Definition and the Defining Equation
When an electron is added to a neutral gaseous atom $\ce{X}$ to convert it into a uninegative ion, the enthalpy change accompanying the process is defined as the electron gain enthalpy, $\Delta_{eg}H$. It is a quantitative measure of the ease with which an atom accepts an electron to form an anion. The defining process is written exactly as NCERT states it:
$$\ce{X(g) + e- -> X^-(g)} \qquad \Delta_{eg}H$$
The qualitative driving force behind the whole property is the universal tendency of an atom to acquire a noble-gas configuration. The NIOS text frames it directly: an atom with five, six or seven electrons in its outermost shell shows a tendency to accept electrons and reach the nearest noble-gas arrangement. Halogens, with seven valence electrons, need just one more electron, so they release the most energy on electron capture; metals, which would have to take several, instead show high positive values.
For the halogens, this is the step that takes a neutral atom to its stable closed-shell anion. Taking chlorine, the NCERT/NIOS-documented value is:
$$\ce{Cl(g) + e- -> Cl^-(g)} \qquad \Delta_{eg}H = -349~\text{kJ mol}^{-1}$$
Two features of this definition matter for every problem you will meet. First, $\Delta_{eg}H$ is defined for the gaseous state, so lattice or hydration effects are excluded — it is a property of the isolated atom. Second, the magnitude reflects how strongly the nucleus can hold one extra electron once it has been pulled in; the sign tells you whether the atom wanted that electron at all.
A neutral gaseous atom captures a free electron and releases (or, for noble gases, absorbs) energy. The colour of the energy arrow encodes the sign of $\Delta_{eg}H$.
The Sign Convention — Read This Twice
This is the single most confused point in the entire subtopic, and it is where NEET sets its traps. Because adding an electron usually releases energy, and because $\Delta_{eg}H$ follows the standard thermodynamic convention in which released energy is negative, a more negative value means a greater tendency to accept an electron — the opposite of the intuitive "bigger number is better" reasoning.
Negative means energy released, which means a stronger tendency to gain an electron.
An exothermic electron capture is assigned a negative $\Delta_{eg}H$. So when a question asks for the element with the most negative electron gain enthalpy, it is asking for the element that releases the most energy and accepts an electron most readily — that is chlorine, $-349~\text{kJ mol}^{-1}$. Do not pick fluorine just because it is the most electronegative element.
More negative $\Delta_{eg}H$ = more energy released = stronger electron-accepting tendency. A positive $\Delta_{eg}H$ (noble gases) means energy must be supplied — the atom resists the electron.
Group 17 elements have very high negative electron gain enthalpies precisely because by picking up one electron they reach a stable noble-gas configuration. By contrast, the closer an element already is to a filled or stable arrangement on its own, the weaker its drive to take an extra electron, pushing $\Delta_{eg}H$ toward less negative — and for the noble gases, positive — values.
Electron Gain Enthalpy Values (NCERT Table 3.7)
The numbers below are taken verbatim from NCERT Table 3.7. Commit the halogen and noble-gas rows to memory; almost every PYQ on this subtopic is decided by them. All values are in $\text{kJ mol}^{-1}$.
| Group 1 | ΔegH | Group 16 | ΔegH | Group 17 | ΔegH | Group 18 | ΔegH |
|---|---|---|---|---|---|---|---|
| H | −73 | — | — | — | — | He | +48 |
| Li | −60 | O | −141 | F | −328 | Ne | +116 |
| Na | −53 | S | −200 | Cl | −349 | Ar | +96 |
| K | −48 | Se | −195 | Br | −325 | Kr | +96 |
| Rb | −47 | Te | −190 | I | −295 | Xe | +77 |
| Cs | −46 | Po | −174 | At | −270 | Rn | +68 |
Read the table column by column. The halogens are sharply negative and the noble gases are uniformly positive — a contrast that captures the whole physical picture in one glance. Within group 1 and group 16 the values become less negative on descending (Li to Cs; O to Po), which is the normal group trend. Group 17 obeys the same descent except at its very top, where F is less negative than Cl — the anomaly examined below.
Trends Across a Period and Down a Group
NCERT cautions that the variation in electron gain enthalpies is less systematic than that of ionisation enthalpies, so these are general rules with documented exceptions rather than rigid laws.
| Direction | General behaviour of ΔegH | Reason (per NCERT §3.7.1) |
|---|---|---|
| Left → right across a period | Becomes more negative | Effective nuclear charge increases and atomic size decreases, so the added electron sits closer to the nucleus and is bound more strongly. |
| Top → bottom down a group | Becomes less negative | Atomic size increases, so the incoming electron enters a level farther from the nucleus and is held more weakly. |
NCERT also notes that electron gain enthalpies reach their largest negative values toward the upper-right region of the periodic table, just before the noble gases — the halogen corner. This is the same nuclear-pull logic that drives ionisation enthalpy and electronegativity trends, all three rooted in how tightly a shrinking atom grips its valence region.
Arrows show the direction in which $\Delta_{eg}H$ becomes more negative. The strongest electron-accepting corner is upper-right, at the halogens; the broken arrow at the top of group 17 marks the F < Cl reversal.
