), it costs less to promote the electron to $e_g$ than to pair it, so the electrons spread out — a high-spin complex with the maximum number of unpaired electrons. When $\Delta_o$ is large (strong-field ligand), pairing in the $t_{2g}$ set is the cheaper option, giving a low-spin complex. NCERT notes that for the same reason, $d^4$ to $d^7$ entities are more stable in the strong-field case.

Compare models

CFT explains why a complex is high or low spin; VBT predicts the same spin states through inner- versus outer-orbital hybridisation. See Valence Bond Theory of Coordination Compounds to line the two pictures up side by side.

Electron Filling d¹–d¹⁰

The table below summarises how the $t_{2g}$ and $e_g$ sets fill in an octahedral field. For $d^1$–$d^3$ and $d^8$–$d^{10}$ the weak-field and strong-field arrangements are identical; only $d^4$–$d^7$ branch into distinct high-spin and low-spin patterns.

dⁿHigh spin (weak field)Unpaired e⁻Low spin (strong field)Unpaired e⁻
$t_{2g}^{1}$1$t_{2g}^{1}$1
$t_{2g}^{2}$2$t_{2g}^{2}$2
$t_{2g}^{3}$3$t_{2g}^{3}$3
d⁴$t_{2g}^{3}e_g^{1}$4$t_{2g}^{4}e_g^{0}$2
d⁵$t_{2g}^{3}e_g^{2}$5$t_{2g}^{5}e_g^{0}$1
d⁶$t_{2g}^{4}e_g^{2}$4$t_{2g}^{6}e_g^{0}$0
d⁷$t_{2g}^{5}e_g^{2}$3$t_{2g}^{6}e_g^{1}$1
d⁸$t_{2g}^{6}e_g^{2}$2$t_{2g}^{6}e_g^{2}$2
d⁹$t_{2g}^{6}e_g^{3}$1$t_{2g}^{6}e_g^{3}$1
d¹⁰$t_{2g}^{6}e_g^{4}$0$t_{2g}^{6}e_g^{4}$0

Crystal Field Stabilisation Energy

Because the $t_{2g}$ orbitals lie below the barycentre, every electron placed there lowers the energy of the system, while electrons in $e_g$ raise it. The net energy lowering relative to the unsplit (spherical) field is the Crystal Field Stabilisation Energy (CFSE). Counting $-\tfrac{2}{5}\Delta_o$ for each $t_{2g}$ electron and $+\tfrac{3}{5}\Delta_o$ for each $e_g$ electron gives:

$\text{CFSE} = \left[-\tfrac{2}{5}\,n(t_{2g}) + \tfrac{3}{5}\,n(e_g)\right]\Delta_o + mP$

where $n(t_{2g})$ and $n(e_g)$ are the electron counts in each set and $mP$ accounts for any extra electron pairs forced by a strong field. CFSE explains why $d^4$–$d^7$ complexes gain extra stability in strong fields, and it underlies trends in lattice energies, hydration enthalpies and the preference of certain ions for octahedral over tetrahedral sites. For NEET, the key takeaway is the sign convention: $t_{2g}$ electrons stabilise, $e_g$ electrons destabilise.

Worked Example

CFSE of low-spin $\ce{[Fe(CN)6]^3-}$ (a $d^5$ ion).

$\ce{CN-}$ is a strong-field ligand, so $\Delta_o > P$ and the configuration is $t_{2g}^{5}e_g^{0}$. CFSE $= [-\tfrac{2}{5}(5) + \tfrac{3}{5}(0)]\Delta_o + 2P = -2.0\,\Delta_o + 2P$. With one unpaired electron the spin-only moment is $\mu = \sqrt{1(1+2)} = 1.73\ \text{BM}$ — exactly the value matched in the NEET 2021 magnetic-moment matching question.

Splitting in a Tetrahedral Field

A tetrahedral field inverts the octahedral picture. Here only four ligands surround the metal, and none of them points directly at any d orbital. The orbitals that come closer to the ligand directions — $d_{xy}$, $d_{yz}$, $d_{xz}$ (the $t_2$ set) — are now raised in energy, while $d_{x^2-y^2}$ and $d_{z^2}$ (the $e$ set) are lowered. Because the tetrahedron has no centre of symmetry, the "g" subscript is dropped: we write $e$ and $t_2$, not $e_g$ and $t_{2g}$.

Crucially, the tetrahedral splitting is much smaller. For the same metal, the same ligands and the same metal–ligand distance it can be shown that $\Delta_t = \tfrac{4}{9}\,\Delta_o$. This splitting is so small that it is almost never larger than the pairing energy, so tetrahedral complexes are nearly always high spin — low-spin tetrahedral complexes are rarely observed.

Figure 2

Tetrahedral splitting (inverted, small) vs the spectrochemical scale

Tetrahedral field barycentre t₂ e Δₜ = (4/9) Δₒ Spectrochemical scale weak field strong field I⁻ < F⁻ < H₂O < NH₃ < en < CN⁻ < CO small Δ large Δ Larger Δ → higher energy absorbed → shorter absorbed wavelength λ $\\Delta = h\\nu = hc/\\lambda$

Left: the tetrahedral split is inverted ($e$ below $t_2$) and small. Right: as field strength rises along the spectrochemical series, $\Delta$ grows, the absorbed photon energy rises and the absorbed wavelength shortens.

Colour by d–d Transitions

One of the most distinctive properties of transition-metal complexes is their wide range of colours, and CFT explains it directly. When white light passes through a complex, light of energy equal to $\Delta$ is absorbed and promotes an electron from the lower d set to the higher one — a d–d transition. The wavelengths not absorbed are transmitted, so the observed colour is the complementary colour of the light absorbed. If a complex absorbs green light it appears red.

The classic example is $\ce{[Ti(H2O)6]^3+}$, a $3d^1$ system. Its single electron sits in the $t_{2g}$ level in the ground state. Absorption of blue-green light excites the transition $t_{2g}^{1}e_g^{0} \rightarrow t_{2g}^{0}e_g^{1}$, and the complex appears violet. The energy relationship is simply $\Delta = h\nu = \dfrac{hc}{\lambda}$, so a larger $\Delta$ means a higher energy absorbed and therefore a shorter absorbed wavelength.

Coordination entityLight absorbedColour observed
$\ce{[CoCl(NH3)5]^2+}$YellowViolet
$\ce{[Co(NH3)5(H2O)]^3+}$Blue-greenRed
$\ce{[Co(NH3)6]^3+}$BlueYellow-orange
$\ce{[Co(CN)6]^3-}$UltravioletPale yellow
$\ce{[Cu(H2O)4]^2+}$RedBlue
$\ce{[Ti(H2O)6]^3+}$Blue-greenViolet
NEET Trap

No ligand, no d–d transition, no colour

If there is no ligand field, the d orbitals stay degenerate and no d–d transition is possible — the substance is colourless or white. Removing water from $\ce{[Ti(H2O)6]Cl3}$ on heating renders it colourless; anhydrous $\ce{CuSO4}$ is white whereas $\ce{CuSO4.5H2O}$ is blue. Likewise, $d^0$ and $d^{10}$ ions (no possible d–d transition) are typically colourless.

Stronger ligand ⇒ larger Δ ⇒ higher energy / shorter wavelength absorbed. For the same metal, energy absorbed follows the spectrochemical order: $\ce{H2O < NH3 < en < CN-}$.

Magnetic Behaviour

Because CFT fixes the number of unpaired electrons through the high-spin/low-spin choice, it predicts the magnetic behaviour of a complex. A complex with one or more unpaired electrons is paramagnetic; one with all electrons paired is diamagnetic. The spin-only magnetic moment follows $\mu = \sqrt{n(n+2)}\ \text{BM}$, where $n$ is the number of unpaired electrons.

This is exactly where weak and strong fields diverge. Both $\ce{[Fe(H2O)6]^3+}$ (weak field, high spin, $t_{2g}^{3}e_g^{2}$, five unpaired) and $\ce{[Fe(CN)6]^3-}$ (strong field, low spin, $t_{2g}^{5}$, one unpaired) are $d^5$ iron(III), yet their moments are $5.92$ BM and $1.73$ BM respectively. The same logic explains why $\ce{[CoF6]^3-}$ is paramagnetic while $\ce{[Co(NH3)6]^3+}$ is diamagnetic. Magnetic susceptibility measurements are therefore a direct experimental probe of the spin state predicted by CFT.