The Fluorine vs Chlorine Anomaly
On the simple group rule, fluorine — the topmost, smallest halogen — should release the most energy on gaining an electron. It does not. The NCERT values are $\Delta_{eg}H(\ce{F}) = -328$ and $\Delta_{eg}H(\ce{Cl}) = -349~\text{kJ mol}^{-1}$, so chlorine is more negative than fluorine, and chlorine in fact holds the most negative electron gain enthalpy of any element.
$$\ce{F(g) + e- -> F^-(g)}\,,\ \Delta_{eg}H = -328 \qquad \ce{Cl(g) + e- -> Cl^-(g)}\,,\ \Delta_{eg}H = -349$$
The reason is electron-electron repulsion in a compact orbital. Fluorine is so small that its incoming electron is forced into the tight $n = 2$ (2p) level, where it experiences significant repulsion from the electrons already crowded into that small region of space. In chlorine the added electron enters the larger $n = 3$ (3p) level, occupying a much bigger volume where electron-electron repulsion is far weaker. The reduced repulsion in chlorine more than compensates for its larger size, so chlorine releases more energy.
Chlorine, not fluorine, has the most negative electron gain enthalpy.
The standard answer key reasoning (NEET 2016) is: "Electron gain enthalpy of F is less than Cl because in F the small size of the 2p orbital results in high electron density, so inter-electronic repulsion is high." The correct increasing order of magnitude across the halogens is therefore $\ce{I < Br < F < Cl}$ — note F slots between Br and Cl, not at the top.
Same effect repeats one group left: O is less negative than S, and N is less negative than P, all because of crowding in the small $n = 2$ shell.
Bar heights are the magnitude $|\Delta_{eg}H|$ for the halogens (kJ mol⁻¹). Chlorine is the tallest bar — fluorine sits below it despite being smaller, the visual signature of the anomaly.
The same small-2p-orbital crowding that suppresses fluorine's electron gain enthalpy also makes the first ionisation enthalpies of period-2 elements unusually high. See Ionisation Enthalpy for the mirror-image trend.
Why Noble Gases Are Positive
The noble gases stand apart with positive electron gain enthalpies — He +48, Ne +116, Ar +96, Kr +96, Xe +77, Rn +68 (all $\text{kJ mol}^{-1}$). A positive value means energy must be supplied for the atom to accept an electron at all; the process is endothermic and the product anion is unstable.
The cause is the filled valence shell. A noble gas already has a complete $ns^2np^6$ octet (or $1s^2$ for He), so any extra electron cannot fit into that shell and is forced into the next higher principal quantum level. That places the electron far from the nucleus and well shielded, producing a very unstable configuration — exactly why the value is positive rather than merely small.
Notice too that the noble-gas values themselves drift toward less positive on descending the group (He +48 is actually lower than Ne +116, but from Ne downward the trend Ne > Ar ≈ Kr > Xe > Rn holds): the larger the atom, the less unfavourable it becomes to park an electron in the next shell. The qualitative message for an exam is simply that the noble-gas column is the one place in the table where $\Delta_{eg}H$ is positive, and that this positivity is a direct consequence of an already-stable octet.
Second Electron Gain Enthalpy
The first electron added to oxygen releases energy, but a second electron is a different matter. Forming $\ce{O^2-}$ requires pushing a negative electron onto an already-negative $\ce{O^-}$ ion:
$$\ce{O(g) + e- -> O^-(g)}\,,\ \Delta_{eg}H_1 < 0 \qquad \ce{O^-(g) + e- -> O^2-(g)}\,,\ \Delta_{eg}H_2 > 0$$
The electrostatic repulsion between the incoming electron and the $\ce{O^-}$ ion must be overcome, so the second electron gain enthalpy is positive (endothermic). Forming the free $\ce{O^2-}$ ion from a gaseous oxygen atom is therefore an overall energy-absorbing process; in real compounds the $\ce{O^2-}$ ion is stabilised only by the large lattice energy of the ionic solid, not by electron gain enthalpy itself.
Electron Gain Enthalpy vs Electron Affinity
Older texts use the term electron affinity ($A_e$) for this same idea, and the two carry opposite signs — a classic point of confusion. NCERT footnotes the relationship explicitly: electron affinity is defined as the negative of the enthalpy change, with a positive $A_e$ meaning energy is released, contrary to the thermodynamic convention. The link, at temperature $T$, is:
$$\Delta_{eg}H = -A_e - \tfrac{5}{2}RT$$
| Feature | Electron gain enthalpy (ΔegH) | Electron affinity (Ae) |
|---|---|---|
| Convention | Standard thermodynamic: energy released → negative | Energy released → positive (contrary to thermodynamics) |
| Defined at | Temperature $T$ (includes a $\tfrac{5}{2}RT$ term) | Absolute zero |
| Sign for a halogen | Negative (e.g. Cl $-349$) | Positive (e.g. Cl $+349$) |
| Relationship | $\Delta_{eg}H = -A_e - \tfrac{5}{2}RT$ | |
For NEET, the safe habit is to work entirely in $\Delta_{eg}H$ with the thermodynamic sign convention, and to read any "electron affinity" phrasing as the magnitude with the sign flipped. Confusing the two is a deliberate trap in comparison questions.
Electron Gain Enthalpy in One Screen
- Definition: enthalpy change for $\ce{X(g) + e- -> X^-(g)}$, denoted $\Delta_{eg}H$, defined for the gaseous atom.
- Sign convention: negative = energy released = exothermic = stronger tendency to gain an electron. Most negative ≠ "biggest tendency" being positive.
- Period trend: more negative left→right (rising $Z_{eff}$, smaller atom). Group trend: less negative top→bottom (larger atom).
- Anomaly: Cl ($-349$) is more negative than F ($-328$) — the small 2p orbital of F gives high electron-electron repulsion. Most negative element overall = Cl. Order: $\ce{I < Br < F < Cl}$.
- Noble gases: positive $\Delta_{eg}H$ — filled shell forces the electron into the next quantum level.
- Second ΔegH of O is positive; electron affinity $A_e$ has the opposite sign, with $\Delta_{eg}H = -A_e - \tfrac{5}{2}RT$.