Complex (d⁵/d⁶)FieldConfigurationUnpaired e⁻μ (BM)
$\ce{[Fe(H2O)6]^3+}$Weak$t_{2g}^{3}e_g^{2}$55.92
$\ce{[Fe(CN)6]^3-}$Strong$t_{2g}^{5}$11.73
$\ce{[Fe(H2O)6]^2+}$Weak$t_{2g}^{4}e_g^{2}$44.90
$\ce{[Fe(CN)6]^4-}$Strong$t_{2g}^{6}$00

Limitations of CFT

CFT is remarkably successful at explaining the formation, structures, colour and magnetic properties of coordination compounds. But its founding assumption — that ligands are pure point charges — has consequences that disagree with experiment. If the interaction were purely electrostatic, anionic ligands should produce the greatest splitting; yet anionic ligands such as the halides actually sit at the low (weak-field) end of the spectrochemical series, while neutral $\ce{CO}$ and $\ce{CN-}$ produce the largest splitting.

The deeper flaw is that CFT ignores the covalent character of the metal–ligand bond. It cannot account for overlap between metal and ligand orbitals or for $\pi$-bonding effects, both of which are needed to rationalise the order of the spectrochemical series. These shortcomings are addressed by Ligand Field Theory and Molecular Orbital Theory, which restore the covalent contribution that CFT discards.

Quick Recap

Crystal Field Theory in ten lines

  • CFT is an electrostatic model; ligands are point charges (anions) or point dipoles (neutral molecules).
  • The asymmetric ligand field lifts d-orbital degeneracy and splits them.
  • Octahedral: lower $t_{2g}$ (−2/5 Δ₀) and higher $e_g$ (+3/5 Δ₀), gap $\Delta_o$.
  • Tetrahedral: inverted ($e$ below $t_2$), no "g", and $\Delta_t = \tfrac{4}{9}\Delta_o$ — so almost always high spin.
  • Spectrochemical series ranks ligand field strength: $\ce{I- < ... < H2O < NH3 < en < CN- < CO}$.
  • $\Delta_o < P$ ⇒ high spin (weak field); $\Delta_o > P$ ⇒ low spin (strong field); only matters for d⁴–d⁷.
  • CFSE $= [-\tfrac{2}{5}n(t_{2g}) + \tfrac{3}{5}n(e_g)]\Delta_o$ measures the stabilisation.
  • Colour arises from d–d transitions; observed colour is complementary to that absorbed.
  • Larger Δ ⇒ higher energy / shorter wavelength absorbed.
  • Magnetic moment $\mu = \sqrt{n(n+2)}$ BM; CFT's main limits are point-charge assumption and neglect of covalency.

NEET PYQ Snapshot — Crystal Field Theory (CFT)

Real NEET previous-year questions that turn on splitting, ligand field strength, colour and magnetism.

NEET 2025 · Q.49

The correct order of the wavelength of light absorbed by the following complexes is: A. $\ce{[Co(NH3)6]^3+}$   B. $\ce{[Co(CN)6]^3-}$   C. $\ce{[Cu(H2O)4]^2+}$   D. $\ce{[Ti(H2O)6]^3+}$.

  1. C < A < D < B
  2. B < D < A < C
  3. B < A < D < C
  4. C < D < A < B
Answer: (3) B < A < D < C

Stronger ligand ⇒ larger Δ ⇒ higher energy ⇒ shorter wavelength absorbed. The measured values are B (310 nm) < A (475 nm) < D (498 nm) < C (600 nm), so wavelength increases as Δ falls: $\ce{CN-} > \ce{NH3}$, with the $\ce{Cu^2+}$ aqua complex absorbing the longest wavelength.

NEET 2022 · Q.86

The order of energy absorbed (responsible for colour) for A. $\ce{[Ni(H2O)2(en)2]^2+}$, B. $\ce{[Ni(H2O)4(en)]^2+}$, C. $\ce{[Ni(en)3]^2+}$ is:

  1. (C) > (B) > (A)
  2. (C) > (A) > (B)
  3. (B) > (A) > (C)
  4. (A) > (B) > (C)
Answer: (2) (C) > (A) > (B)

$\ce{en}$ is a stronger-field ligand than $\ce{H2O}$ in the spectrochemical series, so the more $\ce{en}$ ligands a complex has, the larger its Δ and the higher the energy absorbed: $\ce{[Ni(en)3]^2+} > \ce{[Ni(H2O)2(en)2]^2+} > \ce{[Ni(H2O)4(en)]^2+}$.

NEET 2020 · Q.174

Which is the correct order of increasing field strength of ligands?

  1. $\ce{SCN- < F- < CN- < C2O4^2-}$
  2. $\ce{F- < SCN- < C2O4^2- < CN-}$
  3. $\ce{CN- < C2O4^2- < SCN- < F-}$
  4. $\ce{SCN- < F- < C2O4^2- < CN-}$
Answer: (4) $\ce{SCN- < F- < C2O4^2- < CN-}$

Direct reading of the spectrochemical series: $\ce{SCN-}$ (S-bonded) and $\ce{F-}$ are weak-field, $\ce{C2O4^2-}$ is intermediate, and $\ce{CN-}$ is among the strongest. Field strength rises left to right.

NEET 2021 · Q.87

Match the iron complexes with their spin-only magnetic moments: (a) $\ce{[Fe(CN)6]^3-}$ (b) $\ce{[Fe(H2O)6]^3+}$ (c) $\ce{[Fe(CN)6]^4-}$ (d) $\ce{[Fe(H2O)6]^2+}$ — with (i) 5.92, (ii) 0, (iii) 4.90, (iv) 1.73 BM.

  1. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
  2. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
  3. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
  4. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
Answer: (1) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

$\ce{CN-}$ is strong-field (low spin): $\ce{[Fe(CN)6]^3-}$ ($d^5$, $t_{2g}^5$) has 1 unpaired electron (1.73 BM); $\ce{[Fe(CN)6]^4-}$ ($d^6$, $t_{2g}^6$) has 0 (0 BM). $\ce{H2O}$ is weak-field (high spin): $\ce{[Fe(H2O)6]^3+}$ ($d^5$) has 5 (5.92 BM); $\ce{[Fe(H2O)6]^2+}$ ($d^6$) has 4 (4.90 BM). Using $\mu = \sqrt{n(n+2)}$.

FAQs — Crystal Field Theory (CFT)

Six concept checks NEET aspirants raise most often on splitting, colour and spin.

What is the basic idea of Crystal Field Theory?

Crystal Field Theory is an electrostatic model that treats the metal–ligand bond as purely ionic, arising from electrostatic interaction between the metal ion and the ligands. Ligands are taken as point charges (anions) or point dipoles (neutral molecules like NH3 and H2O). The five d orbitals, which are degenerate in a free gaseous ion, lose their degeneracy when surrounded by an asymmetric ligand field, and the orbitals split into sets of different energy.

Why is Δt smaller than Δo and equal to 4/9 Δo?

In a tetrahedral field only four ligands surround the metal, fewer than the six in an octahedral field, and none of the d orbitals point directly at a ligand, so the repulsion is weaker. For the same metal, same ligands and same metal–ligand distance it can be shown that Δt = (4/9) Δo. Because Δt is small it is almost always less than the pairing energy, so tetrahedral complexes are nearly always high spin and low-spin tetrahedral complexes are rarely observed.

How does CFT explain the colour of coordination compounds?

When the complex absorbs visible light, an electron is promoted from a lower-energy d set to a higher-energy d set (a d–d transition), the energy gap being equal to the crystal field splitting. The complex transmits the wavelengths that are not absorbed, so its observed colour is the complementary colour of the light absorbed. For example, [Ti(H2O)6]3+ absorbs in the blue-green region and therefore appears violet. A larger splitting means a higher energy of light absorbed and hence a shorter absorbed wavelength.

What decides whether a complex is high spin or low spin?

It depends on the relative magnitudes of the crystal field splitting Δo and the pairing energy P. If Δo is less than P (weak field ligands), electrons spread out to avoid pairing and a high-spin complex with maximum unpaired electrons results. If Δo is greater than P (strong field ligands), electrons pair up in the lower t2g set first, giving a low-spin complex with fewer unpaired electrons. This decision only arises for d4 to d7 octahedral configurations.

What is the spectrochemical series?

It is an experimentally determined arrangement of ligands in order of increasing field strength, based on the light absorbed by their complexes: I⁻ < Br⁻ < SCN⁻ < Cl⁻ < S²⁻ < F⁻ < OH⁻ < C2O4²⁻ < H2O < NCS⁻ < edta⁴⁻ < NH3 < en < CN⁻ < CO. Ligands on the left are weak-field (small Δ, high spin) and those on the right are strong-field (large Δ, low spin).

What are the main limitations of Crystal Field Theory?

CFT assumes that ligands are pure point charges, from which it follows that anionic ligands should cause the greatest splitting; in reality anionic ligands lie at the low (weak) end of the spectrochemical series. CFT also ignores the covalent character of the metal–ligand bond. These shortcomings mean it cannot explain the ordering of the spectrochemical series or covalency effects, which are addressed by ligand field and molecular orbital theories.